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Give three ions that are isoelectronic with neon. Place these ions in order of increasing size.

Short Answer

Expert verified
The three ions that are isoelectronic with neon are fluoride ion (F鈦), sodium ion (Na鈦), and magnesium ion (Mg虏鈦). The order of increasing size for these ions is F鈦 > Na鈦 > Mg虏鈦.

Step by step solution

01

Find the electron configuration of neon

Neon is a noble gas with atomic number 10, which means it has 10 electrons in its neutral state 鈥 two in the first shell and 8 in the second shell. Therefore, its electron configuration is 1s虏2s虏2p鈦.
02

Identify ions with the same number of electrons

We need to find ions that have the same number of electrons (10) as neon. To do this, we can identify ions that have gained or lost electrons compared to their neutral state. Three such ions are: 1. Fluoride ion (F鈦): Gained 1 electron; atomic number 9 2. Sodium ion (Na鈦): Lost 1 electron; atomic number 11 3. Magnesium ion (Mg虏鈦): Lost 2 electrons; atomic number 12 All three ions have 10 electrons, just like neon.
03

Arrange the ions in order of increasing size

Since all three ions have the same number of electrons, their size will depend on the effective nuclear charge experienced by the outermost electrons. Here, atomic number plays a role: 1. F鈦: 9 protons, 10 electrons 2. Na鈦: 11 protons, 10 electrons 3. Mg虏鈦: 12 protons, 10 electrons Effective nuclear charge is calculated by subtracting the shielding effect due to inner shells from the total number of protons. Since all three ions have the same number of inner-shell electrons, we can use the atomic numbers to determine the order of increasing effective nuclear charge: F鈦 (9 protons) < Na鈦 (11 protons) < Mg虏鈦 (12 protons) Outer electrons are attracted more strongly to the nucleus as the effective nuclear charge increases. As the attractive force increases, the atomic size (ion radii) decreases. Therefore, the order of increasing size is: F鈦 > Na鈦 > Mg虏鈦

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Most popular questions from this chapter

Nitrous oxide \(\left(\mathrm{N}_{2} \mathrm{O}\right)\) has three possible Lewis structures: Given the following bond lengths, $$ \begin{array}{llll} \mathrm{N}-\mathrm{N} & 167 \mathrm{pm} & \mathrm{N}=\mathrm{O} & 115 \mathrm{pm} \\ \mathrm{N}=\mathrm{N} & 120 \mathrm{pm} & \mathrm{N}-\mathrm{O} & 147 \mathrm{pm} \\ \mathrm{N} \equiv \mathrm{N} & 110 \mathrm{pm} & & \end{array} $$ rationalize the observations that the \(\mathrm{N}-\mathrm{N}\) bond length in \(\mathrm{N}_{2} \mathrm{O}\) is \(112 \mathrm{pm}\) and that the \(\mathrm{N}-\mathrm{O}\) bond length is \(119 \mathrm{pm}\). Assign formal charges to the resonance structures for \(\mathrm{N}_{2} \mathrm{O}\). Can you eliminate any of the resonance structures on the basis of formal charges? Is this consistent with observation?

Which of the following statements is(are) true? Correct the false statements. a. The molecules \(\mathrm{SeS}_{3}, \mathrm{SeS}_{2}, \mathrm{PCl}_{5}, \mathrm{TeCl}_{4}, \mathrm{ICl}_{3}\), and \(\mathrm{XeCl}_{2}\) all exhibit at least one bond angle which is approximately \(120^{\circ}\) b. The bond angle in \(\mathrm{SO}_{2}\) should be similar to the bond angle in \(\mathrm{CS}_{2}\) or \(\mathrm{SCl}_{2}\) c. Of the compounds \(\mathrm{CF}_{4}, \mathrm{KrF}_{4}\), and \(\mathrm{SeF}_{4}\), only \(\mathrm{SeF}_{4}\) exhibits an overall dipole moment (is polar). d. Central atoms in a molecule adopt a geometry of the bonded atoms and lone pairs about the central atom in order to maximize electron repulsions.

Give an example of an ionic compound where both the anion and the cation are isoelectronic with each of the following noble gases. a. Ne c. \(\mathrm{Kr}\) b. \(\mathrm{Ar}\) d. Xe

Which of the following statements is(are) true? Correct the false statements. a. It is impossible to satisfy the octet rule for all atoms in \(\mathrm{XeF}_{2}\). b. Because \(\mathrm{SF}_{4}\) exists, \(\mathrm{OF}_{4}\) should also exist because oxygen is in the same family as sulfur. c. The bond in \(\mathrm{NO}^{+}\) should be stronger than the bond in \(\mathrm{NO}^{-}\). d. As predicted from the two Lewis structures for ozone, one oxygen-oxygen bond is stronger than the other oxygenoxygen bond.

Without using Fig. \(8.3\), predict the order of increasing electronegativity in each of the following groups of elements. a. \(\mathrm{C}, \mathrm{N}, \mathrm{O}\) c. \(\mathrm{Si}, \mathrm{Ge}, \mathrm{Sn}\) b. \(\mathrm{S}, \mathrm{Se}, \mathrm{Cl}\) d. Tl, S, Ge

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