Chapter 15: Problem 64
Methyl red has the following structure:
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 15: Problem 64
Methyl red has the following structure:
All the tools & learning materials you need for study success - in one app.
Get started for free
Consider a solution formed by mixing \(50.0 \mathrm{~mL}\) of \(0.100 \mathrm{M}\) \(\mathrm{H}_{2} \mathrm{SO}_{4}, 30.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{HOCl}, 25.0 \mathrm{~mL}\) of \(0.200 \mathrm{M} \mathrm{NaOH}\). \(25.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{Ba}(\mathrm{OH})_{2}\), and \(10.0 \mathrm{~mL}\) of \(0.150 \mathrm{M} \mathrm{KOH}\). Calculate the \(\mathrm{pH}\) of this solution.
Calculate the \(\mathrm{pH}\) of a solution prepared by mixing \(250 . \mathrm{mL}\) of \(0.174 \mathrm{~m}\) aqueous \(\mathrm{HF}\) (density \(=1.10 \mathrm{~g} / \mathrm{mL}\) ) with \(38.7 \mathrm{~g}\) of an aqueous solution that is \(1.50 \% \mathrm{NaOH}\) by mass (density \(=1.02\) \(\mathrm{g} / \mathrm{mL}\) ). \(\left(K_{\mathrm{a}}\right.\) for \(\mathrm{HF}=7.2 \times 10^{-4}\).)
Calculate the \(\mathrm{pH}\) of each of the following solutions. a. \(0.100 \mathrm{MHONH}_{2}\left(K_{\mathrm{b}}=1.1 \times 10^{-8}\right)\) b. \(0.100 \mathrm{M} \mathrm{HONH}_{3} \mathrm{Cl}\) c. pure \(\mathrm{H}_{2} \mathrm{O}\) d. a mixture containing \(0.100 \mathrm{M} \mathrm{HONH}_{2}\) and \(0.100 \mathrm{M} \mathrm{HONH}_{3} \mathrm{Cl}\)
You have \(75.0 \mathrm{~mL}\) of \(0.10 M\) HA. After adding \(30.0 \mathrm{~mL}\) of \(0.10 M\) \(\mathrm{NaOH}\), the \(\mathrm{pH}\) is \(5.50\). What is the \(K_{\mathrm{u}}\) value of \(\mathrm{HA}\) ?
A \(0.400 M\) solution of ammonia was titrated with hydrochloric acid to the equivalence point, where the total volume was \(1.50\) times the original volume. At what \(\mathrm{pH}\) does the equivalence point occur?
What do you think about this solution?
We value your feedback to improve our textbook solutions.