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Chapter 18: Problem 81

An electrochemical cell consists of a standard hydrogen electrode and a copper metal electrode. If the copper electrode is placed in a solution of \(0.10 \mathrm{M} \mathrm{NaOH}\) that is saturated with \(\mathrm{Cu}(\mathrm{OH})_{2}\), what is the cell potential at \(25^{\circ} \mathrm{C} ?\left[\mathrm{For} \mathrm{Cu}(\mathrm{OH})_{2}, K_{\mathrm{sp}}\right.\) \(\left.=1.6 \times 10^{-19} .\right]\)

Short Answer

Expert verified
The cell potential at \(25^{\circ} \mathrm{C}\) for the given electrochemical cell with a standard hydrogen electrode and a copper electrode in a \(0.10 \mathrm{M} \mathrm{NaOH}\) solution saturated with \(\mathrm{Cu}(\mathrm{OH})_{2}\) is approximately \(0.485 \mathrm{V}\).

Step by step solution

01

Write the balanced half-reactions

In order to calculate cell potential, the balanced half-reactions involving each electrode should be written. For the standard hydrogen electrode (SHE), the half-reaction is: \[\mathrm{2H^{+}(aq) + 2e^{-} \rightarrow H_{2}(g)}\] For the copper electrode, the half-reaction is: \[\mathrm{Cu^{2+}(aq) + 2e^{-} \rightarrow Cu(s)}\]
02

Calculate the concentration of Cu虏鈦� ions

To calculate the cell potential, we need to find the concentration of Cu虏鈦� ions in the solution. We have the equation \(\mathrm{Cu(OH)_2(s) \rightleftharpoons Cu^{2+}(aq) + 2 OH^{-}(aq)}\) and we know that Ksp = 1.6x10鈦宦光伖 and [OH鈦籡 = 0.10 M (from NaOH solution). We can write Ksp as: \[K_{sp} = [\mathrm{Cu^{2+}}][\mathrm{OH^{-}}]^{2}\] Replacing the known values, we get: \[\mathrm{1.6 \times 10^{-19} = [Cu^{2+}](0.10)^{2}}\] Now, we can solve for the concentration of Cu虏鈦� ions: \[[\mathrm{Cu^{2+}}] = \dfrac{1.6 \times 10^{-19}}{(0.10)^{2}} = 1.6 \times 10^{-17} \mathrm{M}\]
03

