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The elements \(\mathrm{Cu}, \mathrm{O}, \mathrm{La}, \mathrm{Y}, \mathrm{Ba}, \mathrm{Tl}\), and \(\mathrm{Bi}\) are all found in high- temperature ceramic superconductors. Write the expected electron configuration for these atoms.

Short Answer

Expert verified
The electron configurations for the given elements are: 1. Cu (Copper): \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1\) 2. O (Oxygen): \(1s^2 2s^2 2p^4\) 3. La (Lanthanum): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^1 5d^1\) 4. Y (Yttrium): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^1\) 5. Ba (Barium): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2\) 6. Tl (Thallium): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^1\) 7. Bi (Bismuth): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^{10} 6p^3\)

Step by step solution

01

Find atomic numbers of the given elements

Using the periodic table, find the atomic numbers (number of electrons) for the elements: - Cu (Copper) has atomic number 29 - O (Oxygen) has atomic number 8 - La (Lanthanum) has atomic number 57 - Y (Yttrium) has atomic number 39 - Ba (Barium) has atomic number 56 - Tl (Thallium) has atomic number 81 - Bi (Bismuth) has atomic number 83
02

Determine electron configurations

Now that we have the atomic numbers, we can build the electron configurations by filling the orbitals in order of increasing energy. 1. For Cu (Copper, atomic number 29): 1s虏 2s虏 2p鈦 3s虏 3p鈦 3d鹿鈦 4s鹿 2. For O (Oxygen, atomic number 8): 1s虏 2s虏 2p鈦 3. For La (Lanthanum, atomic number 57): 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 4f鹿 5d鹿 4. For Y (Yttrium, atomic number 39): 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿 5. For Ba (Barium, atomic number 56): 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 6. For Tl (Thallium, atomic number 81): 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 4f鹿鈦 5d鹿鈦 6p鹿 7. For Bi (Bismuth, atomic number 83): 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 4f鹿鈦 5d鹿鈦 6p鲁

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Number
The concept of the atomic number is fundamentally important in chemistry and physics. It is the number of protons found in the nucleus of an atom and is represented by the symbol 'Z'. The atomic number uniquely identifies a chemical element and determines its position in the periodic table. Because atoms are electrically neutral, the number of protons (which are positively charged) is equal to the number of electrons (which are negatively charged), under normal circumstances. This makes the atomic number also the number of electrons in an atom when it is not an ion. It's the electron configuration that directly influences the atom's chemical properties, which is why it's crucial to understand the atomic number when solving problems regarding electron configuration.

For instance, Copper (Cu) has an atomic number of 29, reflecting its 29 protons and, when neutral, 29 electrons. Knowing the atomic number, we can proceed to write the expected electron arrangement by filling in the orbitals according to their energy levels, as they increase.
Periodic Table
The periodic table is a tabular display of chemical elements, ordered by their atomic number, electron configuration, and recurring chemical properties. Elements are listed in rows called periods and columns called groups. As you navigate the periodic table, each row indicates a new shell of electrons appearing in the electron cloud of the atom.

This organization helps predict the properties of elements and their compounds. For example, elements that fall into the same group often have similar properties, such as the noble gases which are known for their inertness. When tasked with writing the electron configurations for elements like Oxygen or Lanthanum, the periodic table enables us to understand these elements' relationships and chemical behaviors based on their positions.
Orbital Energy Levels

Understanding Orbital Energy Levels

Orbital energy levels are the various regions around the nucleus where electrons are likely to be found. These are organized into principal energy levels, sublevels, and orbitals, and they fill with electrons in a pattern based on increasing energy 鈥 often referred to as the 'Aufbau principle'.

The principal energy levels are numbered 1, 2, 3, and so on, which correspond to the periods in the periodic table. Each energy level can hold a specific number of electrons: the first level can hold up to 2 electrons, the second up to 8, and so on. These levels are further divided into sublevels designated as s, p, d, and f. As you write electron configurations, like those for the elements found in high-temperature ceramic superconductors, following this pattern ensures you fill the orbitals correctly.
Superconductors
Superconductors are materials that can conduct electricity without resistance when they are cooled below a certain temperature. This means they can carry an electric current indefinitely without losing any energy. Superconductors are critical components in various high-technology applications, including MRI machines, maglev trains, and in particle accelerators. High-temperature superconductors, like those containing elements such as Yttrium, Barium, and Copper, have particularly fascinating electron configurations which enable superconductivity at temperatures higher than those of conventional superconductors.

The study of electron configurations in these elements helps scientists to understand and potentially discover new superconducting materials with practical and energy-efficient applications. For example, the unique electron configuration in Bismuth, Bi (atomic number 83), is imperative to its role in superconducting materials.

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Most popular questions from this chapter

The electron affinities of the elements from aluminum to chlorine are \(-44,-120,-74,-200.4\), and \(-384.7 \mathrm{~kJ} / \mathrm{mol}\), respectively. Rationalize the trend in these values.

An ionic compound of potassium and oxygen has the empirical formula KO. Would you expect this compound to be potassium(II) oxide or potassium peroxide? Explain.

An electron is excited from the \(n=1\) ground state to the \(n=3\) state in a hydrogen atom. Which of the following statements are true? Correct the false statements to make them true. a. It takes more energy to ionize (completely remove) the electron from \(n=3\) than from the ground state. b. The electron is farther from the nucleus on average in the \(n=3\) state than in the \(n=1\) state. c. The wavelength of light emitted if the electron drops from \(n=3\) to \(n=2\) will be shorter than the wavelength of light emitted if the electron falls from \(n=3\) to \(n=1\). d. The wavelength of light emitted when the electron returns to the ground state from \(n=3\) will be the same as the wavelength of light absorbed to go from \(n=1\) to \(n=3\). e. For \(n=3\), the electron is in the first excited state.

One of the emission spectral lines for \(\mathrm{Be}^{3+}\) has a wavelength of \(253.4 \mathrm{~nm}\) for an electronic transition that begins in the state with \(n=5 .\) What is the principal quantum number of the lowerenergy state corresponding to this emission? (Hint: The Bohr model can be applied to one- electron ions. Don't forget the \(Z\) factor: \(Z=\) nuclear charge \(=\) atomic number. \()\)

Photosynthesis uses \(660-\mathrm{nm}\) light to convert \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) into glucose and \(\mathrm{O}_{2}\). Calculate the frequency of this light.

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