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Assign the oxidation state for nitrogen in each of the following. a. \(\mathrm{Li}_{3} \mathrm{~N}\) b. \(\mathrm{NH}_{3}\) c. \(\mathrm{N}_{2} \mathrm{H}_{4}\) d. \(\mathrm{NO}\) e. \(\mathrm{N}_{2} \mathrm{O}\) f. \(\mathrm{NO}_{2}\) g. \(\mathrm{NO}_{2}^{-}\) h. \(\mathrm{NO}_{3}^{-}\) I. \(\mathrm{N}_{2}\)

Short Answer

Expert verified
The oxidation states for nitrogen in each compound are as follows: a. Li3N: -3 b. NH3: -1/3 c. N2H4: -2 d. NO: +2 e. N2O: +1 f. NO2: +4 g. NO2-: +3 h. NO3-: +5 i. N2: 0

Step by step solution

01

Rule for assigning oxidation states

When assigning oxidation states for each element in a compound, the sum of all oxidation states must equal the overall charge of the compound. For neutral compounds, the sum of oxidation states must be zero. Different elements have commonly occurring oxidation states according to their positions in the periodic table.
02

Assign oxidation state for nitrogen in Li3N#a.

In Li3N, Li is an alkali metal, and its oxidation state is always +1. Thus, the oxidation state of N should be assigned such that the sum of the oxidation states in Li3N is zero. The oxidation states can be represented by: \(3(+1) + x = 0\) Solving for x, which represents the oxidation state for nitrogen in this compound: x = -3 Thus, the oxidation state of nitrogen in Li3N is -3.
03

Assign oxidation state for nitrogen in NH3 #b.

In NH3, hydrogen has an oxidation state of +1. To find the oxidation state of nitrogen, we will again ensure that the sum of oxidation states equals zero: \(+1 + 3x = 0\) Solving for x: x = -1/3 Thus, the oxidation state of nitrogen in NH3 is -1/3.
04

Assign oxidation state for nitrogen in N2H4 #c.

In N2H4, hydrogen has an oxidation state of +1. Since there are two nitrogen atoms in the compound, the sum of oxidation states can be represented as: \(2x + 4(+1) = 0\) Solving for x: x = -2 Thus, the oxidation state of nitrogen in N2H4 is -2.
05

Assign oxidation state for nitrogen in NO #d.

In NO, we have an oxidation state of -2 for oxygen. To find the oxidation state of nitrogen, we will ensure that the sum of oxidation states equals zero: \(x - 2 = 0\) Solving for x: x = +2 Thus, the oxidation state of nitrogen in NO is +2.
06

Assign oxidation state for nitrogen in N2O #e.

In N2O, we have an oxidation state of -2 for oxygen. Since there are two nitrogen atoms in the compound, the sum of oxidation states can be represented as: \(2x - 2 = 0\) Solving for x: x = +1 Thus, the oxidation state of nitrogen in N2O is +1.
07

Assign oxidation state for nitrogen in NO2 #f.

In NO2, we have an oxidation state of -2 for each oxygen atom. To find the oxidation state of nitrogen, we will ensure that the sum of oxidation states equals zero: \(x - 4 = 0\) Solving for x: x = +4 Thus, the oxidation state of nitrogen in NO2 is +4.
08

Assign oxidation state for nitrogen in NO2- #g.

In NO2-, we have an oxidation state of -2 for each oxygen atom, and the overall charge of the compound is -1. To find the oxidation state of nitrogen, we will ensure that the sum of oxidation states equals the charge of the compound: \(x - 4 = -1\) Solving for x: x = +3 Thus, the oxidation state of nitrogen in NO2- is +3.
09

Assign oxidation state for nitrogen in NO3- #h.

In NO3-, we have an oxidation state of -2 for each oxygen atom, and the overall charge of the compound is -1. To find the oxidation state of nitrogen, we will ensure that the sum of oxidation states equals the charge of the compound: \(x - 6 = -1\) Solving for x: x = +5 Thus, the oxidation state of nitrogen in NO3- is +5.
10

Assign oxidation state for nitrogen in N2 #i.

In N2 molecule, nitrogen does not form a bond with any other element but exists in a diatomic form. In this case, the oxidation state of both nitrogen atoms is zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Assigning Oxidation Numbers
Understanding how to assign oxidation numbers is crucial in the study of redox reactions and chemistry as a whole. An oxidation number, often known as an oxidation state, is a figure used in chemistry to indicate the degree of oxidation of an atom in a chemical compound. Oxidation numbers help chemists keep track of electron transfer in redox reactions.

The rules for assigning oxidation numbers include:
  • The oxidation number of an atom in its elemental form is always zero.
  • For ions comprising just one atom, the oxidation number is equal to the charge on the ion.
  • Oxygen usually has an oxidation number of -2, except in peroxides.
  • Hydrogen typically has an oxidation number of +1 when bonded to nonmetals and -1 when bonded to metals.
  • The sum of oxidation numbers in a neutral molecule must be zero, while in an ion, it must equal the ion's charge.

