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Consider the reaction $$ \mathrm{Fe}^{3+}(a q)+\mathrm{SCN}^{-}(a q) \rightleftharpoons \mathrm{FeSCN}^{2+}(a q) $$ How will the equilibrium position shift if a. water is added, doubling the volume? b. \(\mathrm{AgNO}_{3}(a q)\) is added? (AgSCN is insoluble.) c. \(\mathrm{NaOH}(a q)\) is added? \(\left[\mathrm{Fe}(\mathrm{OH})_{3}\right.\) is insoluble.] d. \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}(a q)\) is added?

Short Answer

Expert verified
a. The equilibrium position will shift to the right, favoring the formation of FeSCN虏鈦, due to the decrease in concentrations caused by the addition of water. b. The equilibrium position will shift to the left, favoring the formation of Fe鲁鈦 and SCN鈦 ions, due to the removal of SCN鈦 ions by the formation of insoluble AgSCN. c. The equilibrium position will shift to the left, favoring the formation of Fe鲁鈦 and SCN鈦 ions, due to the removal of Fe鲁鈦 ions by the formation of insoluble Fe(OH)鈧. d. The equilibrium position will shift to the right, favoring the formation of FeSCN虏鈦, due to the increase in Fe鲁鈦 concentration caused by the addition of Fe(NO鈧)鈧.

Step by step solution

01

Addition of Water

When water is added, the volume of the solution is doubled. This results in the concentrations of all dissolved species being halved. According to Le Ch芒telier's principle, the equilibrium will shift in the direction where the concentration of the species is increased. In this case, the reaction will shift to the right (favoring the formation of FeSCN虏鈦) to restore the original concentrations of the reactants and products. #b. Addition of AgNO3#
02

Addition of AgNO3

When AgNO3(aq) is added to the solution, Ag鈦(aq) ions in AgNO3 will react with SCN鈦(aq) ions to form insoluble AgSCN(s). This effectively removes SCN鈦 from the solution, causing a decrease in its concentration. According to Le Ch芒telier's principle, the reaction will shift to the left (favoring the formation of Fe鲁鈦 and SCN鈦 ions) to counteract the decrease in SCN鈦 concentration. #c. Addition of NaOH#
03

Addition of NaOH

When NaOH(aq) is added to the solution, OH鈦(aq) ions in NaOH will react with Fe鲁鈦(aq) ions to form insoluble Fe(OH)鈧(s). This effectively removes Fe鲁鈦 from the solution, causing a decrease in its concentration. According to Le Ch芒telier's principle, the reaction will shift to the left (favoring the formation of Fe鲁鈦 and SCN鈦 ions) to counteract the decrease in Fe鲁鈦 concentration. #d. Addition of Fe(NO3)3#
04

