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91Ó°ÊÓ

Henry Taube, 1983 Nobel Prize winner in chemistry, has studied the mechanisms of the oxidation-reduction reactions of transition metal complexes. In one experiment he and his students studied the following reaction: \(\begin{aligned} \mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}(a q)+& \mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}^{2+}(a q) \\\ \longrightarrow & \mathrm{Cr}(\mathrm{III}) \text { complexes }+\mathrm{Co}(\mathrm{II}) \text { complexes } \end{aligned}\) Chromium(III) and cobalt(III) complexes are substitutionally inert (no exchange of ligands) under conditions of the experiment. Chromium(II) and cobalt(II) complexes can exchange ligands very rapidly. One of the products of the reaction is \(\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Cl}^{2+} .\) Is this consistent with the reaction proceeding through formation of \(\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Cr}-\mathrm{Cl}-\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5}\) as an intermediate? Explain.

Short Answer

Expert verified
Yes, the formation of the product, \( \mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{Cl}^{2+} \), is consistent with the reaction proceeding through the formation of \( \left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{Cr}-\mathrm{Cl}-\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \) as an intermediate. This is because Chromium(II) and Cobalt(II) complexes can rapidly exchange ligands, allowing for the proposed intermediate to form and ultimately produce the given product.

Step by step solution

01

Understanding the Experiment

Nobel laureate Henry Taube and his students conducted an experiment where they studied an oxidation-reduction reaction of transition metal complexes. The reaction is between a Chromium (Cr) complex and a Cobalt (Co) complex, resulting in the formation of Chromium (III) and Cobalt (II) complexes. The salient point to note is that Chromium(III) and cobalt(III) complexes are inert under conditions of the experiment, while Chromium(II) and Cobalt(II) complexes can exchange ligands rapidly.
02

Reactant and Product Profile

According to the information provided, one of the final products of the reaction includes \( \mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{Cl}^{2+} \). The question is trying to analyze whether the reaction could proceed through the formation of \( \left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{Cr}-\mathrm{Cl}-\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \) as an intermediate.
03

Analysing the Intermediate Step

The intermediate proposed here involves the ligands of the original Chromium and Cobalt complexes shifting, with a Chlorine (Cl) from the Cobalt complex ending up bound to the Chromium complex and forming \( \left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{Cr}-\mathrm{Cl}-\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \).
04

Verifying the Consistency

Given the process we understood from the experiment that the Chromium(II) and Cobalt(II) complexes can rapidly exchange ligands, but Chromium(III) and Cobalt(III) complexes are substitutionally inert. Therefore, the intermediate could indeed form if the reaction is occurring between Chromium and Cobalt at their 2+ oxidation states. As such, there's a clear path for the formation of the \( \mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{Cl}^{2+} \) product within the context of this reaction, assuming that the ligand exchange is a rapid process. This means that the formation of the product, \( \mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{Cl}^{2+} \), is consistent with the reaction proceeding through the formation of \( \left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{Cr}-\mathrm{Cl}-\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \) as an intermediate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transition Metal Complexes
Transition metal complexes are fascinating and play a crucial role in many chemical reactions, including oxidation-reduction processes. Transition metals include elements in the central block of the periodic table. They exhibit unique properties, mainly due to their ability to exist in multiple oxidation states and form complex structures with other molecules known as ligands.
  • These complexes are typically formed when metal ions bind with molecules or ions called ligands through coordinate bonds.
  • These ligands donate pairs of electrons to the metal center, stabilizing various metal oxidation states.
Transition metal complexes are integral in both biological systems and industrial applications, serving as catalysts and reactants in a myriad of processes.
Ligand Exchange
Ligand exchange is a process where ligands in a metal complex are replaced by other ligands. This can greatly affect the properties and reactivity of the metal complex.
  • In the context of the given experiment, ligand exchange plays a significant role because chromium(II) and cobalt(II) complexes can exchange ligands rapidly.
  • Rapid ligand exchange is crucial for forming intermediates like \((\mathrm{H}_{2} \mathrm{O})_{5}\mathrm{Cr}-\mathrm{Cl}-\mathrm{Co}(\mathrm{NH}_{3})_{5}\).
This exchange enhances the overall reaction rate and enables the transfer of electrons between the metal centers, which is essential in oxidation-reduction reactions.
Reaction Intermediates
In chemical reactions, intermediates are temporary structures that exist during the transformation of reactants into products. Identifying intermediates provides insight into the reaction mechanism.
  • The proposed intermediate, \((\mathrm{H}_{2} \mathrm{O})_{5}\mathrm{Cr}-\mathrm{Cl}-\mathrm{Co}(\mathrm{NH}_{3})_{5}\), shows how ligands are reorganized around different metal centers during the reaction.
  • This rearrangement facilitates the eventual transfer of chloride from cobalt to chromium, essential in forming the stable product \(\mathrm{Cr}(\mathrm{H}_{2} \mathrm{O})_{5}\mathrm{Cl}^{2+}\).
Understanding intermediates provides a pathway of how reactions may proceed, flowing smoothly from reactants to end products.
Chemistry Nobel Prize
The Nobel Prize in Chemistry is one of the most prestigious awards, given to individuals who contribute significantly to the field. Henry Taube, awarded in 1983, made groundbreaking advancements in understanding the mechanisms of electron transfer in metal complexes.
  • Taube's work has paved the way for more effective use of transition metal complexes in chemical synthesis and processes.
  • He explored how metal ions interact with ligands, affecting reactivity and electron transfer rates.
His research helps us comprehend how complexes like chromium and cobalt undergo oxidation-reduction, emphasizing the importance of metal oxidation states and ligand interactions.
Chromium and Cobalt Complexes
Chromium and cobalt are essential transition metals, known for forming stable and diverse complexes with the ability to exist in multiple oxidation states.
  • Chromium(III) complexes are substitutionally inert, meaning they do not readily exchange ligands, providing stability.
  • In contrast, chromium(II) can undergo fast ligand exchange, allowing dynamic changes during reactions.
  • Cobalt, similarly, exhibits variable oxidation states where cobalt(III) is quite stable, whereas cobalt(II) allows rapid ligand exchange.
These properties make chromium and cobalt complexes particularly interesting in oxidation-reduction reactions, where ligand arrangement and electron transfer are central to the reactions, as explored in the Nobel Prize-winning work by Henry Taube.

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Most popular questions from this chapter

A certain first-row transition metal ion forms many different colored solutions. When four coordination compounds of this metal, each having the same coordination number, are dissolved in wa ter, the colors of the solutions are red, yellow, green, and blue Further experiments reveal that two of the complex ions are para magnetic with four unpaired electrons and the other two are dia magnetic. What can be deduced from this information about th four coordination compounds?

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