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Write a balanced equation for the reaction of chlorine gas with fluorine gas.

Short Answer

Expert verified
The balanced chemical equation for the reaction between chlorine gas and fluorine gas is Cl2 + 3 F2 -> 2 ClF3.

Step by step solution

01

Identify Reactants and Products

In this reaction, the reactants are chlorine gas (Cl2) and fluorine gas (F2). Chlorine will react with fluorine to produce a new compound, which will be a combination of the two elements. The product of this reaction is chlorine trifluoride (ClF3).
02

Write the Unbalanced Equation

Write down the chemical formula of the reactants and products. The unbalanced chemical equation is: Cl2 + F2 -> ClF3
03

Balance the Equation

Balance the number of atoms for each element on both sides of the equation. This can usually be done by adjusting the coefficients (the numbers in front of the molecules). Start by balancing one of the elements that is not diatomic in the products, like chlorine in this case: 1 Cl2 + 3 F2 -> 2 ClF3. This balances chlorine and fluorine atoms because there are 2 chlorine atoms and 6 fluorine atoms on both sides of the equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reaction
A chemical reaction is a process where substances, known as reactants, transform into different substances called products. This change is caused by the breaking and forming of chemical bonds, resulting in new materials with different properties.

For example, in the reaction where chlorine gas reacts with fluorine gas, the chlorine and fluorine atoms bond differently to form chlorine trifluoride. The atoms in the reactants (Chlorine \textbf{Cl} and Fluorine \textbf{F}) rearrange during the reaction to produce the compound chlorine trifluoride (\textbf{ClF}\(_3\)).

It's critical to remember when observing reactions like this, that during a chemical reaction, matter is not created or destroyed. This is known as the law of conservation of mass, which is the cornerstone for balancing chemical equations.
Stoichiometry
Stoichiometry is essentially the mathematics behind chemistry. It involves calculations that relate the quantities of reactants and products in a chemical reaction. This concept is pivotal in making sure that equations are balanced in terms of atoms and mass.

In our example, stoichiometry lets us find the appropriate coefficients to ensure that the number of atoms of each element is the same on both sides of the equation. It also helps to determine how much reactant is needed to produce a certain amount of product and vice versa, which is particularly useful in industrial applications and chemistry lab settings.

Importance in Balancing Equations

Without stoichiometry, we couldn't precisely predict the outcomes of reactions, as we wouldn't know the exact quantities to experiment with. It provides a quantitative relationship critical not only for the lab but also for real-world applications like pharmaceuticals, engineering, and environmental science.
Chemical Formula
A chemical formula is a way of presenting information about the chemical proportions of atoms that constitute a particular chemical compound or molecule, using chemical element symbols and numerical subscripts.

In the provided exercise, the reactant chemicals were chlorine gas (\textbf{Cl}\(_2\)) and fluorine gas (\textbf{F}\(_2\)), and the product was chlorine trifluoride (\textbf{ClF}\(_3\)). The subscripts in the formula represent the number of atoms of each element in the molecule. For example, \textbf{Cl}\(_2\) indicates that there are two atoms of chlorine bonded together.

Understanding chemical formulas is essential when balancing chemical equations because it gives us the information required to ensure that atoms are conserved in a reaction. It's the language that allows chemists to convert from the microscopic world of atoms and molecules to the macroscopic world of grams and liters.

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Most popular questions from this chapter

Zinc sulfide reacts with oxygen according to the reaction: $$ 2 \mathrm{ZnS}(s)+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{ZnO}(s)+2 \mathrm{SO}_{2}(g) $$ A reaction mixture initially contains \(4.2 \mathrm{~mol} \mathrm{ZnS}\) and \(6.8 \mathrm{~mol}\) \(\mathrm{O}_{2} .\) Once the reaction has occurred as completely as possible, what amount (in moles) of the excess reactant remains?

Write the balanced chemical equation for each reaction. a. Solid copper reacts with solid sulfur to form solid copper(I) sulfide. b. Solid iron(III) oxide reacts with hydrogen gas to form solid iron and liquid water. c. Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas. d. Gaseous ammonia \(\left(\mathrm{NH}_{3}\right)\) reacts with gaseous oxygen to form gaseous nitrogen monoxide and gaseous water.

Nitric acid is a component of acid rain that forms when gaseous nitrogen dioxide pollutant reacts with gaseous oxygen and liquid water to form aqueous nitric acid. Write the balanced chemical equation for this reaction. (Note: This is a simplified representation of this reaction.)

In a popular classroom demonstration, solid sodium is added to liquid water and reacts to produce hydrogen gas and aqueous sodium hydroxide. Write the balanced chemical equation for this reaction.

Complete and balance each combustion reaction equation: a. \(\mathrm{C}_{4} \mathrm{H}_{6}(g)+\mathrm{O}_{2}(g) \longrightarrow\) b. \(\mathrm{C}(s)+\mathrm{O}_{2}(g) \longrightarrow\) c. \(\mathrm{CS}_{2}(s)+\mathrm{O}_{2}(g) \longrightarrow\) d. \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}(l)+\mathrm{O}_{2}(g) \longrightarrow\)

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