Determine the cell potential using the Nernst equation

Now that we know the concentration of Cu虏鈦� ions, we can use the Nernst equation to find the cell potential. The Nernst equation is given by: \[E_{cell} = E_{\circ} - \dfrac{0.0592}{n}\log Q\] Where \(E_{\circ}\) is the standard potential, n is the number of electrons transferred, and Q is the reaction quotient. For this cell, the standard potential is the difference between the standard reduction potentials of the Cu虏鈦�/Cu and H鈦�/H鈧� couple: \(E_{\circ} = E_{\circ}(\mathrm{Cu^{2+}/Cu}) - E_{\circ}(\mathrm{H^{+}/H_{2}}) = 0.34 \mathrm{V} - 0.00 \mathrm{V} = 0.34 \mathrm{V}\) As both half-reactions involve the exchange of 2 electrons, we have n=2. The reaction quotient Q can be written as: \[Q = \dfrac{[\mathrm{Cu^{2+}}]}{[\mathrm{H^{+}}]^{2}}\] Let's assume that the concentration of H鈦� ions is 1 M (neutral solution). Therefore, Q becomes: \[Q=\dfrac{1.6\times10^{-17}}{(1)^2}=1.6\times10^{-17}\] Now, we can plug in the values into the Nernst equation to find the cell potential: \[E_{cell} = 0.34 - \dfrac{0.0592}{2}\log(1.6\times10^{-17})\] \[E_{cell} \approx0.485 \mathrm{V}\] The cell potential at 25掳C is approximately 0.485 V.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Hydrogen Electrode
The standard hydrogen electrode (SHE) is a reference electrode used in electrochemistry to measure electrode potentials. It consists of a platinum electrode that is in contact with hydrogen gas at a pressure of 1 atmosphere and immersed in a solution with hydrogen ions at a concentration of 1 molar.
The half-reaction that takes place at the SHE can be written as:
  • \[\text{2H}^{+}(\text{aq}) + \text{2e}^{-} \rightarrow \text{H}_{2}(\text{g})\]
The SHE has a standard potential of 0.00 V, making it a benchmark for comparing the potential of other electrodes. Its consistent nature provides a stable basis for calculating cell potentials in electrochemical cells. This reference electrode plays a crucial role in determining the direction and magnitude of electron flow in an electrochemical reaction.
Nernst Equation
The Nernst equation is a fundamental formula used to calculate the cell potential of an electrochemical cell under non-standard conditions. It considers the effect of ion concentration on cell potential, providing a more accurate representation of real-world scenarios. The Nernst equation is given by:
  • \[E_{cell} = E_{\circ} - \dfrac{0.0592}{n}\log Q\]
Where:
  • \(E_{cell}\) = cell potential at non-standard conditions
  • \(E_{\circ}\) = standard cell potential
  • \(n\) = number of electrons exchanged
  • \(Q\) = reaction quotient
For the copper-hydrogen cell, the equation uses the known concentrations of ions to calculate the adjusted potential at 25掳C, providing insight into how concentration gradients affect cell behavior. This is especially important for understanding electrochemical reactions in real solutions.
Cell Potential
Cell potential, often described as electromotive force (emf), is a measure of the energy per charge available from an electrochemical cell. It defines the voltage difference between two electrodes and can be calculated using standard reduction potentials.
In our case, the copper half-cell and the hydrogen electrode contribute to the overall cell potential:
  • \[E_{\circ}(\text{Cu}^{2+}/\text{Cu}) = 0.34 \text{ V}\]
  • \[E_{\circ}(\text{H}^{+}/\text{H}_2) = 0.00 \text{ V}\]
The net standard cell potential \(E_{\circ}\) is thus determined by these values:
  • \[E_{\circ} = 0.34 \text{ V} - 0.00 \text{ V} = 0.34 \text{ V}\]
However, the real cell potential considers ion concentrations using the Nernst equation, resulting in a value of approximately 0.485 V. This cell potential reflects how the electron flow and setup conditions impact the overall performance of the electrochemical cell.
Copper Electrode
The copper electrode in an electrochemical cell plays a vital role as a component of the redox reaction. Copper typically functions as a cathode where reduction occurs. In this scenario, copper ions in solution (\[\text{Cu}^{2+}\]) are reduced to solid copper (\[\text{Cu(s)}\]), represented by the half-reaction:
  • \[\text{Cu}^{2+}(\text{aq}) + 2\text{e}^{-} \rightarrow \text{Cu}(\text{s})\]
The concentration of copper ions is determined using the solubility product, \(K_{sp}\), of copper hydroxide (\[\text{Cu(OH)}_2\]). Knowing the ion concentration is crucial to accurately compute the cell potential using the Nernst equation.
The interaction of the copper electrode with its solution environment highlights essential principles of electrochemistry, such as the relationship between ion concentration, electrode potential, and overall cell energy efficiency.

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Most popular questions from this chapter

The solubility product for \(\operatorname{CuI}(s)\) is \(1.1 \times 10^{-12}\). Calculate the value of \(\mathscr{E}^{\circ}\) for the half-reaction $$ \operatorname{CuI}(s)+\mathrm{e}^{-} \longrightarrow \mathrm{Cu}(s)+\mathrm{I}^{-}(a q) $$

A galvanic cell is based on the following half-reactions: $$ \begin{aligned} \mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Fe}(s) & \mathscr{E}^{\circ} &=-0.440 \mathrm{~V} \\ 2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_{2}(g) & \mathscr{E}^{\circ} &=0.000 \mathrm{~V} \end{aligned} $$ where the iron compartment contains an iron electrode and \(\left[\mathrm{Fe}^{2+}\right]=1.00 \times 10^{-3} M\) and the hydrogen compartmentcontains a platinum electrode, \(P_{\mathrm{H}_{2}}=1.00 \mathrm{~atm}\), and a weak acid, HA, at an initial concentration of \(1.00 M .\) If the observed cell potential is \(0.333 \mathrm{~V}\) at \(25^{\circ} \mathrm{C}\), calculate the \(K_{\mathrm{a}}\) value for the weak acid HA.

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A solution containing \(\mathrm{Pt}^{4+}\) is electrolyzed with a current of \(4.00 \mathrm{~A}\). How long will it take to plate out \(99 \%\) of the platinum in \(0.50 \mathrm{~L}\) of a \(0.010-M\) solution of \(\mathrm{Pt}^{4+}\) ?
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