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What are the major species present in \(0.250 M\) solutions of each of the following acids? Calculate the \(\mathrm{pH}\) of each of these solutions. a. \(\mathrm{HClO}_{4}\) b. \(\mathrm{HNO}_{3}\)

Short Answer

Expert verified
The major species in the 0.250 M HClO鈧 solution are H鈦 and ClO鈧勨伝 ions, with a pH of approximately 0.60. The major species in the 0.250 M HNO鈧 solution are H鈦 and NO鈧冣伝 ions, with a pH of approximately 0.60.

Step by step solution

01

(Dissociation of HClO鈧)

HClO鈧 will dissociate completely in water as follows: \(HClO_{4} (aq) -> H^{+} (aq) + ClO_{4}^{-} (aq)\)
02

(Dissociation of HNO鈧)

HNO鈧 will dissociate completely in water as follows: \(HNO_{3} (aq) -> H^{+} (aq) + NO_{3}^{-} (aq)\) ### Step 2: Calculate the concentration of H鈦 ions ###
03

(Concentration of H鈦 ions in HClO鈧 solution)

Since HClO鈧 is a strong acid that dissociates completely, the concentration of H鈦 ions in the 0.250 M HClO鈧 solution will be equal to the initial acid concentration: [H鈦篯 = 0.250 M
04

(Concentration of H鈦 ions in HNO鈧 solution)

Similarly, for HNO鈧, the concentration of H鈦 ions will be equal to the initial acid concentration: [H鈦篯 = 0.250 M ### Step 3: Calculate the pH of each solution ###
05

(pH of HClO鈧 solution)

Using the pH formula, we have: pH = -log([H鈦篯) = -log(0.250) 鈮 0.60
06

(pH of HNO鈧 solution)

Since the concentration of H鈦 ions is the same as that in HClO鈧 solution, the pH is also the same: pH = -log([H鈦篯) = -log(0.250) 鈮 0.60 So, the major species present in the 0.250 M HClO鈧 solution are H鈦 and ClO鈧勨伝 ions, with a pH of approximately 0.60. The major species present in the 0.250 M HNO鈧 solution are H鈦 and NO鈧冣伝 ions, with a pH of approximately 0.60.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid Dissociation
Acid dissociation is a fundamental concept crucial for understanding how acids behave in solution. When an acid is added to water, it dissociates, meaning it breaks apart into ions. These ions usually include a hydrogen ion, denoted as \(H^+\), and a corresponding anion, which depends on the specific acid involved.

For example:
  • When perchloric acid \( (HClO_{4}) \) dissociates, it yields \(H^{+}\) and \(ClO_{4}^{-}\) ions.
  • Meanwhile, nitric acid \( (HNO_{3}) \), dissociates to form \(H^{+}\) and \(NO_{3}^{-}\) ions.
Understanding the dissociation process is essential for predicting the behavior of acids in various chemical reactions and calculating their pH, as it directly determines the concentration of hydrogen ions in a solution.
pH Calculation
The pH of a solution is a measure of its acidity or basicity. Specifically, it indicates the concentration of hydrogen ions \([H^{+}]\) in the solution. The formula for calculating pH is:
\[ pH = -\log([H^{+}]) \]
If you know the concentration of hydrogen ions, calculating the pH becomes straightforward.

For both perchloric acid \((HClO_{4})\) and nitric acid \((HNO_{3})\), their complete dissociation implies that the concentration of \([H^{+}]\) is equal to the original concentration of the acid. So, for a 0.250 M solution:
  • The concentration of \([H^{+}]\) is 0.250 M.
  • Thus, the pH is \(-\log(0.250)\), which is approximately 0.60.
This calculation shows that both solutions are highly acidic, as indicated by their low pH value.
Perchloric Acid Dissociation
Perchloric acid, represented as \(HClO_{4}\), is a particularly strong acid known for its complete dissociation in aqueous solutions. This means that when \(HClO_{4}\) is dissolved in water, it splits entirely into its constituent ions, \(H^{+}\) and \(ClO_{4}^{-}\).

