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The first ionization energies of As and Se are \(0.947\) and \(0.941\) MJ/mol, respectively. Rationalize these values in terms of electron configurations.

Short Answer

Expert verified
The first ionization energy of As is slightly higher than that of Se because upon ionization, As has a relatively more stable half-filled configuration in the 4p orbital. As has an electron configuration of \(4p^3\), which, upon losing an electron, results in a stable \(4p^2\) configuration. In contrast, Se has an electron configuration of \(4p^4\), and after losing an electron, it becomes \(4p^3\), a less stable state compared to the half-filled state. Thus, a higher ionization energy is required for As than for Se.

Step by step solution

01

Determine the atomic numbers of As and Se

First, we need to find out the atomic numbers of As and Se. From the periodic table, we can determine that: - Arsenic (As) has an atomic number of 33 - Selenium (Se) has an atomic number of 34
02

Write the electron configurations of As and Se

Now that we have the atomic numbers of As and Se, we can determine their electron configurations: Arsenic (As): 1s虏, 2s虏, 2p^6, 3s虏, 3p^6, 4s虏, 3d^10, 4p^3 \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^2, 3d^{10}, 4p^3\) Selenium (Se): 1s虏, 2s虏, 2p^6, 3s虏, 3p^6, 4s虏, 3d^10, 4p^4 \(1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^2, 3d^{10}, 4p^4\)
03

Analyze the electron configurations

Looking at the electron configurations, both As and Se have completely filled 3d orbitals. For ionization energy, we must focus on the outermost electrons, which are present in the 4p orbital. - The outermost electron configuration of As is 4p^3 - The outermost electron configuration of Se is 4p^4
04

Relate the ionization energy to electron configurations

In the case of the 4p orbital, it has a maximum capacity of 6 electrons. Removing the first electron for As would reduce its configuration from 4p^3 to 4p虏, which provides a relatively stable half-filled configuration. On the other hand, Se has a configuration of 4p^4. Removing an electron results in 4p^3, a less stable configuration compared to the half-filled state. Given that As has a relatively more stable half-filled configuration upon losing an electron, it would require slightly more energy to ionize the first electron. Thus, the first ionization energy would be a little higher for As in comparison to Se. This explains why the first ionization energies of As (0.947 MJ/mol) and Se (0.941 MJ/mol) differ, with As having a slightly higher value due to its relatively stable configuration upon ionization.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Understanding the electron configuration of an element is essential to grasp why different elements have varying ionization energies. Electron configuration refers to the distribution of electrons among the different orbitals of an atom. These orbitals are labeled as s, p, d, and f, and they have specific capacities to hold electrons: s can hold 2, p can hold 6, d can hold 10, and f can hold 14.

The configuration is often written in a sequence with numbers and letters, like 1s虏 2s虏 2p鈦, indicating how many electrons are in each orbital. Starting from the lowest energy level, electrons fill up the orbitals in a way that minimizes the energy of the atom. An important principle here is Hund鈥檚 rule which states that electrons will fill an orbital singly as far as possible before pairing up. This is why an electron configuration ending in 4p鲁, like in the case of arsenic (As), is more stable - due to it being exactly half-filled.

In our textbook exercise, arsenic's ionization energy is slightly higher because removing an electron disturbs a stable half-filled p orbital. In contrast, selenium (Se) has one more electron in the p orbital, and removing it still leaves a half-filled orbital, thus requiring slightly less energy.
Periodic Table
The periodic table is a systematic organization of the chemical elements, ordered by their atomic number, electron configuration, and recurring chemical properties. Elements are arranged in rows called periods and columns known as groups. Each element in the table is represented by its chemical symbol, like As for arsenic and Se for selenium, and typically includes details such as atomic number and atomic mass.

When dealing with ionization energy, the periodic table is incredibly useful. It enables us to predict trends in ionization energy across different elements. Generally, ionization energy increases across a period (from left to right) and decreases down a group (from top to bottom). The position of an element in the periodic table helps us understand the electron configuration, which is crucial to understanding the ionization energy as shown in our exercise.
Atomic Number
The atomic number is a fundamental property of an element and refers to the number of protons in the nucleus of an atom. This number is unique to each element and dictates its position on the periodic table. The atomic number also determines the number of electrons in a neutral atom, which in turn defines the atom's electron configuration.

In our exercise, knowing the atomic numbers of arsenic (33) and selenium (34) allowed us to derive their electron configurations and analyze their ionization energies. The atomic number directly impacts the ionization energy, as an increase usually leads to a higher positive charge in the nucleus, which in turn attracts the outermost electron more strongly, generally increasing the ionization energy. However, as seen between As and Se, the stability of the electron configuration also plays a significant role in the ionization process.

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Most popular questions from this chapter

A carbon-oxygen double bond in a certain organic molecule absorbs radiation that has a frequency of \(6.0 \times 10^{13} \mathrm{~s}^{-1}\). a. What is the wavelength of this radiation? b. To what region of the spectrum does this radiation belong? c. What is the energy of this radiation per photon? per mole of photons? d. A carbon-oxygen bond in a different molecule absorbs radiation with frequency equal to \(5.4 \times 10^{13} \mathrm{~s}^{-1} .\) Is this radiation more or less energetic?

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