91影视

The pH of a solution is given by the formula: \(pH = -\log[H^+] \) We are given the following information: - \(0.100 \ mol\) of salt is dissolved in \(1.00 \ L\) of solution - the pH of the solution is 8.07

Since we know the pH of the solution, use the relation \(pH + pOH = 14\) to find the pOH. \(pOH = 14 - pH\) Substitute the given pH value and solve for pOH: \(pOH = 14 - 8.07 = 5.93\) Now, calculate the [OH鈦籡 concentration using the formula: \([OH^-] = 10^{-pOH}\) Substitute the pOH value and find the [OH鈦籡 concentration: \([OH^-] = 10^{-5.93} = 1.17 \times 10^{-6} M \)

For each salt, write the equation for how it ionizes in water and identify which ion(s) will increase the [OH鈦籡 concentration. 1) NaCN: \(NaCN \rightarrow Na^+ + CN^-\) (CN鈦� acts as a weak base) 2) NaC鈧侶鈧僌鈧�: \(NaC_2H_3O_2 \rightarrow Na^+ + C_2H_3O_2^-\) (C鈧侶鈧僌鈧傗伝 acts as a weak base) 3) NaF: \(NaF \rightarrow Na^+ + F^-\) (F鈦� acts as a weak base) 4) NaCl: \(NaCl \rightarrow Na^+ + Cl^-\) (Cl鈦� does not affect the [OH鈦籡 concentration) 5) NaOCl: \(NaOCl \rightarrow Na^+ + OCl^-\) (OCl鈦� acts as a weak base) We can eliminate NaCl from contention since it does not affect the [OH鈦籡 concentration, and the pH of the solution is above 7, which indicates a basic solution. Now we will use the [OH鈦籡 concentration to find which salt matches the given pH.

Use the [OH鈦籡 concentration to calculate the concentration of the corresponding anions (weak bases). Since all of the salts were dissolved in 1L of solution, we can equate their moles to molarity. 1) CN鈦�: The dissociation of CN鈦� will produce a very small [OH鈦籡 concentration as it is a weak base. Comparing it with the given [OH鈦籡 concentration, it won't match, so CN鈦� is not the reason behind the given pH. 2) C鈧侶鈧僌鈧傗伝: Similarly, the dissociation of C鈧侶鈧僌鈧傗伝 will also produce a very small [OH鈦籡 concentration compared to the given value, so it's not the reason behind the given pH. 3) F鈦�: In this case, the dissociation of F鈦� will produce a significant [OH鈦籡 concentration compared to CN鈦� and C鈧侶鈧僌鈧傗伝 as F鈦� is less weak relative to them. However, the [OH鈦籡 concentration produced is also very small compared to the given value. So, F鈦� is not the reason behind the given pH. 4) OCl鈦�: The dissociation of OCl鈦� will produce a significant [OH鈦籡 concentration compared to the other weak bases. Since OCl鈦� is less weak relative to the other weak bases, it could be responsible for producing the given [OH鈦籡 concentration. Given the above analysis, we can conclude that the salt causing the given pH is:

The identity of the salt responsible for the given pH is NaOCl.