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Chapter 3: Problem 112

Write the formula for each of the following compounds: a. diboron trioxide b. arsenic pentafluoride c. dinitrogen monoxide d. sulfur hexachloride

Short Answer

Expert verified
The chemical formulas for the given compounds are: a. Diboron trioxide: \(B_2O_3\) b. Arsenic pentafluoride: \(AsF_5\) c. Dinitrogen monoxide: \(N_2O\) d. Sulfur hexachloride: \(SF_6\)

Step by step solution

01

a. Diboron trioxide

1. Identify the elements: In the compound "diboron trioxide," we have two elements - boron (B) and oxygen (O). 2. Identify the prefixes: In our compound name, we have the prefix "di" for boron, which means 2 atoms of boron, and "tri" for oxygen, which means 3 atoms of oxygen. 3. Write the formula: Combine the elements with their respective prefixes. So, diboron trioxide has a chemical formula of \(B_2O_3\).
02

b. Arsenic pentafluoride

1. Identify the elements: In the compound "arsenic pentafluoride," we have two elements - arsenic (As) and fluorine (F). 2. Identify the prefixes: For arsenic, no prefix is provided, which means 1 atom of arsenic is present. For fluorine, we have the prefix "penta," which means 5 atoms of fluorine. 3. Write the formula: Combine the elements with their respective prefixes. So, arsenic pentafluoride has a chemical formula of \(AsF_5\).
03

c. Dinitrogen monoxide

1. Identify the elements: In the compound "dinitrogen monoxide," we have two elements - nitrogen (N) and oxygen (O). 2. Identify the prefixes: For nitrogen, we have the prefix "di," which means 2 atoms of nitrogen, and for oxygen, we have the prefix "mono," which means 1 atom of oxygen. 3. Write the formula: Combine the elements with their respective prefixes. So, dinitrogen monoxide has a chemical formula of \(N_2O\).
04

d. Sulfur hexachloride

1. Identify the elements: In the compound "sulfur hexachloride," we have two elements - sulfur (S) and chlorine (Cl). 2. Identify the prefixes: For sulfur, no prefix is provided, which means 1 atom of sulfur is present. For chlorine, we have the prefix "hexa," which means 6 atoms of chlorine. 3. Write the formula: Combine the elements with their respective prefixes. So, sulfur hexachloride has a chemical formula of \(SF_6\).

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Most popular questions from this chapter

Write electron configurations for a. the cations \(\mathrm{Sr}^{2+}, \mathrm{Cs}^{+}, \mathrm{In}^{+},\) and \(\mathrm{Pb}^{2+}\) b. the anions \(P^{3-}, S^{2-},\) and \(B r^{-}\)

Look up the energies for the bonds in CO and \(\mathrm{N}_{2}\). Although the bond in CO is stronger, CO is considerably more reactive than \(\mathrm{N}_{2}\). Give a possible explanation.

Use the following data to estimate \(\Delta E\) for the reaction: $$\mathrm{Ba}(s)+\mathrm{Br}_{2}(g) \longrightarrow \mathrm{BaBr}_{2}(s) \quad \Delta E=?$$ Lattice energy First ionization energy of Ba Second ionization energy of Ba Electron affinity of Br Bond energy of \(\mathrm{Br}_{2}\) Enthalpy of sublimation of Ba \(-1985 \mathrm{kJ} / \mathrm{mol}\) \(503 \mathrm{kJ} / \mathrm{mol}\) \(965 \mathrm{kJ} / \mathrm{mol}\) -325 kJ/mol \(193 \mathrm{kJ} / \mathrm{mol}\) \(178 \mathrm{kJ} / \mathrm{mol}\)

Write Lewis structures that obey the octet rule for each of the following molecules. a. \(\mathrm{CCl}_{4}\) b. \(\mathrm{NCl}_{3}\) c. \(\operatorname{Sec} 1_{2}\) d. ICl In each case, the atom listed first is the central atom.

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