Chapter 19: Problem 58
The mass percent of carbon in a typical human is \(18 \%\), and the mass percent of \({ }^{14} \mathrm{C}\) in natural carbon is \(1.6 \times 10^{-10} \%\). Assuming a \(180-\mathrm{lb}\) person, how many decay events per second occur in this person due exclusively to the \(\beta\) -particle decay of \({ }^{14} \mathrm{C}\) (for \({ }^{14} \mathrm{C}\), \(t_{1 / 2}=5730\) years)?
Short Answer
Step by step solution
1. Determine the mass of carbon in the person
2. Determine the number of Carbon-14 atoms in the person
3. Calculate the decay constant of Carbon-14
4. Calculate the number of decay events per second
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass Percent Calculation
We start with the given mass percent of carbon in a person, which is 18%. This tells us that 18% of a person's body mass is carbon. To find out the mass of carbon in a person weighing 180 pounds, we begin by converting pounds to kilograms, since the standard unit for mass calculation is kilograms.
- The conversion factor is: 1 lb = 0.453592 kg, thus 180 lb is approximately 81.65 kg.
- Now, to find the mass of carbon, we use the formula: \[ \text{Mass of carbon} = \text{Total mass} \times \left( \frac{\text{Percent of carbon}}{100} \right) \]
- Plugging in the values: \[ \text{Mass of carbon} = 81.65 \text{ kg} \times 0.18 = 14.697 \text{ kg} \]
Isotope Decay Calculation
Knowing the mass percent of Carbon-14 in natural carbon helps in calculating its presence in the human body. It is given as 1.6 x 10^-10 %, which means only a tiny fraction of the carbon in a person's body is Carbon-14. To find the actual mass of Carbon-14, we use the given mass of carbon in the person:
- Calculate the mass of Carbon-14: \[ \text{Mass of Carbon-14} = 14.697 \text{ kg} \times \left(\frac{1.6 \times 10^{-10}}{100}\right) \]
- Which simplifies to approximately 2.35152 x 10^-8 kg.
- Use the formula: \[ \text{Number of Carbon-14 atoms} = \frac{\text{mass of Carbon-14}}{\text{atomic mass of Carbon-14}} \]
- Where the atomic mass of Carbon-14 is approximately 14 AMU, and 1 AMU is 1.66 x 10^-27 kg.
- So, we calculate: \[ \frac{2.35152 \times 10^{-8} \text{ kg}}{14 \times 1.66 \times 10^{-27} \text{ kg}} \approx 5.09008 \times 10^{23} \text{ atoms} \]
Decay Constant
The decay constant, denoted by \(\lambda\), is calculated using the half-life of the isotope. For Carbon-14, the half-life is 5730 years. We convert this into seconds to match the units used in the decay calculations. First, we calculate the half-life in seconds:
- 1 year has 365.25 days to account for leap years.
- The conversion process is as follows: \[ t_{1/2} = 5730 \text{ years} \times \frac{365.25 \text{ days}}{1 \text{ year}} \times \frac{24 \text{ hours}}{1 \text{ day}} \times \frac{60 \text{ mins}}{1 \text{ hour}} \times \frac{60 \text{ seconds}}{1 \text{min}} \approx 1.8075 \times 10^{11} \text{ seconds} \]
- The formula to use is: \[ \lambda = \frac{\ln 2}{t_{1/2}} \]
- By substituting the values: \[ \lambda \approx \frac{\ln 2}{1.8075 \times 10^{11} \text{ seconds}} \approx 3.83465 \times 10^{-12} \text{s}^{-1} \]