/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 84 Carbohydrates, a class of compou... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Carbohydrates, a class of compounds containing the elements carbon, hydrogen, and oxygen, were originally thought to contain one water molecule \(\left(\mathrm{H}_{2} \mathrm{O}\right)\) for each carbon atom present. The carbohydrate glucose contains six carbon atoms. Write a general formula showing the relative numbers of each type of atom present in glucose.

Short Answer

Expert verified
The general formula for glucose, based on the relative numbers of each type of atom, is \[C_6H_{12}O_6\].

Step by step solution

01

Identify the number of carbon atoms

We are given that glucose has 6 carbon atoms, so our formula will include 6 Carbon atoms represented as C_6.
02

Determine the number of hydrogen atoms

Since there is one water molecule (H2O) for each carbon atom and glucose has 6 carbon atoms, we can say there are 6 water molecules. Considering there are 2 hydrogen atoms in a water molecule, we will have a total of 2*6=12 hydrogen atoms, which we will represent as H12 in the formula.
03

Determine the number of oxygen atoms

We know each water molecule contains 1 oxygen atom. We have 6 water molecules, so there are 6 oxygen atoms associated with the water molecules. We represent this as O6 in the formula.
04

Write the general formula

Now, we know the proportions of each type of atom present in glucose. We just need to combine them in a formula. The resulting general formula for glucose is: \[C_6H_{12}O_6\] This formula represents the molecular structure of glucose, with 6 carbon, 12 hydrogen, and 6 oxygen atoms present.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carbohydrates
Carbohydrates are a vital class of organic compounds composed of carbon, hydrogen, and oxygen. They play essential roles in biological processes, mainly acting as a primary source of energy for both plants and animals. These compounds are generally divided into three main types: **sugars**, **starch**, and **fibers**. Glucose is a type of sugar, which is a simple carbohydrate or **monosaccharide**. Unlike starchy carbohydrates, which consist of multiple sugar units, monosaccharides are single-unit sugars.

One key feature of carbohydrates is their general empirical formula \( ext{C}_n( ext{H}_2 ext{O})_n \), which explains why they are sometimes described as "hydrates of carbon." This formula highlights the 2:1 ratio of hydrogen to oxygen, similar to water. However, not all carbohydrates strictly adhere to this formula, especially more complex ones.
Chemical Formulas
Chemical formulas, such as the one for glucose, \( ext{C}_6 ext{H}_{12} ext{O}_6 \), express the composition of molecules in terms of the atoms they contain. These formulas give us a clear understanding of the proportions of each element within the compound.

By looking at the chemical formula of glucose, we can determine it contains:
  • 6 Carbon atoms
  • 12 Hydrogen atoms
  • 6 Oxygen atoms
These formulas not only tell us the number of atoms but also allow us to infer other properties, such as molecular mass. In glucose, the arrangement and bond distribution of these atoms define its specific properties and functionalities.
Molecular Structure
The molecular structure of a compound like glucose refers to the three-dimensional arrangement of its atoms in space. This structure heavily influences the compound's biological and chemical properties. In the case of glucose, each carbon atom is tetrahedrally bonded, facilitating its ability to form various structural isomers that can perform different functions in living organisms.

One critical aspect of the glucose molecular structure is its **ring formation**, which arises in aqueous solutions when the molecule forms a cyclic compound, a pyranose ring. This arrangement has significant implications for glucose's metabolism and functionality within biological systems. The distinctive structural arrangements contribute to glucose's role as an essential energy source in cellular respiration.
Organic Chemistry
Organic chemistry is the branch of chemistry that deals with the structure, properties, and reactions of organic compounds containing carbon. Glucose and its chemical formula \( ext{C}_6 ext{H}_{12} ext{O}_6 \) is a classic example of an organic molecule studied within this field. Organic chemistry explores how glucose interacts with other molecules, participates in biochemical reactions, and supports life.
  • The study of glucose involves understanding its synthesis paths and breakdown processes, such as glycolysis and photosynthesis.
  • Organic chemists also investigate how glucose's structure leads to different reactivity patterns and serves as a building block for more complex carbohydrates.
Organic chemistry not only explains the properties of glucose itself but also its transformations and roles in broader biological systems. Understanding these aspects helps us utilize carbohydrates in medicine, agriculture, and industry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the following statements is(are) true? For the false statements, correct them. a. All particles in the nucleus of an atom are charged b. The atom is best described as a uniform sphere of matter in which electrons are embedded. c. The mass of the nucleus is only a very small fraction of the mass of the entire atom. d. The volume of the nucleus is only a very small fraction of the total volume of the atom. e. The number of neutrons in a neutral atom must equal the numher of electrons.

Write the formula for each of the following compounds: a. sulfur difluoride b. sulfur hexafluoride c. sodium dihydrogen phosphate d. lithium nitride e. chromium(III) carbonate f. tin(II) fluoride g. ammonium acetate h. ammonium hydrogen sulfate i. cobalt(III) nitrate

A certain element has only two naturally occurring isotopes: one with 18 neutrons and the other with 20 neutrons. The element forms \(1-\) charged ions when in ionic compounds. Predict the identity of the element. What number of electrons does the \(1-\) charged ion have?

Write the formula for each of the following compounds: a. zinc chloride d. aluminum sulfide b. \(\operatorname{tin}(\mathrm{IV})\) fluoride e. mercury(I) selenide c. calcium nitride f. silver iodide

You have gone back in time and are working with Dalton on a table of relative masses. Following are his data. \(0.602 \mathrm{~g}\) gas A reacts with \(0.295 \mathrm{~g}\) gas \(\mathrm{B}\) \(0.172 \mathrm{~g}\) gas \(\mathrm{B}\) reacts with \(0.401 \mathrm{~g}\) gas \(\mathrm{C}\) \(0.320 \mathrm{~g}\) gas \(\mathrm{A}\) reacts with \(0.374 \mathrm{~g}\) gas \(\mathrm{C}\) a. Assuming simplest formulas \((\mathrm{AB}, \mathrm{BC}\), and \(\mathrm{AC}\) ), construct a table of relative masses for Dalton. b. Knowing some history of chemistry, you tell Dalton that if he determines the volumes of the gases reacted at constant temperature and pressure, he need not assume simplest formulas. You collect the following data: 6 volumes gas \(A+1\) volume gas \(B \rightarrow 4\) volumes product 1 volume gas \(\mathrm{B}+4\) volumes gas \(\mathrm{C} \rightarrow 4\) volumes product 3 volumes gas \(\mathrm{A}+2\) volumes gas \(\mathrm{C} \rightarrow 6\) volumes product Write the simplest balanced equations, and find the actual relative masses of the elements. Explain your reasoning.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.