/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 123 Adipic acid is an organic compou... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Adipic acid is an organic compound composed of \(49.31 \% \mathrm{C}\). \(43.79 \% \mathrm{O}\), and the rest hydrogen. If the molar mass of adipic acid is \(146.1 \mathrm{~g} / \mathrm{mol}\), what are the empirical and molecular formulas for adipic acid?

Short Answer

Expert verified
The empirical formula of adipic acid is C3H5O2 and the molecular formula is C6H10O4.

Step by step solution

01

Moles of Carbon

Given: Carbon percentage: 49.31% Assume: mass of sample = 100g Moles of Carbon = (mass of carbon / molar mass of carbon) Moles of Carbon = (49.31g / 12.01g/mol) = 4.108 mol
02

Moles of Oxygen

Given: Oxygen percentage: 43.79% Moles of Oxygen = (mass of oxygen / molar mass of oxygen) Moles of Oxygen = (43.79g / 16.00g/mol) = 2.737 mol
03

Moles of Hydrogen

Given: Carbon, Oxygen, and Hydrogen percentages add up to 100%: Hydrogen percentage: 100 - 49.31 - 43.79 = 6.9% Moles of Hydrogen = (mass of hydrogen / molar mass of hydrogen) Moles of Hydrogen = (6.9g / 1.008g/mol) = 6.846 mol #Step 2: Determine the mole ratios of each element.# Now we will find the mole ratios by dividing the moles of each element by the smallest number of moles (2.737 in this case).
04

Mole Ratios

Carbon : (4.108 / 2.737) ≈ 1.5 Oxygen : (2.737 / 2.737) = 1 Hydrogen : (6.846 / 2.737) ≈ 2.5 Since we cannot have fractions in an empirical formula, we will multiply each ratio by 2 to remove the fractions. Carbon : 1.5 × 2 = 3 Oxygen : 1 × 2 = 2 Hydrogen : 2.5 × 2 = 5 #Step 3: Write the empirical formula.# The empirical formula will be written by utilizing the mole ratios that we have found.
05

Empirical Formula

Empirical Formula = C3H5O2 #Step 4: Calculate the molecular formula.# To calculate the molecular formula, we must first find the molar mass of the empirical formula. Then, we will compare it to the given molar mass of adipic acid and find the ratio between them.
06

Molar Mass of Empirical Formula

Molar Mass (C3H5O2) = (3 × 12.01) + (5 × 1.008) + (2 × 16.00) ≈ 73.05 g/mol Now, we will determine the ratio between the given molar mass and the empirical molar mass.
07

Ratio Between Molar Masses

Ratio = (146.1 g/mol) / (73.05 g/mol) ≈ 2 Since the ratio is 2, we just need to multiply each element in the empirical formula by 2 to obtain the molecular formula. #Step 5: Write the molecular formula.# Now we write the molecular formula for adipic acid, based on the ratio.
08

Molecular Formula

Molecular Formula = C6H10O4

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is the mathematical relationship between the relative quantities of reactants and products in chemical reactions. It allows chemists to predict the amounts of substances consumed and produced in a given reaction. The concept is founded on the principle of the conservation of mass, which states that in a chemical reaction, matter is neither created nor destroyed.

Understanding stoichiometry involves balancing chemical equations to reflect the conservation of atoms. The coefficients in a balanced equation tell us in what ratio the substances react and are formed. For example, in the complete combustion of propane, we have the chemical equation \( C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O \). This equation indicates that one molecule of propane reacts with five molecules of oxygen to produce three molecules of carbon dioxide and four molecules of water. Stoichiometry is a tool that would allow us to calculate the masses of reactants needed to produce a desired amount of product or, as in the case of the adipic acid example, determine the empirical and molecular formulas of a compound.
Molar Mass Calculation
Molar mass calculation is a fundamental concept in stoichiometry, as it links the mass of a substance to the amount of substance in terms of moles. The molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol). One mole contains Avogadro's number \(6.022 \times 10^{23}\) of entities, whether they are atoms, molecules, ions, or electrons.

