Chapter 13: Problem 127
Calculate the \(\mathrm{pH}\) of a \(0.050-M\) Al(NO_3)a solution. The \(K_{\mathrm{a}}\) value for \(\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}\) is \(1.4 \times 10^{-5}\).
Short Answer
Expert verified
The pH of the \(0.050\,\text{M}\) Al(NO鈧)鈧 solution is approximately 3.23.
Step by step solution
01
Write the reaction equation
The reaction equation for the dissolution of Al(H鈧侽)鈧喡斥伜 can be written as:
Al(H鈧侽)鈧喡斥伜 + H鈧侽 鈫 Al(H鈧侽)鈧(OH)虏鈦 + H鈧僌鈦
Now, let's determine the concentration of H鈧僌鈦 ions.
02
Determine the initial concentrations
The initial concentration of Al(NO鈧)鈧 is \(0.050\,\text{M}\), which means that the initial concentration of Al(H鈧侽)鈧喡斥伜 is \(0.050\,\text{M}\). No H鈧僌鈦 ions are initially present, so we can assume that their initial concentration is \(0\,\text{M}\).
03
Calculate the change in concentrations
As the Al(H鈧侽)鈧喡斥伜 in the solution dissociates, it leads to an increase in the concentration of H鈧僌鈦 ions. Since the stoichiometry of the reaction is 1:1:1, we can represent the change in concentrations using the variable x:
\[ \text{Al(H鈧侽)鈧喡斥伜} \rightarrow -x \newline \text{H鈧僌鈦簘 \rightarrow +x \newline \text{Al(H鈧侽)鈧(OH)虏鈦簘 \rightarrow +x
\]
04
Write the equation for K鈧
The K鈧 expression can be written as:
鈬 K鈧 = \[\frac{[\text{Al(H鈧侽)鈧(OH)虏鈦簘][\text{H鈧僌鈦簘]} {[\text{Al(H鈧侽)鈧喡斥伜}]} \]
However, since the concentration of Al(H鈧侽)鈧(OH)虏鈦 and H鈧僌鈦 are equal, we can simplify this expression:
鈬 K鈧 = \[\frac{x^2}{0.050 - x}\]
Now, let's plug in the value of K鈧 and solve for x.
05
Solve for the H鈧僌鈦 concentration
Given the K鈧 value of \(1.4 \times 10^{-5}\), we can set up an equation and solve for x:
\(1.4 \times 10^{-5} = \frac{x^2}{0.050 - x}\)
To solve for x, we can assume that the value of x is much smaller than 0.050, which would simplify the equation to:
\(1.4 \times 10^{-5} = \frac{x^2}{0.050}\)
鈬 \(x = \sqrt{(1.4 \times 10^{-5})(0.050)}\)
The concentration of H鈧僌鈦 ions (x) is approximately equal to \( 5.92 \times 10^{-4}\,\text{M}\).
06
Calculate the pH
Now, we can calculate the pH using the formula: pH = -log[H鈧僌鈦篯:
pH = -log(\(5.92 \times 10^{-4}\))
pH 鈮 3.23
Thus, the pH of the \(0.050\,\text{M}\) Al(NO鈧)鈧 solution is approximately 3.23.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
K鈧 expression
The acid dissociation constant, represented by K鈧, is a crucial concept in chemistry that quantifies the strength of an acid in solution. The K鈧 expression is derived from the chemical equilibrium of a weak acid鈥檚 dissociation in water. For example, in an aqueous solution, a weak acid such as Al(H鈧侽)鈧喡斥伜 ionizes to form Al(H鈧侽)鈧(OH)虏鈦 and H鈧僌鈦 ions.
The mathematical K鈧 expression for this equilibrium is: \[ K鈧 = \frac{[\text{Al(H鈧侽)鈧(OH)虏鈦簘][\text{H鈧僌鈦簘]}{[\text{Al(H鈧侽)鈧喡斥伜}]} \]
This expression allows us to relate the concentrations of the products and reactants at equilibrium. Importantly, it implies the principle that at equilibrium, the rate of the forward reaction equals the rate of the reverse reaction.
The mathematical K鈧 expression for this equilibrium is: \[ K鈧 = \frac{[\text{Al(H鈧侽)鈧(OH)虏鈦簘][\text{H鈧僌鈦簘]}{[\text{Al(H鈧侽)鈧喡斥伜}]} \]
This expression allows us to relate the concentrations of the products and reactants at equilibrium. Importantly, it implies the principle that at equilibrium, the rate of the forward reaction equals the rate of the reverse reaction.
Chemical Equilibrium
Chemical equilibrium is a state reached in a reversible chemical reaction when the rate of the forward reaction equals the rate of the reverse reaction, resulting in no net change in concentration of reactants and products over time. It is a dynamic state, as molecules continue to react, but the overall concentrations remain constant. When looking at the dissociation of Al(H鈧侽)鈧喡斥伜 in solution, equilibrium is reached when the rate at which Al(H鈧侽)鈧喡斥伜 ions form Al(H鈧侽)鈧(OH)虏鈦 and H鈧僌鈦 equals the rate at which these products recombine to form the Al(H鈧侽)鈧喡斥伜 ion.
Acid Dissociation Constant
The acid dissociation constant (K鈧) is a numerical value that indicates the strength of an acid in solution - the lower the K鈧 value, the weaker the acid. It measures the extent to which an acid can donate protons to water, forming hydronium ions (H鈧僌鈦). A high K鈧 means the acid more readily donates protons, leading to a greater concentration of hydronium ions. The K鈧 value of 1.4 x 10鈦烩伒 for Al(H鈧侽)鈧喡斥伜 tells us it is a weak acid since it partially dissociates in water.
Stoichiometry
Stoichiometry refers to the quantitative relationships between the amounts of reactants and products in a chemical reaction. These relationships are crucial for calculating the changes in concentration as reactants are converted into products. In the given reaction, the stoichiometry is 1:1:1 between Al(H鈧侽)鈧喡斥伜, Al(H鈧侽)鈧(OH)虏鈦, and H鈧僌鈦. This means that for every one mole of Al(H鈧侽)鈧喡斥伜 that dissociates, one mole of Al(H鈧侽)鈧(OH)虏鈦 and one mole of H鈧僌鈦 are produced. Understanding stoichiometry is essential for correctly setting up the K鈧 expression and subsequently solving for hydronium ion concentration.
Hydronium Ion Concentration
The concentration of hydronium ions (H鈧僌鈦) in a solution determines its acidity, and by extension, its pH. When a weak acid like Al(H鈧侽)鈧喡斥伜 dissociates, it increases the concentration of hydronium ions, causing the pH to decrease. pH is the negative base-10 logarithm of the hydronium ion concentration: \[\text{pH} = -\log[\text{H鈧僌鈦簘]\]
Therefore, by calculating the concentration of H鈧僌鈦 ions (denoted as 'x' in the K鈧 expression), we can determine the pH of the solution. In this exercise, we approximated the pH to be 3.23 based on the solved concentration of H鈧僌鈦, illustrating the direct relationship between hydronium ion concentration and pH levels in a solution.
Therefore, by calculating the concentration of H鈧僌鈦 ions (denoted as 'x' in the K鈧 expression), we can determine the pH of the solution. In this exercise, we approximated the pH to be 3.23 based on the solved concentration of H鈧僌鈦, illustrating the direct relationship between hydronium ion concentration and pH levels in a solution.