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Which of the following pairs of compounds have the same empirical formula? a. acetylene, \(\mathrm{C}_{2} \mathrm{H}_{2}\), and benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\) b. ethane, \(\mathrm{C}_{2} \mathrm{H}_{6}\), and butane, \(\mathrm{C}_{4} \mathrm{H}_{10}\) c. nitrogen dioxide, \(\mathrm{NO}_{2}\), and dinitrogen tetroxide, \(\mathrm{N}_{2} \mathrm{O}_{4}\) d. diphenyl ether, \(\mathrm{C}_{12} \mathrm{H}_{10} \mathrm{O}\), and phenol, \(\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{OH}\)

Short Answer

Expert verified
The pairs of compounds with the same empirical formula are: a. Acetylene, $\mathrm{C}_{2} \mathrm{H}_{2}$, and benzene, $\mathrm{C}_{6}\mathrm{H}_{6}$ c. Nitrogen dioxide, $\mathrm{NO}_{2}$, and dinitrogen tetroxide, $\mathrm{N}_{2} \mathrm{O}_{4}$

Step by step solution

01

Find the ratio of atoms in each compound

For each compound, we will find the ratio between the different types of atoms. a. Acetylene: C2H2 -> ratio of C to H is 2:2, which reduces to 1:1 Benzene: C6H6 -> ratio of C to H is 6:6, which reduces to 1:1 b. Ethane: C2H6 -> ratio of C to H is 2:6, which reduces to 1:3 Butane: C4H10 -> ratio of C to H is 4:10, which reduces to 2:5 c. Nitrogen dioxide: NO2 -> ratio of N to O is 1:2 Dinitrogen tetroxide: N2O4 -> ratio of N to O is 2:4, which reduces to 1:2 d. Diphenyl ether: C12H10O -> ratio of C to H to O is 12:10:1, which reduces to 6:5:1 Phenol: C6H3OH -> ratio of C to H to O is 6:3:1, which reduces to 2:1:1
02

Compare the ratios of atoms in pairs of compounds

We will now compare the atomic ratios of different compounds to determine which pair has the same empirical formula. a. Acetylene (1:1) and Benzene (1:1) b. Ethane (1:3) and Butane (2:5) c. Nitrogen dioxide (1:2) and Dinitrogen tetroxide (1:2) d. Diphenyl ether (6:5:1) and Phenol (2:1:1) Based on our comparisons, the pairs with the same empirical formula are: a. Acetylene and Benzene c. Nitrogen dioxide and Dinitrogen tetroxide

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Formulas
Molecular formulas represent the actual number of each type of atom in a molecule of a compound. For example, benzene is written as \(\mathrm{C}_6\mathrm{H}_6\) which means each molecule contains six carbon atoms and six hydrogen atoms. Unlike empirical formulas, which depict the simplest integer ratio of atoms, molecular formulas show the true structure of the molecule, providing specific insight into the number of atoms involved.
  • Molecular formulas are essential for identifying the complete molecular structure.
  • They allow chemists to predict certain chemical and physical properties of the compound.
  • The molecular formula can often be determined from the empirical formula if the molar mass is known.
Understanding both molecular and empirical formulas is key to gaining comprehensive knowledge of the composition and characteristics of chemical compounds.
Mole Ratios
Mole ratios are a way to compare the proportions of elements in a chemical compound or reaction. They are derived from the coefficients of a balanced chemical equation or from the molecular or empirical formulas of a compound. These ratios are crucial for stoichiometry calculations and understanding how substances react.
In the context of our exercise, determining the mole ratio helps identify whether two compounds possess the same empirical formula. For example, acetylene \((\mathrm{C}_2\mathrm{H}_2)\) and benzene \((\mathrm{C}_6\mathrm{H}_6)\) both simplify to a 1:1 mole ratio of carbon to hydrogen, indicating the same empirical formula.
  • Mole ratios aid in determining empirical formulas from experimental data.
  • They are used in chemical calculations to find limiting reagents or the amount of product formed in a reaction.
  • Understanding mole ratios allows chemists to balance equations and predict outcomes of reactions.
Grasping this concept lays the foundation for various applications in chemistry, from laboratory practices to industrial processes.
Chemical Compounds
Chemical compounds are substances made up of two or more different types of atoms bonded together. They can be ionically or covalently bonded, forming a vast array of substances with distinct properties. Understanding chemical compounds involves knowing their formulas, the type of bond holding them together, and their properties.
In our exercise, each pair of compounds—such as acetylene \(\text{(C}_2\text{H}_2\text{)}\) and benzene \(\text{(C}_6\text{H}_6\text{)}\)—illustrate how different compounds can share the same empirical formula yet have vastly different structures and properties.
  • Compounds are usually represented by chemical formulas that show the composition.
  • These formulas describe fixed ratios and types of atoms.
  • The physical and chemical properties of compounds stem from the arrangement and types of atoms.
Understanding the nature and distinction of chemical compounds allows one to explore the intricate details and interactions that occur in chemical processes.
Atomic Ratios
Atomic ratios provide the simplest representation of a compound by showing the relative number of each type of atom present. This is the cornerstone for writing empirical formulas, which reduces the actual number of atoms in a molecule to the smallest whole number ratio.
For instance, both acetylene \(\text{(C}_2\text{H}_2\text{)}\) and benzene \(\text{(C}_6\text{H}_6\text{)}\) share an atomic ratio of carbon to hydrogen of 1:1. This commonality allows them to have the same empirical formula despite their different molecular compositions.
  • Empirical formulas are derived from atomic ratios.
  • Knowing these ratios is crucial for interpreting experimental data such as mass spectrometry results.
  • Atomic ratios play a key role in understanding chemical reactions and conservation of mass in chemistry.
Mastering atomic ratios enables learners to connect the dots between theoretical chemistry and practical applications, offering tools to decipher the compositions of unknown substances and predict reactions.

