Chapter 15: Problem 10
Write integrated rate laws for zero-order, first-order, and secondorder reactions of the form \(\mathrm{A} \longrightarrow\) products.
Short Answer
Expert verified
Zero-order: \[A\] = \[A\text{_{0}}\] - kt. First-order: ln(\text{[A]}/\[A\text{_{0}}\]) = -kt. Second-order: 1/[[A]] - 1/[[A]]_0 = kt.
Step by step solution
01
Zero-Order Reaction
A zero-order reaction has a rate that is independent of the concentration of the reactant. Its rate law can be written as: rate = k, where k is the rate constant. The integrated rate law for a zero-order reaction can be derived from the rate law by separating variables and integrating from the initial concentration of A, \[A\text{_{0}}\], to the concentration of A at time t, \[A\], and from 0 to t. This yields the equation: \[[A\] - \[A\text{_{0}}\] = -kt.
02
First-Order Reaction
The rate of a first-order reaction is directly proportional to the concentration of one reactant. The rate law for a first-order reaction is: rate = k\text{[A]}. By separating variables and integrating, the integrated rate law for a first-order reaction is derived as: ln(\text{[A]}/\[A\text{_{0}}\]) = -kt.
03
Second-Order Reaction
For a second-order reaction, the rate is proportional to the square of the concentration of one reactant. The rate law for a second-order reaction is: rate = k[[A]]^2. The integrated rate law is found by separating variables and integrating, which gives: 1/[[A]] - 1/[[A]]_0 = kt.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Zero-Order Reactions
When exploring the kinetics of chemical reactions, a zero-order reaction is one where the rate is constant and does not depend on the concentration of the reactant. Imagine a bustling kitchen where chefs are cooking meals at a steady rate, regardless of how many ingredients are on hand. This is akin to a zero-order reaction, where the rate law is simply expressed as 'rate = k', with 'k' being the constant rate of the reaction.
Delving into the mathematics, the integrated rate law for a zero-order reaction can be represented as \[A\] - \[A_{0}\] = -kt. This equation tells us that the concentration of the reactant A decreases linearly over time, similar to a clock ticking down steadily. In other words, for each unit of time that passes, a fixed amount of the reactant A is transformed into products, until it is depleted. This type of reaction is quite rare and generally occurs under conditions where the reactant is in excess or when a catalyst surface is saturated with the reactant.
Delving into the mathematics, the integrated rate law for a zero-order reaction can be represented as \[A\] - \[A_{0}\] = -kt. This equation tells us that the concentration of the reactant A decreases linearly over time, similar to a clock ticking down steadily. In other words, for each unit of time that passes, a fixed amount of the reactant A is transformed into products, until it is depleted. This type of reaction is quite rare and generally occurs under conditions where the reactant is in excess or when a catalyst surface is saturated with the reactant.
- Rate Constant (k): The speed at which the reaction proceeds.
- Initial Concentration (\[A_{0}\]): The starting concentration of reactant A.
- Concentration of A at time t (\[A\]): The concentration after time t has elapsed.
First-Order Reactions Simplified
First-order reactions are like a game of musical chairs—each participant (reactant molecule) has a chance to find a chair (transform into product) that is directly proportional to the number of players (concentration of the reactant). In chemical terms, the rate of a first-order reaction is directly proportional to the concentration of the reactant. It follows the rate law 'rate = k[A]', signifying that the rate changes with varying concentrations of reactant A.
The integrated rate law for a first-order reaction is a bit more complex but equally revealing, given by the natural logarithm ln(\[A\]/\[A_{0}\]) = -kt. This logarithmic relationship indicates that as time ticks away, the concentration of the reactant A decreases exponentially. Unlike the steady cookware in a zero-order kitchen, the concentration here affects the cooking speed. You can think of k as the pace at which the chefs work—the higher it is, the faster the ingredients are used up.
The integrated rate law for a first-order reaction is a bit more complex but equally revealing, given by the natural logarithm ln(\[A\]/\[A_{0}\]) = -kt. This logarithmic relationship indicates that as time ticks away, the concentration of the reactant A decreases exponentially. Unlike the steady cookware in a zero-order kitchen, the concentration here affects the cooking speed. You can think of k as the pace at which the chefs work—the higher it is, the faster the ingredients are used up.
- Natural Logarithm (ln): Showcases the exponential decline of reactant concentration over time.
- Dependence on Concentration: Indicates the reaction speeds up or slows down based on reactant availability.
Deciphering Second-Order Reactions
Second-order reactions take us into a different dynamic, akin to a team sport where cooperation is key. The rate of reaction depends on the interaction between two reactant molecules or two times the concentration of a single reactant as described by the rate law 'rate = k\[[A\]]^2'. Imagine partners in a dance competition moving with a speed that's influenced by the level of coordination between them. Here the coordination correlates to the concentration of reactant A.
The integrated rate law for a second-order reaction draws a picture of how these interactions change over time, described by the equation 1/\[[A\]] - 1/\[[A_{0}\]] = kt. This highlights the fact that as the reactant concentration decreases, the reaction rate also decreases, but much more dramatically compared to first-order reactions. Unlike the linear or exponential relationships seen in zero- and first-order reactions, second-order reactions form a curve that gets steeper as time progresses.
The integrated rate law for a second-order reaction draws a picture of how these interactions change over time, described by the equation 1/\[[A\]] - 1/\[[A_{0}\]] = kt. This highlights the fact that as the reactant concentration decreases, the reaction rate also decreases, but much more dramatically compared to first-order reactions. Unlike the linear or exponential relationships seen in zero- and first-order reactions, second-order reactions form a curve that gets steeper as time progresses.
- Rate Law and Squared Concentration: Underscores the idea that the reaction rate is tied to the square of the reactant’s concentration.
- Integrated Rate Law: Allows us to predict concentrations at various times and deduce the reaction kinetics.