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The \(\mathrm{pH}\) of \(1.0 \times 10^{-8} \mathrm{M}\) hydrochloric acid is not \(8.00\). The correct \(\mathrm{pH}\) can be calculated by considering the relationship between the molarities of the three principal ions in the solution \(\left(\mathrm{H}^{+}, \mathrm{Cl}^{-},\right.\), and \(\mathrm{OH}^{-}\) ). These molarities can be calculated from algebraic equations that can be derived from the considerations given below. a. The solution is electrically neutral. b. The hydrochloric acid can be assumed to be \(100 \%\) ionized. c. The product of the molarities of the hydronium ions and the hydroxide ions must equal \(K_{\mathrm{w}}\). Calculate the \(\mathrm{pH}\) of a \(1.0 \times 10^{-8} \mathrm{HCl}\) solution.

Short Answer

Expert verified
The pH of the 1.0 x 10^-8 M hydrochloric acid solution is approximately 5.995.

Step by step solution

01

Write down the ionization equation for HCl and autoionization of water

HCl ionizes in water as follows: HCl (aq) 鈫 H+ (aq) + Cl- (aq) Water (H2O) autoionizes as follows: H2O (l) 鈫 H+ (aq) + OH- (aq) The equilibrium constant for this reaction is represented as Kw.
02

Determine the initial concentrations of ions

We know that the concentration of HCl is 1.0 x 10^-8 M and it is 100% ionized. So the initial concentration of H鈦 ions from HCl is: [H鈦篯HCl = 1.0 x 10^-8 M
03

Let x represent the concentration of the additional H鈦 ions from water's autoionization

Let x be the concentration of H鈦 ions that are generated from the autoionization of water: [H鈦篯H2O = x Now, the total concentration of H鈦 ions will be: [H鈦篯total = [H鈦篯HCl + [H鈦篯H2O = 1.0 x 10^-8 + x
04

Write the equation for electrical neutrality and the dissociation constant for water (Kw)

The solution should be electrically neutral, and therefore: [H鈦篯total = [OH鈦籡 (1) We know that the autoionization of water has the equilibrium constant, Kw: Kw = [H鈦篯H2O * [OH鈦籡 (2) Kw for water is 1 x 10^-14 at room temperature.
05

Solve the equations for x (concentration of H鈦 ions from water's autoionization) and [OH鈦籡

From equation (1), we can write [OH鈦籡 in terms of [H鈦篯total: [OH鈦籡 = [H鈦篯total Substitute this in the equation for Kw (2) and solve for x: Kw = [H鈦篯H2O * [H鈦篯total 1 x 10^-14 = x * (1.0 x 10^-8 + x) Taking into account that x is very small compared to 1.0 x 10^-8, we can simplify this equation to: 1 x 10^-14 鈮 x * 1.0 x 10^-8 Solving for x, we get: x 鈮 1 x 10^-6 Now, we have the concentration of H鈦 ions from water's autoionization.
06

Calculate the total concentration of H鈦 ions and pH

Next, we'll find the total concentration of H鈦 ions in the solution using the value of x: [H鈦篯total = 1.0 x 10^-8 + x 鈮 1.0 x 10^-8 + 1 x 10^-6 Therefore, [H鈦篯total 鈮 1.01 x 10^-6 M Now, we can find the pH of the solution using the formula: pH = -log10[H鈦篯 pH = -log10(1.01 x 10^-6) Calculate the pH: pH 鈮 5.995
07

Final Answer

The pH of the 1.0 x 10^-8 M hydrochloric acid solution is approximately 5.995.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrochloric Acid Ionization
When hydrochloric acid (HCl) dissolves in water, it ionizes, or splits into its component ions. This process can be represented by the simple equation:
HCl (aq) 鈫 H鈦 (aq) + Cl鈦 (aq)
In dilute solutions, such as the example with a concentration of 1.0 x 10鈦烩伕 M, HCl can be assumed to dissociate completely. This assumption leads us to conclude that every molecule of HCl provides one hydrogen ion (H鈦) and one chloride ion (Cl鈦) to the solution. As a result, the same concentration of chloride ions will also exist in the solution. Understanding this ionization process is crucial for calculating the pH of an HCl solution and addressing the exercise improvement advice, we ensure that the concept of essentially complete ionization is highlighted for clarity.
Autoionization of Water
Water itself slightly ionizes in a process known as autoionization or self-ionization, which has the equation:
H鈧侽 (l) 鈫 H鈦 (aq) + OH鈦 (aq)
This process is essential when considering very dilute solutions of strong acids or bases, or even pure water. The equilibrium constant for this reaction is the ion product of water, Kw. In such solutions, the contributions of H鈦 and OH鈦 ions from water's autoionization can significantly affect pH calculations, a point not to be overlooked in our educational approach.
Concentration of Ions
The concentration of ions in a solution refers to the number of ions of a particular type (e.g., H鈦, OH鈦, Cl鈦) present in a unit volume of the solution. It is typically expressed in molarity (moles per liter, M). In the given exercise, the initial concentration of H鈦 ions from HCl is known to be 1.0 x 10鈦烩伕 M. However, due to water's autoionization, additional H鈦 ions are present, and their concentration must be determined to calculate the actual pH accurately鈥攖hus adhering to easy-to-understand content, we emphasize this consideration to improve students' comprehension.
Electrical Neutrality
In any aqueous solution, there is a fundamental principle of electrical neutrality: the sum of the positive charges must equal the sum of the negative charges. When calculating ion concentrations, this principle must be satisfied. As such, the total concentration of positive ions (particularly H鈦 ions) must equal the total concentration of negative ions (OH鈦 ions and any other anions present). For the exercise at hand, electrical neutrality helps set up an important relationship between the concentrations of hydronium and hydroxide ions, key to solving for pH.
Dissociation Constant (Kw)
The dissociation constant for water, Kw, is the product of the concentrations of hydrogen ions and hydroxide ions in pure water. At room temperature (25掳C), Kw is always 1 x 10鈦宦光伌. This constant is crucial for understanding the relationship between H鈦 and OH鈦 ion concentrations. When solving for the additional H鈦 ions from water's autoionization, Kw is used to calculate the potential increase in H鈦 ions, which, in turn, affects pH calculation. This explanation is in line with the imperative to provide content that ensures a student can easily grasp the intricacies of pH calculations involving Kw.

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