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Most popular questions from this chapter

A \(0.4230-\mathrm{g}\) sample of impure sodium nitrate was heated, converting all the sodium nitrate to \(0.2864 \mathrm{~g}\) of sodium nitrite and oxygen gas. Determine the percent of sodium nitrate in the oriainal sample.

Vitamin \(\mathrm{B}_{12}\), cyanocobalamin, is essential for human nutrition. It is concentrated in animal tissue but not in higher plants. Although nutritional requirements for the vitamin are quite low, people who abstain completely from animal products may develop a deficiency anemia. Cyanocobalamin is the form used in vitamin supplements. It contains \(4.34 \%\) cobalt by mass. Calculate the molar mass of cyanocobalamin, assuming that there is one atom of cobalt in every molecule of cyanocobalamin.

The space shuttle environmental control system handles excess \(\mathrm{CO}_{2}\) (which the astronauts breathe out; it is \(4.0 \%\) by mass of exhaled air) by reacting it with lithium hydroxide, LiOH. pellets to form lithium carbonate, \(\mathrm{Li}_{2} \mathrm{CO}_{3}\), and water. If there are seven astronauts on board the shuttle, and each exhales 20\. L of air per minute, how long could clean air be generated if there were \(25,000 \mathrm{~g}\) of \(\mathrm{LiOH}\) pellets available for each shuttle mission? Assume the density of air is \(0.0010 \mathrm{~g} / \mathrm{mL}\).

Chloral hydrate \(\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}_{3} \mathrm{O}_{2}\right)\) is a drug formerly used as a sedative and hypnotic. It is the compound used to make "Mickey Finns" in detective stories. a. Calculate the molar mass of chloral hydrate. b. What amount (moles) of \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}_{3} \mathrm{O}_{2}\) molecules are in \(500.0 \mathrm{~g}\) chloral hydrate? c. What is the mass in grams of \(2.0 \times 10^{-2}\) mole of chloral hydrate? d. What number of chlorine atoms are in \(5.0 \mathrm{~g}\) chloral hydrate? e. What mass of chloral hydrate would contain \(1.0 \mathrm{~g} \mathrm{Cl}\) ? f. What is the mass of exactly 500 molecules of chloral hydrate?

Elixirs such as Alka-Seltzer use the reaction of sodium bicarbonate with citric acid in aqueous solution to produce a fizz: \(3 \mathrm{NaHCO}_{3}(a q)+\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7}(a q) \longrightarrow\) $$ 3 \mathrm{CO}_{2}(g)+3 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Na}_{3} \mathrm{C}_{6} \mathrm{H}_{3} \mathrm{O}_{7}(a q) $$ a. What mass of \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7}\) should be used for every \(1.0 \times 10^{2}\) \(\mathrm{mg} \mathrm{NaHCO}_{3} ?\) b. What mass of \(\mathrm{CO}_{2}(\mathrm{~g})\) could be produced from such a mixture?

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