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The second electron affinity values for both oxygen and sulfur are unfavorable (positive). Explain.

Short Answer

Expert verified
The second electron affinity values for both oxygen and sulfur are unfavorable (positive) because adding a second electron to their already negatively charged ions (O鈦 and S鈦) increases the system's energy due to electron-electron repulsion. The incoming electron experiences strong repulsion from the negatively charged ion and is forced to occupy a higher energy orbital, making the process of gaining a second electron unfavorable.

Step by step solution

01

Understand electron affinity

Electron affinity is the energy that is released (exothermic) or absorbed (endothermic) when an electron is added to an atom to form a negative ion. It is a measure of how much an atom wants to gain an electron. The sign of electron affinity can be positive or negative, indicating a favorable (exothermic) or unfavorable (endothermic) process, respectively.
02

Examine the electron configuration of oxygen and sulfur

Oxygen has an electron configuration of 1s虏 2s虏 2p^4, and sulfur has an electron configuration of 1s虏 2s虏 2p^6 3s虏 3p^4. When both elements gain one electron, they form a negative ion with stable configurations (half-filled or fully filled p orbitals): Oxygen: 1s虏 2s虏 2p^5 (O鈦) and Sulfur: 1s虏 2s虏 2p^6 3s虏 3p^5 (S鈦).
03

Analyze the first electron affinity

The first electron affinity for oxygen and sulfur is negative (favorable). The energy is released when they gain one electron. This is because the incoming electron will occupy a stable position (half-filled or fully filled p orbitals), leading to a lower potential energy and increased stability.
04

Explain why the second electron affinity is positive (unfavorable)

The second electron affinity for oxygen and sulfur is positive (unfavorable) because adding an additional electron requires energy. This is because the incoming electron will experience strong repulsion from the negatively charged ion (O鈦 or S鈦) that has already gained an electron. The additional electron will be forced to occupy a higher energy orbital, causing the system's energy to increase. Consequently, the process of gaining a second electron is unfavorable, and the second electron affinity is positive. In summary, the second electron affinity values for both oxygen and sulfur are unfavorable (positive) because adding a second electron to their already negatively charged ions results in an increase in energy due to electron-electron repulsion, which makes the process unfavorable.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Affinity Explained
Electron affinity is a term that describes the change in energy when an atom gains an electron to form an anion. In simple terms, it's like a measure of how much an atom 'wants' an extra electron. This process can either release energy, which we call exothermic, or absorb energy, known as endothermic.

For many elements, the first electron affinity is negative because adding the first electron usually leads to a more stable electronic arrangement, thus releasing energy. However, the second electron affinity is often positive, particularly for nonmetals like oxygen and sulfur. The positivity indicates that energy must be put in to add another electron against the electrostatic repulsion of the negatively charged ion formed after the first electron addition.

Understanding electron affinity is crucial for predicting how elements will interact, especially when they form ionic compounds. For instance, elements with high negative electron affinities are more likely to accept electrons and form anions during chemical reactions.
Electron Configuration and Stability
Understanding electron configuration is key to making sense of many chemical phenomena. The electron configuration tells us how the electrons are distributed among an atom's orbitals, which determines the atom's chemical behavior.

An important aspect of electron configurations is achieving a full or half-full set of p orbitals, which is energetically favorable and lends stability to the atom. The electron configuration of oxygen is 1s虏 2s虏 2p鈦, and for sulfur it's 1s虏 2s虏 2p鈦 3s虏 3p鈦. Once they gain one electron, they achieve a half-filled p orbital (for oxygen) or a filled p orbital (for sulfur), which is quite stable.

However, adding a second electron to these ions disrupts this stability and forces the electron into a more repulsive environment, further from the nucleus and among other negatively charged electrons. This need for additional energy to push the electron into a less stable position explains why the second electron affinities of oxygen and sulfur are unfavorable.
Exothermic and Endothermic Processes
These terms are essential for understanding energy changes in chemical reactions. An exothermic process is one that releases energy, often in the form of heat, making the surroundings warmer. Combustion is a classic example of an exothermic reaction.

On the flip side, an endothermic process absorbs energy from its surroundings, leading to a drop in temperature. Melting ice is an endothermic process, as it requires heat from the surroundings to change state from solid to liquid.

In the context of electron affinity, a negative value indicates an exothermic process, where energy is released when an atom gains an electron. The first electron affinities of oxygen and sulfur fall into this category. However, the second electron affinity involves an endothermic process; energy must be added to overcome electrostatic repulsion and add another electron to an already negative ion.

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Most popular questions from this chapter

Write Lewis structures that obey the octet rule for each of the following molecules and ions. (In each case the first atom listed is the central atom.) a. \(\mathrm{POCl}_{3}, \mathrm{SO}_{4}^{2-}, \mathrm{XeO}_{4}, \mathrm{PO}_{4}^{3-}, \mathrm{ClO}_{4}^{-}\) b. \(\mathrm{NF}_{3}, \mathrm{SO}_{3}^{2-}, \mathrm{PO}_{3}^{3-}, \mathrm{ClO}_{3}^{-}\) c. \(\mathrm{ClO}_{2}^{-}, \mathrm{SCl}_{2}, \mathrm{PCl}_{2}^{-}\) d. Considering your answers to parts a, b, and c, what conclusions can you draw concerning the structures of species containing the same number of atoms and the same number of valence electrons?

Write Lewis structures that obey the octet rule (duet rule for H) for each of the following molecules. a. \(\mathrm{H}_{2} \mathrm{CO}\) b. \(\mathrm{CO}_{2}\) c. HCN Carbon is the central atom in all of these molecules.

Write Lewis structures that obey the octet rule for the following species. Assign the formal charge for each central atom. a. \(\mathrm{POCl}_{3}\) b. \(\mathrm{SO}_{4}^{2-}\) c. \(\mathrm{ClO}_{4}\) d. \(\mathrm{PO}_{4}^{3-}\) e. \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) f. \(\quad X \in O_{4}\) g. \(\mathrm{ClO}_{3}\) h. \(\mathrm{NO}_{4}^{3-}\)

Which compound in each of the following pairs of ionic substances has the most negative lattice energy? Justify your answers. a. LiF, CsF b. NaBr, NaI c. \(\mathrm{BaCl}_{2}, \mathrm{BaO}\) d. \(\mathrm{Na}_{2} \mathrm{SO}_{4}, \mathrm{CaSO}_{4}\) e. \(\mathrm{KF}, \mathrm{K}_{2} \mathrm{O}\) f. \(\mathrm{Li}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{S}\)

Given the following information: Energy of sublimation of \(\mathrm{Li}(s)=166 \mathrm{kJ} / \mathrm{mol}\) Bond energy of \(\mathrm{HCl}=427 \mathrm{kJ} / \mathrm{mol}\) Ionization energy of \(\mathrm{Li}(g)=520 . \mathrm{kJ} / \mathrm{mol}\) Electron affinity of \(\mathrm{Cl}(g)=-349 \mathrm{kJ} / \mathrm{mol}\) Lattice energy of \(\mathrm{LiCl}(s)=-829 \mathrm{kJ} / \mathrm{mol}\) Bond energy of \(\mathrm{H}_{2}=432 \mathrm{kJ} / \mathrm{mol}\) Calculate the net change in energy for the following reaction: $$ 2 \mathrm{Li}(s)+2 \mathrm{HCl}(g) \longrightarrow 2 \mathrm{LiCl}(s)+\mathrm{H}_{2}(g) $$

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