To calculate the molar mass, one must sum the atomic masses of all the atoms in the molecular formula. For example, the molar mass of water, \(H_2O\), is calculated by adding the mass of two hydrogen atoms and one oxygen atom, which results in approximately 18.02 g/mol. In our adipic acid exercise, the molar mass calculation is crucial for determining the molecular formula. By comparing the molar mass of the empirical formula with the given molar mass of adipic acid, we arrive at the molecular formula, further illustrating the practical application of molar mass in solving chemical problems.
Mole-to-Mole Conversion
Mole-to-mole conversion is a vital process in stoichiometry that involves using the balanced chemical equation to convert between the amounts of reactants and products in moles. This process relies on the mole ratios derived from the coefficients in a balanced chemical equation, ensuring that atoms are conserved in a reaction.

For example, if the equation for the reaction of nitrogen with hydrogen to form ammonia is given as \(N_2 + 3H_2 \rightarrow 2NH_3\), the mole ratio of \(N_2:H_2:NH_3\) is 1:3:2. This tells us that for every mole of nitrogen used, three moles of hydrogen are required, and two moles of ammonia are produced. In the exercise solution, mole-to-mole conversion is illustrated when the moles of each element are compared with the smallest number of moles to establish the simplest whole number ratio among the elements. This ratio is crucial for determining the empirical formula, which is then used to find the molecular formula through the use of molar mass calculations and mole-to-mole conversions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You take \(1.00 \mathrm{~g}\) of an aspirin tablet (a compound consisting solely of carbon, hydrogen, and oxygen), burn it in air, and collect \(2.20\) \(\mathrm{g} \mathrm{CO}_{2}\) and \(0.400 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}\). You know that the molar mass of aspirin is between 170 and \(190 \mathrm{~g} / \mathrm{mol}\). Reacting 1 mole of salicylic acid with 1 mole of acetic anhydride \(\left(\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{3}\right)\) gives you 1 mole of aspirin and 1 mole of acetic acid \(\left(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}_{2}\right)\). Use this information to determine the molecular formula of salicylic acid.

A compound contains only carbon, hydrogen, and oxygen. Combustion of \(10.68 \mathrm{mg}\) of the compound yields \(16.01 \mathrm{mg}\) \(\mathrm{CO}_{2}\) and \(4.37 \mathrm{mg} \mathrm{H}_{2} \mathrm{O} .\) The molar mass of the compound is \(176.1 \mathrm{~g} / \mathrm{mol}\). What are the empirical and molecular formulas of the compound?

Terephthalic acid is an important chemical used in the manufacture of polyesters and plasticizers. It contains only \(\mathrm{C}, \mathrm{H}\), and \(\mathrm{O}\). Combustion of \(19.81 \mathrm{mg}\) terephthalic acid produces \(41.98 \mathrm{mg}\) \(\mathrm{CO}_{2}\) and \(6.45 \mathrm{mg} \mathrm{H}_{2} \mathrm{O}\). If \(0.250 \mathrm{~mol}\) of terephthalic acid has a mass of \(41.5 \mathrm{~g}\), determine the molecular formula for terephthalic acid.

Coke is an impure form of carbon that is often used in the industrial production of metals from their oxides. If a sample of coke is \(95 \%\) carbon by mass, determine the mass of coke needed to react completely with \(1.0\) ton of copper(II) oxide. $$ 2 \mathrm{CuO}(s)+\mathrm{C}(s) \longrightarrow 2 \mathrm{Cu}(s)+\mathrm{CO}_{2}(g) $$

Give the balanced equation for each of the following. a. The combustion of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) forms carbon dioxide and water vapor. A combustion reaction refers to a reaction of a substance with oxygen gas. b. Aqueous solutions of lead(II) nitrate and sodium phosphate are mixed, resulting in the precipitate formation of lead(II) phosphate with aqueous sodium nitrate as the other product. c. Solid zinc reacts with aqueous \(\mathrm{HCl}\) to form aqueous zinc chloride and hydrogen gas. d. Aqueous strontium hydroxide reacts with aqueous hydrobromic acid to produce water and aqueous strontium bromide.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.