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A solution contains 0.018 molel each of \(\mathrm{I}^{-}, \mathrm{Br}^{-},\) and \(\mathrm{Cl}^{-}\). When the solution is mixed with \(200 . \mathrm{mL}\) of \(0.24\) \(M\) \(\mathrm{AgNO}_{3}\), what mass of \(\mathrm{AgCl}(s)\) precipitates out, and what is \(\left[\mathrm{Ag}^{+}\right] ?\) Assume no volume change. $$\begin{aligned} \operatorname{AgI}: K_{\mathrm{sp}} &=1.5 \times 10^{-16} \\ \operatorname{AgBr}: K_{\mathrm{sp}} &=5.0 \times 10^{-13} \\ \mathrm{AgCl}: K_{\mathrm{sp}} &=1.6 \times 10^{-10} \end{aligned}$$

Short Answer

Expert verified
The mass of AgCl(s) that precipitates out is 2.5812 g, and the final concentration of Ag鈦 is 0 M.

Step by step solution

01

Determine moles of AgNO鈧

200 mL of 0.24 M AgNO鈧 solution contains 0.24 mol/L 脳 0.2 L = 0.048 moles of AgNO鈧.
02

Determine which compound precipitates first

We will determine the solubility quotient Q for all three compounds and compare it with their Ksp. Q = ([Ag鈦篯[X鈦籡) / Ksp, where X is either I, Br, or Cl. Using initial moles of 0.018 mol of X鈦 in 0.2 L Initial [X鈦籡 = 0.018 mol / 0.2 L = 0.09 M Initial [Ag鈦篯 = 0.24 M AgI: Q = (0.24)(0.09) / 1.5 脳 10鈦宦光伓 = 1.44 脳 10鹿鈦 AgBr: Q = (0.24)(0.09) / 5.0 脳 10鈦宦孤 = 4.32 脳 10鹿鹿 AgCl: Q = (0.24)(0.09) / 1.6 脳 10鈦宦光伆 = 1.44 脳 10鈦 Since AgI has the highest Q (compared to its Ksp), it will precipitate first.
03

Determine remaining moles of Ag鈦 and X鈦 ions

Once AgI precipitates, we are left with 0.048 - 0.018 = 0.030 moles of Ag鈦. Since AgBr has the next highest Q, it will precipitate next. Once AgBr precipitates, we are left with 0.030 - 0.018 = 0.012 moles of Ag鈦.
04

Determine moles and mass of AgCl precipitated

Now that there are 0.012 moles of Ag鈦 left, all remaining Cl鈦 ions (0.018 moles) will react with Ag鈦 to form AgCl. Moles of AgCl precipitated = 0.018 moles Mass of AgCl precipitated = (moles of AgCl) 脳 (molar mass of AgCl) = 0.018 moles 脳 (107.9 + 35.5) g/mol = 0.018 脳 143.4 g/mol = 2.5812 g
05

Calculate the final concentration of Ag鈦

Moles of Ag鈦 remaining after AgCl precipitates = 0.012 - 0.018 = -0.006 moles Since this value is negative, it means all Ag鈦 ions have reacted with the Cl鈦 ions. Final [Ag鈦篯 = 0 M (since no more Ag鈦 is left in the solution) The mass of AgCl(s) that precipitates out is 2.5812 g, and the final concentration of Ag鈦 is 0 M.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility Product Constant (Ksp)
Understanding the solubility product constant, or Ksp, is crucial for predicting whether a precipitate will form in a solution. The Ksp is an equilibrium constant that applies to the dissolution of sparingly soluble salts.

Let's simplify this concept: Imagine a dance floor where certain dance partners (ions) prefer not to dance together (solid state) and only mix with the crowd (solution) to a limited extent. The Ksp tells us how much of this salt will 'dance' in solution before the floor becomes too crowded, inducing some pairs to leave the floor and form a solid precipitate.

The Ksp value is unique for each salt at a given temperature and is determined by the concentrations of the ions in their saturated solution. For instance, in the exercise:
  • AgCl: Ksp = \(1.6 \times 10^{-10}\)
This Ksp value suggests that only a minute amount of AgCl will dissolve before it starts to precipitate. The smaller the Ksp value, the less soluble the compound is. Overall, Ksp helps us understand and predict the extent of a substance's solubility, playing a vital role in chemistry, from industry to the environment.
Molar Concentration
Molar concentration, often represented by square brackets [], is a measure of the number of moles of a solute that is present in a unit volume of solution. It is typically expressed in moles per liter (mol/L).

As an analogy, think of molar concentration as the number of people in a room per square meter. The more people there are, the more crowded the space becomes. Similarly, the higher the molar concentration of a solute in a solution, the more particles are available to interact and possibly form a precipitate.

In our precipitation reaction scenario, the initial molar concentration of Ag鈦 ions in the AgNO鈧 solution was 0.24 M. This concentration helps determine which silver halide precipitates first, as the ions from the salt meet up in the solution, potentially hitting their solubility limit and starting to precipitate. Proper understanding of molar concentration is also the key to calculating the final concentration of ions in a solution after a reaction takes place.
Solubility Quotient (Q)
The solubility quotient, or Q, is the calculated 'product' of the molar concentrations of the ions that compose a salt at any given moment, not necessarily at equilibrium. This value is extremely useful when you want to determine if a precipitate will form under certain conditions.

Imagine you are filling a bag with groceries until it reaches its limit. Q represents the amount of groceries in the bag at any point during filling, while Ksp is the maximum capacity of the bag before it starts to tear. Once your calculated Q exceeds the known Ksp for the compound, the bag 'tears' and the compound begins to precipitate.

Returning to our exercise, the calculated Q values for AgI, AgBr, and AgCl were:
  • AgI: Q = \(1.44 \times 10^{15}\)
  • AgBr: Q = \(4.32 \times 10^{11}\)
  • AgCl: Q = \(1.44 \times 10^9\)
These calculations revealed that AgI had the highest Q compared to its Ksp and thus precipitated first. In general, by comparing Q to Ksp, we can predict whether a precipitate will form immediately (if Q>Ksp) or remain dissolved (if Q

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