Addition of Fe(NO3)3

When Fe(NO3)3(aq) is added to the solution, it will increase the concentration of Fe鲁鈦 ions. According to Le Ch芒telier's principle, the reaction will shift to the right (favoring the formation of FeSCN虏鈦) to counteract the increase in Fe鲁鈦 concentration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Le Ch芒telier's Principle
Le Ch芒telier's Principle is a fundamental concept in chemical equilibrium. It states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change. This principle helps us predict how the balance of reactants and products will react to various changes.
For instance, if a reaction in equilibrium is exposed to a change in concentration, temperature, or pressure, the system adjusts itself. It does so in a way to "undo" the disturbance as much as possible.
Here are some key takeaways when applying Le Ch芒telier's Principle:
  • If the concentration of a reactant or product is increased, the system shifts to consume more of it.
  • If the concentration is decreased, the system shifts to produce more of that substance.
  • Remember that the principle helps predict the direction of the shift but not the extent of it.
Equilibrium Shifts
Equilibrium shifts refer to the movement of a chemical reaction's balance. This movement is in response to changes in conditions like concentration, temperature, or pressure. When equilibrium shifts, it does so to favor either the formation of products or reactants.
To illustrate:
Adding a substance that reacts with one of the present compounds will cause the equilibrium to shift. For instance, adding a compound that removes a reactant will shift the equilibrium towards forming more reactants. Conversely, adding a substance that increases the concentration of a current reactant will shift the equilibrium toward product formation.
In summary, equilibrium shifts serve to restore balance under new conditions.
Solubility
Solubility is an essential concept when understanding chemical reactions in solutions. It refers to the extent to which a solute can dissolve in a solvent at a given temperature.
The solubility of a substance can significantly influence the equilibrium of a reaction:
  • Insoluble compounds precipitate out, removing specific ions from the solution.
  • This removal causes shifts in equilibrium to replace the removed ions.
For instance, when an insoluble compound forms, like AgSCN from Ag鈦 and SCN鈦, it reduces the concentration of SCN鈦 ions, thus affecting equilibrium.
Reaction Dynamics
Reaction dynamics explore how different factors influence the speed and equilibrium of chemical reactions. These include concentration, temperature, pressure, and the presence of catalysts.
For example, when a catalyst is added to a reaction mixture, it speeds up both the forward and reverse reactions equally. However, it does not alter the position of the equilibrium.
Dynamics also dictate that even without equilibrium changes, altering conditions like concentration can temporarily speed up or slow down a reaction. Systems then adjust to achieve a new equilibrium state.
Understanding these dynamics allows chemists to control and optimize reactions efficiently.

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Most popular questions from this chapter

What will happen to the number of moles of \(\mathrm{SO}_{3}\) in equilibrium with \(\mathrm{SO}_{2}\) and \(\mathrm{O}_{2}\) in the reaction $$ 2 \mathrm{SO}_{3}(g) \rightleftharpoons 2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) $$ in each of the following cases? a. Oxygen gas is added. b. The pressure is increased by decreasing the volume of the reaction container. c. In a rigid reaction container, the pressure is increased by adding argon gas. d. The temperature is decreased (the reaction is endothermic). e. Gaseous sulfur dioxide is removed.

Consider the following reaction at a certain temperature: $$ 4 \mathrm{Fe}(s)+3 \mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{Fe}_{2} \mathrm{O}_{3}(s) $$ An equilibrium mixture contains \(1.0\) mole of \(\mathrm{Fe}, 1.0 \times 10^{-3}\) mole of \(\mathrm{O}_{2}\), and \(2.0\) moles of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) all in a \(2.0-\mathrm{L}\) container. Calculate the value of \(K\) for this reaction.

The equilibrium constant \(K_{\mathrm{p}}\) for the reaction $$ \mathrm{CCl}_{4}(g) \rightleftharpoons \mathrm{C}(s)+2 \mathrm{Cl}_{2}(g) $$ at \(700^{\circ} \mathrm{C}\) is \(0.76 .\) Detemine the initial pressure of carbon tetrachloride that will produce a total equilibrium pressure of \(1.20 \mathrm{~atm}\) at \(700^{\circ} \mathrm{C}\).

Ammonia is produced by the Haber process, in which nitrogen and hydrogen are reacted directly using an iron mesh impregnated with oxides as a catalyst. For the reaction $$ \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g) $$ equilibrium constants ( \(K_{\mathrm{p}}\) values) as a function of temperature are \(300^{\circ} \mathrm{C}, \quad 4.34 \times 10^{-3}\) \(500^{\circ} \mathrm{C}, \quad 1.45 \times 10^{-5}\) \(600^{\circ} \mathrm{C}, \quad 2.25 \times 10^{-6}\) Is the reaction exothermic or endothermic?

At \(25^{\circ} \mathrm{C}, K_{\mathrm{p}}=5.3 \times 10^{5}\) for the reaction $$ \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g) $$ When a certain partial pressure of \(\mathrm{NH}_{3}(g)\) is put into an otherwise empty rigid vessel at \(25^{\circ} \mathrm{C}\), equilibrium is reached when \(50.0 \%\) of the original ammonia has decomposed. What was the original partial pressure of ammonia before any decomposition occurred?

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