Chapter 22: Problem 102
Why is glycine not optically active?
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Chapter 22: Problem 102
Why is glycine not optically active?
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Diborane, \(\mathrm{B}_{2} \mathrm{H}_{6}\), is a highly unstable compound that reacts explosively with oxygen. Ethane, \(\mathrm{C}_{2} \mathrm{H}_{6}\), combines with oxygen only at elevated temperatures. Explain the differences in these two compounds.
Glucose can occur in three forms: two cyclic forms and one openchain structure. In aqueous solution, only a tiny fraction of the glucose is in the open-chain form. Yet tests for the presence of glucose depend on reaction with the aldehyde group, which is found only in the open-chain form. Explain why these tests work.
Three different organic compounds have the formula \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\). Only two of these isomers react with \(\mathrm{KMnO}_{4}\) (a strong oxidizing agent). What are the names of the products when these isomers react with excess \(\mathrm{KMnO}_{4}\) ?
Which of the following polymers would be stronger or more rigid? Explain your
choices.
a. The copolymer of ethylene glycol and terephthalic acid or the copolymer of
1,2 -diaminoethane and terephthalic acid \((1,2-\) diaminoethane
\(=\mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) )
b. The polymer of
\(\mathrm{HO}-\left(\mathrm{CH}_{2}\right)_{6}-\mathrm{CO}_{2} \mathrm{H}\) or
that of
Polystyrene can be made more rigid by copolymerizing styrene with divinylbenzene: How does the divinylbenzene make the copolymer more rigid?
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