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Consider a weak acid, HX. If a \(0.10 M\) solution of HX has a pH of \(5.83\) at \(25^{\circ} \mathrm{C}\), what is \(\Delta G^{\circ}\) for the acid's dissociation reaction at \(25^{\circ} \mathrm{C}\) ?

Short Answer

Expert verified
The standard Gibbs Free Energy change (螖G掳) for the dissociation of the weak acid HX at 25掳C is 56.196 kJ/mol.

Step by step solution

01

Convert the pH to the concentration of H+ ions

We first need to find the concentration of H+ ions from the given pH value: pH = - log[H+] Or [H+] = 10^(-pH) Given pH = 5.83, we can determine the concentration of H+ ions: [H+] = 10^(-5.83) = 1.47 脳 10^(-6) M
02

Write the chemical equation for the dissociation of HX

The chemical equation for the dissociation of the weak acid HX is: HX(aq) 鈬 H+(aq) + X^-(aq)
03

Calculate the equilibrium constant (Ka) for the reaction

Using the reaction above, we can now determine the equilibrium constant (Ka). Since the dissociation is at equilibrium, we can write the expression for Ka: \[ K_a = \frac{[H+][X^-]}{[HX]} \] We know that [H+] = 1.47 脳 10^(-6) M, and [HX] at the start is 0.10 M. Since the weak acid dissociates partially, at equilibrium, the concentration of X鈦 will also be equal to [H+]. Therefore, [X鈦籡 = 1.47 脳 10^(-6) M. Now, we can calculate Ka: \[ K_a = \frac{(1.47 \times 10^{-6})(1.47 \times 10^{-6})}{0.10} \] Ka = 2.15 脳 10^(-12)
04

Determine the standard reaction Gibbs energy change (螖G掳) using the relationship between 螖G掳 and Ka

Finally, we need to find the standard Gibbs Free Energy change (螖G掳) using the following formula: \[ \Delta G^{\circ} = -RT \ln(K_a) \] Where R is the gas constant (8.314 J/(mol路K)) and T is the temperature in Kelvin (25掳C = 298.15 K) \[ \Delta G^{\circ} = -(8.314)(298.15) \ln(2.15 \times 10^{-12}) \] 螖G掳 = 56,196 J/mol = 56.196 kJ/mol Therefore, the standard Gibbs Free Energy change (螖G掳) for the dissociation of the weak acid HX at 25掳C is 56.196 kJ/mol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

pH calculation
The concept of pH is central to understanding acid-base reactions. It measures the acidity or basicity of a solution. The pH scale ranges from 0 to 14, with 7 being neutral. Acidic solutions have pH values less than 7, while basic solutions are above 7.
To find the concentration of hydrogen ions ([H+]) from a given pH, we use the formula:\[\text{pH} = -\log[\text{H}^+]\]
Reversing this gives the concentration as:\[[\text{H}^+] = 10^{-\text{pH}}\]
In our example, a pH of 5.83 means the concentration of H+ ions is \(1.47 \times 10^{-6}\ M\). This calculation helps in determining how strongly an acid dissociates in solution.
Equilibrium constant (Ka)
The equilibrium constant \(K_a\) is a vital parameter for weak acids. It quantifies the extent of dissociation of an acid in water. For a weak acid like HX, which dissociates into H+ and X-, the expression is given by:
\[ K_a = \frac{[\text{H}^+][\text{X}^-]}{[\text{HX}]} \]
In our scenario, we know that at equilibrium, [H+] = [X-], both equal to \(1.47 \times 10^{-6}\ M\). The initial concentration of HX is \(0.10\ M\).
By substituting these values into the expression, we find:\[ K_a = \frac{(1.47 \times 10^{-6})(1.47 \times 10^{-6})}{0.10} \approx 2.15 \times 10^{-12} \]
This small \(K_a\) value indicates that HX is a weak acid, dissociating only slightly in solution.
Gibbs Free Energy (螖G掳)
Gibbs Free Energy change (\(\Delta G^\circ\)) provides insight into the favorability of a reaction. It's a thermodynamic quantity that predicts whether a reaction will occur spontaneously.
For chemical reactions, \(\Delta G^\circ\) is related to the equilibrium constant (\(K_a\)) using:
\[ \Delta G^{\circ} = -RT \ln(K_a) \]
Here, \(R\) represents the gas constant (8.314 J/(mol路K)), and \(T\) is the temperature in Kelvin.
At 25掳C or 298.15 K, substituting \(K_a = 2.15 \times 10^{-12}\), we find:
\[ \Delta G^{\circ} = -(8.314)(298.15) \ln(2.15 \times 10^{-12}) \approx 56.196\ \text{kJ/mol} \]
This positive \(\Delta G^\circ\) suggests the dissociation of HX into H+ and X- is not spontaneous.
Chemical equilibrium
Chemical equilibrium is a state where the forward and reverse reactions occur at the same rate, resulting in constant concentrations of products and reactants.
For the dissociation of a weak acid like HX:
\[ \text{HX} (aq) \rightleftharpoons \text{H}^+ (aq) + \text{X}^- (aq) \]
Equilibrium is reached when the concentration of HX, H+, and X- stabilize. At this point, the rates of dissociation and recombination of HX equal each other.
This balance is described quantitatively by the equilibrium constant \(K_a\). It helps determine how much an acid will dissociate under specific conditions.
In weak acids, the position of equilibrium is toward the reactants side, indicating limited dissociation, which is why \(K_a\) values are usually small.
This concept is crucial for understanding not only acid-base chemistry, but overall chemical reactions and their behaviors in various conditions.

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Most popular questions from this chapter

For a liquid, which would you expect to be larger, \(\Delta S_{\text {fusion }}\) or \(\Delta S_{\text {evaporation }}\) ? Why?

A green plant synthesizes glucose by photosynthesis, as shown in the reaction $$6 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+6 \mathrm{O}_{2}(g)$$ Animals use glucose as a source of energy: $$\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+6 \mathrm{O}_{2}(g) \longrightarrow 6 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l)$$ If we were to assume that both these processes occur to the same extent in a cyclic process, what thermodynamic property must have a nonzero value?

List three different ways to calculate the standard free energy change, \(\Delta G^{\circ}\), for a reaction at \(25^{\circ} \mathrm{C}\). How is \(\Delta G^{\circ}\) estimated at temperatures other than \(25^{\circ} \mathrm{C}\) ? What assumptions are made?

At what temperatures will the following processes be spontaneous? a. \(\Delta H=-18 \mathrm{~kJ}\) and \(\Delta S=-60 . \mathrm{J} / \mathrm{K}\) b. \(\Delta H=+18 \mathrm{~kJ}\) and \(\Delta S=+60 . \mathrm{J} / \mathrm{K}\) c. \(\Delta H=+18 \mathrm{~kJ}\) and \(\Delta S=-60 . \mathrm{J} / \mathrm{K}\) d. \(\Delta H=-18 \mathrm{~kJ}\) and \(\Delta S=+60 . \mathrm{J} / \mathrm{K}\)

Consider the following system at equilibrium at \(25^{\circ} \mathrm{C}\) : $$\mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{PCl}_{5}(g) \quad \Delta G^{\circ}=-92.50 \mathrm{~kJ}$$ What will happen to the ratio of partial pressure of \(\mathrm{PCl}_{5}\) to partial pressure of \(\mathrm{PCl}_{3}\) if the temperature is raised? Explain completely.

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