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Using the molecular orbital model, write electron configurations for the following diatomic species and calculate the bond orders. Which ones are paramagnetic? Place the species in order of increasing bond length and bond energy. a. CO b. \(\mathrm{CO}^{+}\) c. \(\mathrm{CO}^{2+}\)

Short Answer

Expert verified
Electron configurations: CO: \(\sigma_{1s}^2\sigma_{1s*}^2\sigma_{2s}^2\sigma_{2s*}^2\pi_{2p}^4\sigma_{2p}^2\); \(\mathrm{CO}^{+}\): \(\sigma_{1s}^2\sigma_{1s*}^2\sigma_{2s}^2\sigma_{2s*}^2\pi_{2p}^4\sigma_{2p}^1\); \(\mathrm{CO}^{2+}\): \(\sigma_{1s}^2\sigma_{1s*}^2\sigma_{2s}^2\sigma_{2s*}^2\pi_{2p}^4\). Bond orders: CO (3), \(\mathrm{CO}^{+}\) (2.5), and \(\mathrm{CO}^{2+}\) (2). The paramagnetic species is \(\mathrm{CO}^{+}\). The order by bond length is CO < \(\mathrm{CO}^{+}\) < \(\mathrm{CO}^{2+}\), and the order by bond energy is \(\mathrm{CO}^{2+}\) < \(\mathrm{CO}^{+}\) < CO.

Step by step solution

01

1. Write electron configurations using the molecular orbital model

To write the electron configurations for CO, \(\mathrm{CO}^{+}\), and \(\mathrm{CO}^{2+}\), first recall the atomic electron configurations for Carbon (C) and Oxygen (O): Carbon (C) has 6 electrons: 1s虏 2s虏 2p虏 Oxygen (O) has 8 electrons: 1s虏 2s虏 2p鈦 Now, combine the electron configurations for C and O, and distribute the electrons based on molecular orbital energy diagram for diatomic molecules: CO (14 electrons): \(\sigma_{1s}^2\sigma_{1s*}^2\sigma_{2s}^2\sigma_{2s*}^2\pi_{2p}^4\sigma_{2p}^2\). \(\mathrm{CO}^{+}\) (13 electrons): \(\sigma_{1s}^2\sigma_{1s*}^2\sigma_{2s}^2\sigma_{2s*}^2\pi_{2p}^4\sigma_{2p}^1\). \(\mathrm{CO}^{2+}\) (12 electrons): \(\sigma_{1s}^2\sigma_{1s*}^2\sigma_{2s}^2\sigma_{2s*}^2\pi_{2p}^4\).
02

2. Calculate the bond orders

To calculate the bond orders, use the formula: Bond order = (Number of electrons in bonding orbitals - Number of electrons in antibonding orbitals) / 2. CO: Bond order = (10 - 4) / 2 = 3. CO\(^{+}\): Bond order = (9 - 4) / 2 = 2.5. CO\(^{2+}\): Bond order = (8 - 4) / 2 = 2.
03

3. Identify paramagnetic species

A species is paramagnetic if it has unpaired electrons. From the electron configurations: CO: All electrons are paired; it is diamagnetic. CO\(^{+}\): One unpaired electron in \(\sigma_{2p}\); it is paramagnetic. CO\(^{2+}\): All electrons are paired; it is diamagnetic.
04