The periodic table also provides guidance, as elements in the same group often have similar oxidation states. For instance, alkali metals (group 1) always have an oxidation number of +1, and alkaline earth metals (group 2) have an oxidation number of +2. By following these guidelines, chemists systematically find the oxidation states of elements in chemical compounds.
Redox Reactions
Redox reactions are chemical reactions that involve a transfer of electrons between two species. It's a combination of two processes: reduction and oxidation. Oxidation refers to the loss of electrons, while reduction is the gain of electrons. To remember this, the mnemonic 'OIL RIG' can be used, meaning 'Oxidation Is Loss, Reduction Is Gain.'

Redox reactions are essential in various biological processes, industrial applications, and even in everyday life, such as in batteries and combustion. Oxidation numbers provide insight into the electron movement in redox processes. A change in oxidation number indicates that a redox reaction has occurred. For instance, in the oxidation of glucose in our bodies, glucose's carbon atoms lose electrons (oxidized), while oxygen is reduced (gains electrons).
Periodic Table
The periodic table is a tabular display of all chemical elements, organized by their chemical properties and electron configurations. Elements are displayed in order of increasing atomic number, that is, the number of protons in an atom's nucleus, which uniquely identifies a chemical element. The layout of the table has significant importance because it brings insight into the reactivity and properties of the elements, including oxidation states.

As you move from left to right across a period, the oxidation states usually increase, while moving down a group typically indicates a constant state or minor variations. Understanding the trend in oxidation states across the periodic table can help you predict the makeup of compounds and the results of chemical reactions.
Chemical Compounds
Chemical compounds are substances formed by two or more different types of elements held together by chemical bonds. The way the oxidation number is used can be crucial to understanding the nature of a compound. For example, knowing the oxidation state of an element in a compound can tell us whether it is in its elemental form, part of a simple ion, or involved in a complex ion.

Compounds also have a specific nomenclature that reflects the oxidation states of their constituent elements. For example, the presence of different oxidation states in transition metals can give rise to compounds with very different properties, such as color or magnetic behavior. An understanding of how oxidation numbers work helps in not only naming these compounds but also in predicting and explaining their reactivity and interaction with other chemicals.

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Most popular questions from this chapter

The unknown acid \(\mathrm{H}_{2} \mathrm{X}\) can be neutralized completely by \(\mathrm{OH}^{-}\) according to the following (unbalanced) equation: $$ \mathrm{H}_{2} \mathrm{X}(a q)+\mathrm{OH}^{-}(a q) \longrightarrow \mathrm{X}^{2-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) $$ The ion formed as a product, \(\mathrm{X}^{2-}\), was shown to have 36 total electrons. What is element \(\mathrm{X}\) ? Propose a name for \(\mathrm{H}_{2} \mathrm{X}\). To completely neutralize a sample of \(\mathrm{H}_{2} \mathrm{X}, 35.6 \mathrm{~mL}\) of \(0.175 \mathrm{M}\) \(\mathrm{OH}^{-}\) solution was required. What was the mass of the \(\mathrm{H}_{2} \mathrm{X}\) sample used?

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Three students were asked to find the identity of the metal in a particular sulfate salt. They dissolved a \(0.1472-\mathrm{g}\) sample of the salt in water and treated it with excess barium chloride, resulting in the precipitation of barium sulfate. After the precipitate had been filtered and dried, it weighed \(0.2327 \mathrm{~g}\). Each student analyzed the data independently and came to different conclusions. Pat decided that the metal was titanium. Chris thought it was sodium. Randy reported that it was gallium. What formula did each student assign to the sulfate salt? Look for information on the sulfates of gallium, sodium, and titanium in this text and reference books such as the \(C R C\) Handbook of Chemistry and Physics. What further tests would you suggest to determine which student is most likely correct?

A \(50.00-\mathrm{mL}\) sample of aqueous \(\mathrm{Ca}(\mathrm{OH})_{2}\) requires \(34.66 \mathrm{~mL}\) of a \(0.944-M\) nitric acid for neutralization. Calculate the concentration (molarity) of the original solution of calcium hydroxide.

When the following solutions are mixed together, what precipitate (if any) will form? a. \(\mathrm{FeSO}_{4}(a q)+\mathrm{KCl}(a q)\) b. \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}(a q)+\mathrm{Ba}(\mathrm{OH})_{2}(a q)\) c. \(\mathrm{CaCl}_{2}(a q)+\mathrm{Na}_{2} \mathrm{SO}_{4}(a q)\) d. \(\mathrm{K}_{2} \mathrm{~S}(a q)+\mathrm{Ni}\left(\mathrm{NO}_{3}\right)_{2}(a q)\)

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