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Give three ions that are isoelectronic with neon. Place these ions in order of increasing size.

Short Answer

Expert verified
The three ions that are isoelectronic with neon are fluoride ion (F鈦), sodium ion (Na鈦), and magnesium ion (Mg虏鈦). The order of increasing size for these ions is F鈦 > Na鈦 > Mg虏鈦.

Step by step solution

01

Find the electron configuration of neon

Neon is a noble gas with atomic number 10, which means it has 10 electrons in its neutral state 鈥 two in the first shell and 8 in the second shell. Therefore, its electron configuration is 1s虏2s虏2p鈦.
02

Identify ions with the same number of electrons

We need to find ions that have the same number of electrons (10) as neon. To do this, we can identify ions that have gained or lost electrons compared to their neutral state. Three such ions are: 1. Fluoride ion (F鈦): Gained 1 electron; atomic number 9 2. Sodium ion (Na鈦): Lost 1 electron; atomic number 11 3. Magnesium ion (Mg虏鈦): Lost 2 electrons; atomic number 12 All three ions have 10 electrons, just like neon.
03

Arrange the ions in order of increasing size

Since all three ions have the same number of electrons, their size will depend on the effective nuclear charge experienced by the outermost electrons. Here, atomic number plays a role: 1. F鈦: 9 protons, 10 electrons 2. Na鈦: 11 protons, 10 electrons 3. Mg虏鈦: 12 protons, 10 electrons Effective nuclear charge is calculated by subtracting the shielding effect due to inner shells from the total number of protons. Since all three ions have the same number of inner-shell electrons, we can use the atomic numbers to determine the order of increasing effective nuclear charge: F鈦 (9 protons) < Na鈦 (11 protons) < Mg虏鈦 (12 protons) Outer electrons are attracted more strongly to the nucleus as the effective nuclear charge increases. As the attractive force increases, the atomic size (ion radii) decreases. Therefore, the order of increasing size is: F鈦 > Na鈦 > Mg虏鈦

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Most popular questions from this chapter

Use the following standard enthalpies of formation to estimate the \(\mathrm{N}-\mathrm{H}\) bond energy in ammonia: \(\mathrm{N}(\mathrm{g}), 472.7 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{H}(\mathrm{g})\), \(216.0 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{NH}_{3}(g),-46.1 \mathrm{~kJ} / \mathrm{mol}\). Compare your value to the one in Table \(8.4\).

Which compound in each of the following pairs of ionic substances has the most exothermic lattice energy? Justify your answers. a. \(\mathrm{NaCl}, \mathrm{KCl}\) b. \(\mathrm{LiF}, \mathrm{LiCl}\) c. \(\mathrm{Mg}(\mathrm{OH})_{2}, \mathrm{MgO}\) d. \(\mathrm{Fe}(\mathrm{OH})_{2}, \mathrm{Fe}(\mathrm{OH})_{3}\) e. \(\mathrm{NaCl}, \mathrm{Na}_{2} \mathrm{O}\) f. \(\mathrm{MgO}, \mathrm{BaS}\)

Which of the following statements is(are) true? Correct the false statements. a. It is impossible to satisfy the octet rule for all atoms in \(\mathrm{XeF}_{2}\). b. Because \(\mathrm{SF}_{4}\) exists, \(\mathrm{OF}_{4}\) should also exist because oxygen is in the same family as sulfur. c. The bond in \(\mathrm{NO}^{+}\) should be stronger than the bond in \(\mathrm{NO}^{-}\). d. As predicted from the two Lewis structures for ozone, one oxygen-oxygen bond is stronger than the other oxygenoxygen bond.

Write Lewis structures that obey the octet rule (duet rule for \(\mathrm{H}\) ) for each of the following molecules. a. \(\mathrm{H}_{2} \mathrm{CO}\) b. \(\mathrm{CO}_{2}\) c. HCN Except for \(\mathrm{HCN}\) and \(\mathrm{H}_{2} \mathrm{CO}\), the first atom listed is the central atom. For \(\mathrm{HCN}\) and \(\mathrm{H}_{2} \mathrm{CO}\), carbon is the central atom. Carbon is the central atom in all of these molecules.

Look up the energies for the bonds in \(\mathrm{CO}\) and \(\mathrm{N}_{2}\). Although the bond in \(\mathrm{CO}\) is stronger, \(\mathrm{CO}\) is considerably more reactive than \(\mathrm{N}_{2}\). Give a possible explanation.

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