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Consider the pseudo-octahedral complex ion of \(\mathrm{Cr}^{3+}\), where \(\mathrm{A}\) and \(\mathrm{B}\) represent ligands. Ligand A produces a stronger crystal field than ligand B. Draw an appropriate crystal field diagram for this complex ion (assume the A ligands are on the \(z\) -axis).

Short Answer

Expert verified
To draw the crystal field energy diagram for the pseudo-octahedral complex ion of \(\mathrm{Cr}^{3+}\) with ligand A producing a stronger crystal field than ligand B, split the d-orbitals into two energy levels: the higher energy level for the \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals and the lower energy level for the \(d_{xy}\), \(d_{xz}\), and \(d_{yz}\) orbitals. Label the respective orbitals and indicate that the A ligands (stronger crystal field) are along the z-axis, while the B ligands (weaker crystal field) are along the x and y axes. The diagram should represent the influence of ligands A and B on the d-orbital energies for the complex ion.

Step by step solution

01

Recall Octahedral Crystal Field Splitting

In an octahedral crystal field splitting, the d-orbitals are split into two groups because of the interaction with the ligands. With ligands along the x, y, and z axes, the d-orbitals (\(d_{z^2}\) and \(d_{x^2-y^2}\)) along the axes will experience a higher energy than those (\(d_{xy}\), \(d_{xz}\), and \(d_{yz}\)) in between the axes. This leads to a splitting of the 5 d-orbitals into two sets - one with two orbitals (\(d_{z^2}\) and \(d_{x^2-y^2}\)) and the other with three orbitals (\(d_{xy}\), \(d_{xz}\), and \(d_{yz}\)).
02

Comparing the Two Ligands

Ligand A produces a stronger crystal field than ligand B meaning that the energy difference between d-orbitals along the z-axis and those in between the x and y axes is greater when A ligands are present along the z-axis. Thus, the order of energy for the d-orbitals would be \(d_{z^2}\) (and \(d_{x^2-y^2}) > d_{xz}\), \(d_{yz}\), \(d_{xy}\).
03

Draw the Crystal Field Diagram

To draw the crystal field energy diagram for this complex ion: 1. Draw two horizontal lines representing the two sets of energy levels, with the higher one for the \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals and the lower one for the \(d_{xy}\), \(d_{xz}\), and \(d_{yz}\) orbitals. 2. Label the two lines with the respective orbitals. 3. Indicate that the A ligands (stronger crystal field) are along the z-axis, and the B ligands (weaker crystal field) are along the x and y axes. The crystal field energy diagram represents the influence of ligands A and B on the d-orbital energies for the given pseudo-octahedral complex ion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Octahedral Complexes
In the realm of crystal field theory, an octahedral complex is a molecular architecture where six ligands symmetrically surround a central metal ion. This arrangement resembles an octahedron, a three-dimensional shape in geometry. Here, ligands interact with the metal ion, affecting the energy of its d-orbitals. Typically, the ligands align along the x, y, and z axes, creating two distinct groups of d-orbitals with different energy levels.
  • The ligands are placed symmetrically around the central metal ion.
  • The octahedral geometry leads to specific splitting of d-orbital energies.
It is essential to understand that the arrangement of ligands is crucial in determining how the d-orbitals will split. This is why in exercises like drawing a crystal field diagram, knowing the position of ligands helps predict d-orbital energies and visualize the splitting that occurs in an octahedral complex.
The Impact of Ligand Field Strength
Ligand field strength refers to the ability of a ligand to interact with and influence the central metal ion's d-orbitals in a complex. Ligands can be either strong or weak field ligands, based on their ability to cause d-orbital splitting.
  • Strong field ligands: These cause a more significant energy difference between different d-orbitals.
  • Weak field ligands: These induce a smaller energy difference.
In the case of the compound \(\mathrm{Cr}^{3+}\) with ligands A and B, ligand A is considered a stronger field ligand compared to ligand B. This means that the presence of A causes greater splitting and higher energy for the d-orbitals in line with its direction, in this case, the z-axis. Thus, understanding your specific ligands and their impact on field strength is critical in predicting how a metal complex will behave.
Exploring D-Orbital Splitting
D-orbital splitting is a key concept in understanding how ligands affect metal ions in a complex. In octahedral complexes, the d-orbitals split into two groups due to the interaction with ligands.
  • Higher Energy Level: The orbitals that lie directly along the axes (\(d_{z^2}\) and \(d_{x^2-y^2}\)) experience a greater repulsion and, thus, higher energy.
  • Lower Energy Level: The orbitals between the axes (\(d_{xy}\), \(d_{xz}\), and \(d_{yz}\)) experience less repulsion and lower energy.
In our example of a pseudo-octahedral complex, where ligand A offers a stronger field than B, greater splitting occurs in the \(d_{z^2}\) and \(d_{x^2-y^2}\) orbitals because these are aligned with the stronger field (z-axis). Creating a crystal field diagram helps visualize this energy level difference, reflecting the strength of the ligands' field.
Chromium Complexes and Their Properties
Chromium complexes, particularly those involving \(\mathrm{Cr}^{3+}\), exemplify the influence of crystal field theory in transition metals. Chromium, as a transition metal, has unfilled d-orbitals that engage with ligands, leading to the splitting of these orbitals.
Chromium complexes can exhibit various colors and properties depending on the ligands' field strength. Such variability is crucial since the color changes relate directly to the d-orbital splitting.
  • The types of ligands determine the color and magnetism of chromium complexes.
  • The specific splitting pattern impacts chemical reactivity, stability, and the complex's overall properties.
For the given \(\mathrm{Cr}^{3+}\) complex, understanding the differences in ligand strength not only assists in drawing accurate crystal field diagrams but also grants insight into the broader implications in physical and chemical contexts.

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Most popular questions from this chapter

Acetylacetone (see Exercise 43, part a), abbreviated acacH, is a bidentate ligand. It loses a proton and coordinates as acac-, as shown below: Acetylacetone reacts with an ethanol solution containing a salt of europium to give a compound that is \(40.1 \% \mathrm{C}\) and \(4.71 \% \mathrm{H}\) by mass. Combustion of \(0.286 \mathrm{~g}\) of the compound gives \(0.112\) \(\mathrm{g} \mathrm{Eu}_{2} \mathrm{O}_{3}\). Assuming the compound contains only \(\mathrm{C}, \mathrm{H}, \mathrm{O}\), and Eu, determine the formula of the compound formed from the reaction of acetylacetone and the europium salt. (Assume that the compound contains one europium ion.)

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Write electron configurations for each of the following. a. \(\mathrm{Cr}, \mathrm{Cr}^{2+}, \mathrm{Cr}^{3+}\) b. \(\mathrm{Cu}, \mathrm{Cu}^{+}, \mathrm{Cu}^{2+}\) c. \(\mathrm{V}, \mathrm{V}^{2+}, \mathrm{V}^{3+}\)

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