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Write equations corresponding to the following: a. the fourth ionization energy of Se b. the electron affinity of \(S^{-}\) c. the electron affinity of \(\mathrm{Fe}^{3+}\) d. the ionization energy of \(\mathrm{Mg}\)

Short Answer

Expert verified
a. \[ \mathrm{Se}^{3+}(g) \rightarrow \mathrm{Se}^{4+}(g) + e^{-} \] b. \[ S^{-}(g) + e^{-} \rightarrow S^{2-}(g) \] c. \[ \mathrm{Fe}^{3+}(g) + e^{-} \rightarrow \mathrm{Fe}^{2+}(g) \] d. \[ \mathrm{Mg}(g) \rightarrow \mathrm{Mg}^{+}(g) + e^{-} \]

Step by step solution

01

Identify the chemical for ionization

Selenium (Se) is a chemical element with atomic number 34.
02

Determine the new charge after ionization

We are asked for the fourth ionization energy, indicating we need to remove the fourth electron, taking a neutral Se atom to an ion with a +4 charge.
03

Write the equation

The fourth ionization energy equation for Se is: \[ \mathrm{Se}^{3+}(g) \rightarrow \mathrm{Se}^{4+}(g) + e^{-} \] b. the electron affinity of \(S^{-}\)
04

Identify the chemical for electron addition

The chemical given is the sulfide ion, \(S^{-}\).
05

Determine the new charge after electron addition

We will add one electron to \(S^{-}\), resulting in \(S^{2-}\).
06

Write the equation

The electron affinity equation for \(S^{-}\) is: \[ S^{-}(g) + e^{-} \rightarrow S^{2-}(g) \] c. the electron affinity of \(\mathrm{Fe}^{3+}\)
07

Identify the chemical for electron addition

The chemical given is the iron(III) ion, \(\mathrm{Fe}^{3+}\).
08

Determine the new charge after electron addition

We will add one electron to \(\mathrm{Fe}^{3+}\), resulting in \(\mathrm{Fe}^{2+}\).
09

Write the equation

The electron affinity equation for \(\mathrm{Fe}^{3+}\) is: \[ \mathrm{Fe}^{3+}(g) + e^{-} \rightarrow \mathrm{Fe}^{2+}(g) \] d. the ionization energy of \(\mathrm{Mg}\)
10

Identify the chemical for ionization

Magnesium (Mg) is a chemical element with atomic number 12.
11

Determine the new charge after ionization

Removing one electron from a neutral Mg atom results in a \(\mathrm{Mg}^{+}\) ion.
12

Write the equation

The ionization energy equation for Mg is: \[ \mathrm{Mg}(g) \rightarrow \mathrm{Mg}^{+}(g) + e^{-} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Ionization
Chemical ionization is a process where ions are formed from a substance through the addition or removal of charged particles, particularly electrons. This process is essential in various fields, including chemistry and physics, as it relates to the formation of ions which are pivotal in electrical conductivity and chemical reactions.

For example, the fourth ionization energy of selenium (Se) involves removing a fourth electron from a selenium ion that already has a +3 charge. This is represented by the equation \[ \mathrm{Se}^{3+}(g) \rightarrow \mathrm{Se}^{4+}(g) + e^{-} \].
In this equation, a positively charged selenium ion (the reactant) loses an electron to form a more positively charged ion, illustrating the energy required to remove an electron from a positively charged ion.
Electron Affinity
Electron affinity refers to the amount of energy released when an electron is added to a neutral atom or molecule in the gaseous state to form a negative ion. It is an important concept in understanding how elements form compounds and participate in chemical bonds.

The electron affinity of the sulfide ion (\(S^{-}\)) involves adding an electron to form a disulfide ion (\(S^{2-}\)), as represented by the equation \[ S^{-}(g) + e^{-} \rightarrow S^{2-}(g) \]. Similarly, an iron(III) ion (\(\mathrm{Fe}^{3+}\)) can gain an electron to form an iron(II) ion (\(\mathrm{Fe}^{2+}\)), as shown by \[ \mathrm{Fe}^{3+}(g) + e^{-} \rightarrow \mathrm{Fe}^{2+}(g) \].
These equations help to illustrate the process of gaining an electron and the energy implications associated with it.
Ionization Energy
Ionization energy is the energy required to remove an electron from an atom or ion in its gaseous state. It is a critical concept in chemistry that helps us understand the reactivity of elements and their tendency to form chemical bonds.

The ionization energy of magnesium (\(\mathrm{Mg}\)) is demonstrated by the equation \[ \mathrm{Mg}(g) \rightarrow \mathrm{Mg}^{+}(g) + e^{-} \], which shows the energy input necessary to remove an electron from a neutral magnesium atom, resulting in a positively charged magnesium ion. Each successive ionization energy is higher than the last, which means it takes more energy to remove each subsequent electron.
This concept explains why certain elements are more likely to lose electrons and form cations, playing a crucial role in the periodic trends observed across the elements.

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Most popular questions from this chapter

In defining the sizes of orbitals, why must we use an arbitrary value, such as \(90 \%\) of the probability of finding an electron in that region?

Given the valence electron orbital level diagram and the description, identify the element or ion. a. A ground state atom b. An atom in an excited state (assume two electrons occupy the \(1 s\) orbital) c. A ground state ion with a charge of -1

An electron is excited from the \(n=1\) ground state to the \(n=\) 3 state in a hydrogen atom. Which of the following statements is/are true? Correct the false statements to make them true. a. It takes more energy to ionize (completely remove) the electron from \(n=3\) than from the ground state. b. The electron is farther from the nucleus on average in the \(n=3\) state than in the \(n=1\) state. c. The wavelength of light emitted if the electron drops from \(n=3\) to \(n=2\) will be shorter than the wavelength of light emitted if the electron falls from \(n=3\) to \(n=1\) d. The wavelcngth of light cmittcd when the clectron returns to the ground state from \(n=3\) will be the same as the wavelength of light absorbed to go from \(n=1\) to \(n=3\) e. For \(n=3,\) the electron is in the first excited state.

For each of the following pairs of elements $$ (\mathrm{C} \text { and } \mathrm{N}) \quad(\mathrm{Ar} \text { and } \mathrm{Br}) $$ pick the atom with a. more favorable (more negative) electron affinity. b. higher ionization energy. c. larger size.

One bit of evidence that the quantum mechanical model is "correct" lies in the magnetic properties of matter. Atoms with unpaired electrons are attracted by magnetic fields and thus are said to exhibit paramagnetism. The degree to which this effect is observed is directly related to the number of unpaired electrons present in the atom. Consider the ground-state electron configurations for Li, N, Ni, Te, Ba, and Hg. Which of these atoms would be expected to be paramagnetic, and how many unpaired electrons are present in each paramagnetic atom?

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