/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 A photon of ultraviolet (UV) lig... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 7: Problem 40

A photon of ultraviolet (UV) light possesses enough energy to mutate a strand of human DNA. What is the energy of a single UV photon and a mole of UV photons having a wavelength of \(25 \mathrm{~nm} ?\)

Short Answer

Expert verified
The energy of a single UV photon with a wavelength of \(25 nm\) is approximately \(7.97 脳 10^{-19} J\), and the energy of a mole of UV photons is approximately \(4.80 脳 10^5 J\).

Step by step solution

01

Convert the wavelength to meters

First, we need to convert the wavelength from nanometers (nm) to meters (m) since the other constants are in SI units. We know that 1 nm is equal to 1 脳 10^-9 m. So, we can convert the given wavelength as follows: \( \lambda = 25 ~nm * \frac{1 脳 10^{-9} ~m}{1 ~nm} = 25 脳 10^{-9} ~m \)
02

Calculate the energy of a single photon

Now, we can plug in the values for Planck's constant (h), the speed of light (c), and the wavelength (位) into the equation E = h * (c / 位) to find the energy of a single photon. Planck's constant (h) = 6.626 脳 10^-34 Js Speed of light (c) = 3.00 脳 10^8 m/s \( E = 6.626 脳 10^{-34} ~Js * \frac{3.00 脳 10^8 ~m/s}{25 脳 10^{-9} ~m} \) Solve for E: \( E 鈮� 7.97 脳 10^{-19} ~J \) So, the energy of a single UV photon is approximately 7.97 脳 10^-19 J.
03

Calculate the energy of a mole of photons

Now, we will find the energy of a mole of photons by multiplying the energy of a single photon by Avogadro's number (6.022 x 10^23). \( Energy~of~a~mole~of~photons = E 脳 Avogadro's~number \) \( Energy~of~a~mole~of~photons = 7.97 脳 10^{-19} ~J 脳 6.022 脳 10^{23}~photon^{-1} \) Solve for the total energy: \( Energy~of~a~mole~of~photons 鈮� 4.80 脳 10^5~J \) So, the energy of a mole of UV photons is approximately 4.80 脳 10^5 J.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Element 106 has been named seaborgium, \(\mathrm{Sg}\), in honor of Glenn Seaborg, discoverer of the first transuranium element. a. Write the expected electron configuration for element 106 . b. What other element would be most like element 106 in its properties? c. Write the formula for a possible oxide and a possible oxyanion of element 106 .

Arrange the following groups of atoms in order of increasing size. a. \(\mathrm{Te}, \mathrm{S}, \mathrm{Se}\) b. \(\mathrm{K}, \mathrm{Br}, \mathrm{Ni}\) c. \(\mathrm{Ba}, \mathrm{Si}, \mathrm{F}\)

Assume that we are in another universe with different physical laws. Electrons in this universe are described by four quantum numbers with meanings similar to those we use. We will call these quantum numbers \(p, q, r\), and \(s .\) The rules for these quantum numbers are as follows: \(p=1,2,3,4,5, \ldots\) \(q\) takes on positive odd integers and \(q \leq p\) \(r\) takes on all even integer values from \(-q\) to \(+q\). (Zero is considered an even number.) \(s=+\frac{1}{2}\) or \(-\frac{1}{2}\) a. Sketch what the first four periods of the periodic table will look like in this universe. b. Wh?t are the atomic numbers of the first four elements you would expect to be least reactive? c. Give an example, using elements in the forst four rows, of ionic compounds with the formulas \(\mathrm{XY}, \mathrm{XY}_{2}, \mathrm{X}_{2} \mathrm{Y}, \mathrm{XY}_{3}\), and \(\mathrm{X}_{2} \mathrm{Y}_{3}\) d. How many electrons can have \(p=4, q=3 ?\) e. How many electrons can have \(p=3, q=0, r=0 ?\) f. How many electrons can have \(p=6\) ?

In the ground state of element 115, Uup, a. how many electrons have \(n=5\) as one of their quantum numbers? b. how many electrons have \(\ell=3\) as one of their quantum numbers? c. how many electrons have \(m_{\ell}=1\) as one of their quantum numbers? d. how many electrons have \(m_{s}=-\frac{1}{2}\) as one of their quantum numbers?

Cesium was discovered in natural mineral waters in 1860 by R. W. Bunsen and G. R. Kirchhoff using the spectroscope they invented in \(1859 .\) The name came from the Latin caesius ("sky blue") because of the prominent blue line observed for this element at \(455.5 \mathrm{~nm} .\) Calculate the frequency and energy of a photon of this light.
See all solutions

Recommended explanations on Chemistry Textbooks

Inorganic Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation

The Earths Atmosphere

Read Explanation

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.