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One bit of evidence that the quantum mechanical model is "correct" lies in the magnetic properties of matter. Atoms with unpaired electrons are attracted by magnetic fields and thus are said to exhibit paramagnetism. The degree to which this effect is observed is directly related to the number of unpaired electrons present in the atom. Consider the ground-state electron configurations for \(\mathrm{Li}, \mathrm{N}, \mathrm{Ni}, \mathrm{Te}, \mathrm{Ba}\), and \(\mathrm{Hg} .\) Which of these atoms would be expected to be paramagnetic, and how many unpaired electrons are present in each paramagnetic atom?

Short Answer

Expert verified
The paramagnetic elements and their number of unpaired electrons are: - Lithium (Li): 1 unpaired electron - Nitrogen (N): 3 unpaired electrons - Nickel (Ni): 2 unpaired electrons - Tellurium (Te): 2 unpaired electrons Barium (Ba) and Mercury (Hg) do not have unpaired electrons and are not expected to be paramagnetic.

Step by step solution

01

Write the ground-state electron configurations

First, let's write the ground-state electron configurations for each of the given elements: - Lithium (Li): Atomic number 3 鈥 1s虏 2s鹿 - Nitrogen (N): Atomic number 7 鈥 1s虏 2s虏 2p鲁 - Nickel (Ni): Atomic number 28 鈥 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鈦 - Tellurium (Te): Atomic number 52 鈥 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 - Barium (Ba): Atomic number 56 鈥 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 - Mercury (Hg): Atomic number 80 鈥 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 4f鹿鈦 5d鹿鈦
02

Identify paramagnetic elements

Now, we can determine which of these elements have unpaired electrons, causing them to be paramagnetic: - Li: 1 unpaired electron in 2s鹿 - N: 3 unpaired electrons in 2p鲁 - Ni: 2 unpaired electrons in 3d鈦 - Te: 2 unpaired electrons in 5p鈦 - Ba: No unpaired electrons - Hg: No unpaired electrons
03

Write the final answer

Based on the analysis above, the paramagnetic elements and the number of unpaired electrons are: - Lithium (Li): 1 unpaired electron - Nitrogen (N): 3 unpaired electrons - Nickel (Ni): 2 unpaired electrons - Tellurium (Te): 2 unpaired electrons Barium (Ba) and Mercury (Hg) do not have unpaired electrons and therefore are not expected to exhibit paramagnetism.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quantum Mechanical Model
The quantum mechanical model of atoms is a foundational cornerstone of modern chemistry and physics. This model describes the behavior of electrons in an atom as existing in regions called orbitals, not fixed paths. The electrons are represented by wave functions, which provide the probability of finding an electron in a particular region around the nucleus.

According to this model, each orbital has a specific energy level and can hold a maximum of two electrons. These electrons must have opposite spins, a phenomenon known as the Pauli Exclusion Principle. The quantum model integrates principles from wave mechanics and provides a more accurate explanation for the electron configurations and chemical properties of elements.

Understanding the quantum mechanical model is critical for explaining why certain elements exhibit magnetic properties such as paramagnetism, which is directly linked to the presence of unpaired electrons as quantified by quantum numbers.
Unpaired Electrons
Unpaired electrons are singular electrons in an atom's electron shell that are not part of an electron pair. Electron pairs share the same orbital but have opposite spins, thereby 'pairing up'. Atoms with unpaired electrons are often the source of magnetic properties in materials.

Paramagnetism, a form of magnetism, occurs in atoms that have at least one unpaired electron. The magnetic field produced by these electrons causes the atoms to align with and be attracted by an external magnetic field. The number of unpaired electrons in an atom contributes to the strength of its paramagnetic properties. Higher numbers of unpaired electrons mean a stronger paramagnetic effect.

Identifying Unpaired Electrons

In the case of our textbook problem, identifying the unpaired electrons involved analyzing the electron configurations of each element and detecting orbitals that are not entirely filled with electron pairs.
Ground-State Electron Configurations
Ground-state electron configurations describe the arrangement of electrons in the lowest energy state, or base level, of an atom. These configurations provide essential information about the properties and behavior of an element, including its chemical reactivity and physical properties such as paramagnetism.

Electrons fill the available orbitals in a manner that minimizes the atom's energy, starting from the lowest to the highest energy orbitals鈥攁 guideline known as the Aufbau principle. The ground-state configuration leads to a predictable periodicity on the periodic table, explaining the structure behind periodic trends such as atomic size and ionization energy.

The exercise required determining the ground-state electron configurations of several elements. By carefully following the Aufbau principle, Hund's rule, and the Pauli Exclusion Principle, the configurations show which elements have unpaired electrons and are expected to be paramagnetic. For example, Lithium (Li) has a single unpaired electron, while Barium (Ba) and Mercury (Hg) have none, explaining their lack of paramagnetic properties.

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Most popular questions from this chapter

Cesium was discovered in natural mineral waters in \(1860 \mathrm{by}\) R. W. Bunsen and G. R. Kirchhoff using the spectroscope they invented in \(1859 .\) The name came from the Latin caesius ("sky blue") because of the prominent blue line observed for this element at \(455.5 \mathrm{~nm} .\) Calculate the frequency and energy of a photon of this light.

Give the maximum number of electrons in an atom that can have these quantum numbers: a. \(n=4\) b. \(n=5, m_{\ell}=+1\) c. \(n=5, m_{s}=+\frac{1}{2}\) d. \(n=3, \ell=2\) e. \(n=2, \ell=1\)

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electromagnetic radiation is emitted in each transition? a. \(n=3 \rightarrow n=2\) b. \(n=4 \rightarrow n=2\) c. \(n=2 \rightarrow n=1\)

Which of the following statements is(are) true? a. The \(2 s\) orbital in the hydrogen atom is larger than the \(3 s\) orbital also in the hydrogen atom. b. The Bohr model of the hydrogen atom has been found to be incorrect. c. The hydrogen atom has quantized energy levels. d. An orbital is the same as a Bohr orbit. e. The third energy level has three sublevels, the \(s, p\), and \(d\) sublevels.

Answer the following questions based on the given electron configurations, and identify the elements. a. Arrange these atoms in order of increasing size: \([\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{6} ;[\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{1} ;[\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{3}\) b. Arrange these atoms in order of decreasing first ionization energy: \([\mathrm{Ne}] 3 s^{2} 3 p^{5} ;[\mathrm{Ar}] 4 s^{2} 3 d^{10} 4 p^{3} ;[\mathrm{Ar}] 4 s^{2} 3 d^{10} 4 p^{5}\).

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