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Without using Fig. \(8.3\), predict the order of increasing electronegativity in each of the following groups of elements. a. \(\mathrm{Na}, \mathrm{K}, \mathrm{Rb}\) c. \(\mathrm{F}, \mathrm{Cl}, \mathrm{Br}\) b. \(\mathrm{B}, \mathrm{O}, \mathrm{Ga}\) d. \(\mathrm{S}, \mathrm{O}, \mathrm{F}\)

Short Answer

Expert verified
a. Rb < K < Na b. Br < Cl < F c. Ga < B < O d. S < O < F

Step by step solution

01

a. Na, K, Rb

These elements are alkali metals (group 1) in the periodic table. As we move down the group, the electronegativity decreases. So the order of increasing electronegativity is: Rb < K < Na.
02

b. F, Cl, Br

These elements are halogens (group 17) in the periodic table. Similar to group 1 elements, the electronegativity decreases as we move down the group. Therefore, the order of increasing electronegativity is: Br < Cl < F.
03

c. B, O, Ga

Here, the elements are from different groups. B is from group 13, O is from group 16, and Ga is also from group 13. As we move across a period from left to right, electronegativity increases, and as we move down a group, electronegativity decreases. So the order of increasing electronegativity is: Ga < B < O.
04

d. S, O, F

In this group, S is from group 16, O is also from group 16, and F is from group 17. As we move across a period from left to right, electronegativity increases, and within the same group, it decreases as we move down. Therefore, the order of increasing electronegativity is: S < O < F.

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