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Write net ionic equations for the reaction, if any, that occurs when aqueous solutions of the following are mixed. a. ammonium sulfate and barium nitrate b. lead(II) nitrate and sodium chloride c. sodium phosphate and potassium nitrate d. sodium bromide and rubidium chloride e. copper(II) chloride and sodium hydroxide

Short Answer

Expert verified
a. \(Ba^{2+} (aq) + SO_4^{2-} (aq) 鈫 BaSO_4 (s)\) b. \(Pb^{2+} (aq) + 2 Cl^- (aq) 鈫 PbCl_2 (s)\) c. No reaction d. No reaction e. \(Cu^{2+} (aq) + 2 OH^- (aq) 鈫 Cu(OH)_2 (s)\)

Step by step solution

01

a. Ammonium sulfate and barium nitrate

Start by writing the reactants and products of the possible double replacement reaction: (Ammonium ion: NH鈧勨伜, Sulfate ion: SO鈧劼测伝, Barium ion: Ba虏鈦, Nitrate ion: NO鈧冣伝) NH鈧勨倐SO鈧 (aq) + Ba(NO鈧)鈧 (aq) 鈫 2 NH鈧凬O鈧 (aq) + BaSO鈧 (s) Since barium sulfate is insoluble, a reaction occurs. Now, write the net ionic equation by omitting the spectator ions (NH鈧勨伜 and NO鈧冣伝): Ba虏鈦 (aq) + SO鈧劼测伝 (aq) 鈫 BaSO鈧 (s)
02

b. Lead(II) nitrate and sodium chloride

Write the reactants and products of the possible double replacement reaction: (Lead(II) ion: Pb虏鈦, Nitrate ion: NO鈧冣伝, Sodium ion: Na鈦, Chloride ion: Cl鈦) Pb(NO鈧)鈧 (aq) + 2 NaCl (aq) 鈫 2 NaNO鈧 (aq) + PbCl鈧 (s) Since lead(II) chloride is insoluble, a reaction occurs. Write the net ionic equation by omitting the spectator ions (NO鈧冣伝 and Na鈦): Pb虏鈦 (aq) + 2 Cl鈦 (aq) 鈫 PbCl鈧 (s)
03

c. Sodium phosphate and potassium nitrate

Write the reactants and products of the possible double replacement reaction: (Sodium ion: Na鈦, Phosphate ion: PO鈧劼斥伝, Potassium ion: K鈦, Nitrate ion: NO鈧冣伝) Na鈧働O鈧 (aq) + 3 KNO鈧 (aq) 鈫 3 NaNO鈧 (aq) + K鈧働O鈧 (aq) Since all the compounds are soluble, no reaction occurs, and no net ionic equation needs to be written.
04

d. Sodium bromide and rubidium chloride

Write the reactants and products of the possible double replacement reaction: (Sodium ion: Na鈦, Bromide ion: Br鈦, Rubidium ion: Rb鈦, Chloride ion: Cl鈦) NaBr (aq) + RbCl (aq) 鈫 NaCl (aq) + RbBr (aq) Since all the compounds are soluble, no reaction occurs, and no net ionic equation needs to be written.
05

e. Copper(II) chloride and sodium hydroxide

Write the reactants and products of the possible double replacement reaction: (Copper(II) ion: Cu虏鈦, Chloride ion: Cl鈦, Sodium ion: Na鈦, Hydroxide ion: OH鈦) CuCl鈧 (aq) + 2 NaOH (aq) 鈫 2 NaCl (aq) + Cu(OH)鈧 (s) Since copper(II) hydroxide is insoluble, a reaction occurs. Write the net ionic equation by omitting the spectator ions (Na鈦 and Cl鈦): Cu虏鈦 (aq) + 2 OH鈦 (aq) 鈫 Cu(OH)鈧 (s)

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Most popular questions from this chapter

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