The complete dissociation ensures that the concentration of hydrogen ions in the solution equals the initial concentration of perchloric acid. Consequently, the major species present in a 0.250 M solution of perchloric acid are \(H^{+}\) and \(ClO_{4}^{-}\) ions. This complete ionization process significantly affects the solution's acidity, contributing to its characteristic low pH value of approximately 0.60.

The unique behavior of strong acids like \(HClO_{4}\) makes them important in various industrial and laboratory processes. Understanding their dissociation helps in predicting the pH and reactivity of solutions containing these compounds.
Nitric Acid Dissociation
Nitric acid, \(HNO_{3}\), is another strong acid similar to perchloric acid in that it dissociates completely in water. As \(HNO_{3}\) dissolves, it releases \(H^{+}\) ions and \(NO_{3}^{-}\) ions into the solution. This complete dissociation characteristic of strong acids ensures that the concentration of \(H^{+}\) ions is equal to the overall initial concentration of the acid.

For a 0.250 M solution of \(HNO_{3}\), the major species present are \(H^{+}\) and \(NO_{3}^{-}\) ions. This parallels what is observed with \(HClO_{4}\) and results in a similar pH value. The dissociation into these ions, and their involvement in various reactions, illustrate the critical nature of understanding acid behavior.

In practical applications, \(HNO_{3}\) is used extensively due to its reactive nature stemming from its acidic properties. Whether in cleaning, etching, or synthesis processes, knowing how nitric acid dissociates helps in optimizing and controlling the relevant chemical reactions.

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Most popular questions from this chapter

Place the species in each of the following groups in order of increasing acid strength. a. \(\mathrm{H}_{2} \mathrm{O}, \mathrm{H}_{2} \mathrm{~S}, \mathrm{H}_{2} \mathrm{Se}\) (bond energies: \(\mathrm{H}-\mathrm{O}, 467 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{H}-\mathrm{S}\), \(363 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{H}-\mathrm{Se}, 276 \mathrm{~kJ} / \mathrm{mol})\) b. \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}, \mathrm{FCH}_{2} \mathrm{CO}_{2} \mathrm{H}, \mathrm{F}_{2} \mathrm{CHCO}_{2} \mathrm{H}, \mathrm{F}_{3} \mathrm{CCO}_{2} \mathrm{H}\) c. \(\mathrm{NH}_{4}^{+}, \mathrm{HONH}_{3}{ }^{+}\) d. \(\mathrm{NH}_{4}{ }^{+}, \mathrm{PH}_{4}{ }^{+}\) (bond energies: \(\mathrm{N}-\mathrm{H}, 391 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{P}-\mathrm{H}, 322\) \(\mathrm{kJ} / \mathrm{mol}\) ) Give reasons for the orders you chose.

One mole of a weak acid HA was dissolved in \(2.0 \mathrm{~L}\) of solution. After the system had come to equilibrium, the concentration of HA was found to be \(0.45 M .\) Calculate \(K_{\mathrm{a}}\) for HA.

Arrange the following \(0.10 M\) solutions in order of most acidic to most basic. \(\mathrm{KOH}, \quad \mathrm{KNO}_{3}, \quad \mathrm{KCN}, \quad \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{HCl}\).

Consider \(1000 . \mathrm{mL}\) of a \(1.00 \times 10^{-4} M\) solution of a certain acid HA that has a \(K_{\mathrm{a}}\) value equal to \(1.00 \times 10^{-4} .\) How much water was added or removed (by evaporation) so that a solution remains in which \(25.0 \%\) of HA is dissociated at equilibrium? Assume that HA is nonvolatile.

Calculate the \(\mathrm{pH}\) of a \(0.20 \mathrm{MC}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}\) solution \(\left(K_{\mathrm{b}}=5.6 \times 10^{-4}\right)\).

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