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Write balanced equations for each of the processes described below. a. Chromium- \(51,\) which targets the spleen and is used as a tracer in studies of red blood cells, decays by electron capture. b. Iodine-131, used to treat hyperactive thyroid glands, decays by producing a \(\beta\) particle. c. Phosphorus- \(32,\) which accumulates in the liver, decays by \(\beta\) -particle production.

Short Answer

Expert verified
a. \[^{51}_{24}Cr + e^- \rightarrow ^{51}_{23}V\] b. \[^{131}_{53}I \rightarrow ^{131}_{54}Xe + \beta^-\] c. \[^{32}_{15}P \rightarrow ^{32}_{16}S + \beta^-\]

Step by step solution

01

a. Chromium-51

Chromium-51 undergoes electron capture. The atomic number (Z) decreases by 1 and the mass number (A) remains the same. The initial nucleus is \(^{51}_{24}Cr\), and after electron capture, the resulting nuclide has an atomic number of 23. The balanced equation is: \(^{51}_{24}Cr + e^- \rightarrow ^{51}_{23}V\)
02

b. Iodine-131

Iodine-131 decays by β decay, which means it emits a β particle (an electron). The atomic number (Z) increases by 1 and the mass number (A) remains the same. The initial nucleus is \(^{131}_{53}I\), and after β decay, the resulting nuclide has an atomic number of 54. The balanced equation is: \(^{131}_{53}I \rightarrow ^{131}_{54}Xe + \beta^-\)
03

c. Phosphorus-32

Phosphorus-32 decays by β particle production, which is the same as β decay. The atomic number (Z) increases by 1 and the mass number (A) remains the same. The initial nucleus is \(^{32}_{15}P\), and after β decay, the resulting nuclide has an atomic number of 16. The balanced equation is: \(^{32}_{15}P \rightarrow ^{32}_{16}S + \beta^-\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Capture
Electron capture is a type of nuclear decay in which an atomic nucleus absorbs an inner-shell electron from its own electron cloud. This process results in the transformation of a proton into a neutron and simultaneously emits a neutrino, which is a nearly massless particle.

During electron capture, the mass number (A) of the isotope remains the same because the nucleus is simply reconfiguring its particles without adding or losing nucleons. However, the atomic number (Z) decreases by one because one proton (positively charged particle) is converted into one neutron (a neutral particle).

The notation for electron capture involves adding an electron (\(e^-\)) on the reactant side of the nuclear equation. For instance, when Chromium-51 (\( ^{51}_{24}Cr \)) undergoes electron capture, the equation is written as \( ^{51}_{24}Cr + e^- \rightarrow ^{51}_{23}V \), where Vanadium-51 (\( ^{51}_{23}V \) ) is the resulting nuclide.
Beta Decay
Beta decay represents a form of radioactive decay where a beta particle, which is essentially an electron or a positron, is emitted from an atomic nucleus. For beta-minus decay (\( \beta^- \) decay), a neutron is converted into a proton with the emission of an electron and an antineutrino. This causes the atomic number (Z) to increase by one while the mass number (A) remains constant.

In beta-plus decay (\( \beta^+ \) decay), the opposite occurs where a proton is transformed into a neutron with the emission of a positron and a neutrino, causing the atomic number to decrease by one. The general formula for beta-minus decay is \( ^A_ZX \rightarrow ^A_{Z+1}Y + \beta^- \).

As an example, Iodine-131 (\( ^{131}_{53}I \) ) decaying into Xenon-131 (\( ^{131}_{54}Xe \) ) with the emission of a beta particle can be represented as \( ^{131}_{53}I \rightarrow ^{131}_{54}Xe + \beta^- \). Similarly, Phosphorus-32 (\( ^{32}_{15}P \) ) undergoes beta decay to form Sulfur-32 (\( ^{32}_{16}S \) ), which is expressed as \( ^{32}_{15}P \rightarrow ^{32}_{16}S + \beta^- \).
Radioisotope Applications
Radioisotopes have wide-ranging applications in the field of medicine, industry, and scientific research due to their unique radioactive properties. In medical applications, radioactive tracers can help diagnose and treat various health conditions. For example, Chromium-51, with its ability to target the spleen, is utilized in red blood cell studies to understand and diagnose blood disorders.

Another common use is in the treatment of thyroid conditions, where Iodine-131 is administered to patients to manage hyperthyroidism. The beta particles emitted by the decaying Iodine-131 can destroy overactive thyroid cells, thus treating the condition.

In the research domain, radioisotopes such as Phosphorus-32 are used to trace the assimilation of nutrients in organisms. This isotope accumulates in the liver, allowing scientists to monitor liver function and health. These examples demonstrate the critical role radioisotopes play in enhancing our ability to detect and remedy medical challenges, as well as to facilitate advancements in biological research.

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Most popular questions from this chapter

Iodine-131 has a half-life of 8.0 days. How many days will it take for 174 g of \(^{131}\) I to decay to 83 g of \(^{131}\) I?

Given the following information: Mass of proton \(=1.00728 \mathrm{u}\) Mass of neutron \(=1.00866 \mathrm{u}\) Mass of electron \(=5.486 \times 10^{-4} \mathrm{u}\) Speed of light \(=2.9979 \times 10^{8} \mathrm{m} / \mathrm{s}\) Calculate the nuclear binding energy of \(\frac{24}{12} \mathrm{Mg},\) which has an atomic mass of 23.9850 u.

Estimate the temperature needed to achieve the fusion of deuterium to make an \(\alpha\) particle. The energy required can be estimated from Coulomb's law [use the form \(E=9.0 \times 10^{9}\) \(\left(Q_{1} Q_{2} / r\right),\) using \(Q=1.6 \times 10^{-19} \mathrm{C}\) for a proton, and \(r=2 \times\) \(10^{-15} \mathrm{m}\) for the helium nucleus; the unit for the proportionality constant in Coloumb's law is \(\left.\mathbf{J} \cdot \mathbf{m} / \mathbf{C}^{2}\right]\).

Which of the following statement(s) is(are) true? a. A radioactive nuclide that decays from \(1.00 \times 10^{10}\) atoms to \(2.5 \times 10^{9}\) atoms in 10 minutes has a half-life of 5.0 minutes.b. Nuclides with large \(Z\) values are observed to be \(\alpha\) -particle producers. c. As \(Z\) increases, nuclides need a greater proton-to-neutron ratio for stability. d. Those "light" nuclides that have twice as many neutrons as protons are expected to be stable.

The most stable nucleus in terms of binding energy per nucleon is \(^{56} \mathrm{Fe}\). If the atomic mass of \(^{56} \mathrm{Fe}\) is \(55.9349 \mathrm{u},\) calculate the binding energy per nucleon for \(^{56} \mathrm{Fe}\).

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