4. Order species by bond length and bond energy

Bond length is inversely proportional to the bond order and bond energy is directly proportional to the bond order. - Bond order: CO\(^{2+}\) < CO\(^{+}\) < CO - Bond length: CO < CO\(^{+}\) < CO\(^{2+}\) - Bond energy: CO\(^{2+}\) < CO\(^{+}\) < CO In summary: 1. Electron configurations: CO: \(\sigma_{1s}^2\sigma_{1s*}^2\sigma_{2s}^2\sigma_{2s*}^2\pi_{2p}^4\sigma_{2p}^2\). CO\(^{+}\): \(\sigma_{1s}^2\sigma_{1s*}^2\sigma_{2s}^2\sigma_{2s*}^2\pi_{2p}^4\sigma_{2p}^1\). CO\(^{2+}\): \(\sigma_{1s}^2\sigma_{1s*}^2\sigma_{2s}^2\sigma_{2s*}^2\pi_{2p}^4\). 2. Bond orders: CO (3), CO\(^{+}\) (2.5), CO\(^{2+}\) (2). 3. Paramagnetic species: CO\(^{+}\). 4. Order by bond length: CO < CO\(^{+}\) < CO\(^{2+}\). 5. Order by bond energy: CO\(^{2+}\) < CO\(^{+}\) < CO.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configurations
Electron configurations describe how electrons are distributed among the molecular orbitals of a molecule. In molecular orbital theory, these configurations are key to understanding the chemical and physical behavior of molecules.
For diatomic molecules like CO and its ions ( CO^{+} , CO^{2+} ), we combine atomic orbitals of individual atoms into molecular orbitals. Carbon (C) provides 6 electrons, and Oxygen (O) supplies 8 electrons, which makes a total of 14 electrons for the carbon monoxide (CO) molecule.
Using the molecular orbital energy diagram, we distribute these 14 electrons among various orbitals:
  • 蟽_{1s}^{2} , 蟽_{1s^{*}}^{2} (these represent the inner core electrons and have little effect on bonding)
  • 蟽_{2s}^{2} , 蟽_{2s^{*}}^{2}
  • 蟺冲调2辫皑镑调4皑
  • 蟽冲调2辫皑镑调2皑

Thus, the electron configurations are:
  • CO: 蟽_{1s}^{2}蟽_{1s^{*}}^{2}蟽_{2s}^{2}蟽_{2s^{*}}^{2}蟺冲调2辫皑镑调4皑蟽冲调2辫皑镑调2皑
  • CO鈦: 蟽_{1s}^{2}蟽_{1s^{*}}^{2}蟽_{2s}^{2}蟽_{2s^{*}}^{2}蟺冲调2辫皑镑调4皑蟽_{2p}^{1}
  • CO虏鈦: 蟽_{1s}^{2}蟽_{1s^{*}}^{2}蟽_{2s}^{2}蟽_{2s^{*}}^{2}蟺冲调2辫皑镑调4皑
This approach helps in explaining different properties such as bond order and magnetic behavior.
Bond Order
Bond order indicates the strength and stability of a bond. It is calculated by taking the difference between the number of electrons in bonding orbitals and antibonding orbitals, divided by two.
The formula is:
  • Bond Order = (Number of Bonding Electrons - Number of Antibonding Electrons) / 2

For CO, CO鈦, and CO虏鈦:
  • CO: Bond order = (10 - 4) / 2 = 3
  • CO鈦: Bond order = (9 - 4) / 2 = 2.5
  • CO虏鈦: Bond order = (8 - 4) / 2 = 2
A higher bond order suggests a stronger, shorter, and more stable bond. Therefore, the bond order helps predict the molecular stability and bond characteristics. CO, with the highest bond order, is the most stable and has the strongest bond. As we remove electrons to go to CO鈦 and CO虏鈦, the bonds become weaker and longer.
Paramagnetism
Paramagnetism arises in molecules with unpaired electrons. A molecule is paramagnetic if it can be attracted to an external magnetic field, which is a direct result of its unpaired electrons.
In the context of molecular orbitals:
  • CO: All electrons are paired, making it diamagnetic (not attracted to magnetic fields).
  • CO鈦: Has one unpaired electron in the 蟽_{2p} orbital, which makes it paramagnetic.
  • CO虏鈦: All electrons paired again, rendering it diamagnetic.
To identify paramagnetic species, look for unfilled molecular orbitals, which typically indicates unpaired electrons. This characteristic impacts a molecule's magnetic properties, demonstrating an intriguing aspect of chemistry where electronic configurations determine physical attributes.
Diatomic Molecules
Diatomic molecules consist of two atoms, which may either be the same element or different (like CO). Understanding these simple molecules is crucial because they form the basis for more complex structures in chemical theory.
Studying diatomic molecules using molecular orbital theory involves:
  • Identifying the number of electrons involved by considering each atom.
  • Filling these electrons into molecular orbitals, starting from the lowest energy level and following exclusion and filling rules.
  • Using molecular orbital diagrams to infer properties such as bond order, bond length, and magnetic behavior.
In exercises like the one involving CO, CO鈦, and CO虏鈦, the relative bond order allows us to predict properties like bond energy and bond length. Diatomic molecules are straightforward yet immensely valuable in providing insight into molecular interactions and structure-function relationships.

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