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An important reaction in the commercial production of hydrogen is $$ \mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{CO}_{2}(g) $$ How will this system at equilibrium shift in each of the five following cases? a. Gaseous carbon dioxide is removed. b. Water vapor is added. c. In a rigid reaction container, the pressure is increased by adding helium gas. d. The temperature is increased (the reaction is exothermic). e. The pressure is increased by decreasing the volume of the reaction container.

Short Answer

Expert verified
a. The system will shift to the right, producing more H鈧(g) and CO鈧(g). b. The system will shift to the right, producing more H鈧(g) and CO鈧(g). c. The system remains at the same equilibrium point. d. The system will shift to the left, producing more CO(g) and H鈧侽(g). e. The system remains at the same equilibrium point.

Step by step solution

01

Case a: Gaseous carbon dioxide is removed.

When gaseous carbon dioxide is removed from the equilibrium system, according to Le Ch芒telier's principle, the system will shift to the side that produces gaseous carbon dioxide to counteract the disturbance and restore equilibrium. So, the system will shift to the right, producing more H鈧(g) and CO鈧(g).
02

Case b: Water vapor is added.

When water vapor is added to the equilibrium system, this disturbs the balance in favor of the reactants. According to Le Ch芒telier's principle, the system will shift to the side that reduces the amount of water vapor to restore equilibrium. Therefore, the system will shift to the right, producing more H鈧(g) and CO鈧(g).
03

Case c: Pressure is increased by adding helium gas.

Adding helium gas to a rigid reaction container increases the pressure, but it does not directly affect the number of moles of any component in the reaction. Hence, the change in pressure does not result in a shift in the equilibrium of the reaction. The system remains at the same equilibrium point.
04

Case d: Temperature is increased (the reaction is exothermic).

Since the reaction is exothermic, increasing the temperature adds heat to the equilibrium system. According to Le Ch芒telier's principle, the system will try to minimize the disturbance by shifting to the side that consumes the added heat. In this case, heat is produced in the forward reaction (CO + H鈧侽 鈫 H鈧 + CO鈧), so the system will shift to the left, producing more CO(g) and H鈧侽(g).
05

Case e: Pressure is increased by decreasing the volume of the reaction container.

Decreasing the volume of the reaction container increases the pressure in the system. According to Le Ch芒telier's principle, the system will shift to the side with fewer moles of gas to reduce the pressure and restore equilibrium. In this reaction, there are equal numbers of moles of reactants and products (1 mol of CO + 1 mol of H鈧侽 鈬 1 mol of H鈧 + 1 mol of CO鈧), so the change in volume does not result in a shift in the equilibrium of the reaction, and the system remains at the same equilibrium point.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
Chemical equilibrium refers to a state in a reversible chemical reaction where the rates of the forward and reverse reactions are equal. At this point, the concentrations of the reactants and products remain constant over time. This does not necessarily mean that the concentrations of reactants and products are equal, but that their ratios remain constant. Chemical equilibrium is dynamic, meaning that reactions continue to occur, but without any net change.
The concept of equilibrium is central to understanding how reactions respond to various changes in conditions. This can be particularly important in industrial settings, where maximizing the yield of desired products is critical.
Factors that can affect equilibrium include changes in concentration, temperature, and pressure. Each of these can cause a reaction to shift, favoring either the forward or reverse reaction, according to Le Chatelier's Principle.
Reaction Shifts
Reaction shifts occur in response to changes in concentration, pressure, volume, or temperature. According to Le Chatelier's Principle, if a system at equilibrium is subjected to an external change, the system will adjust itself to minimize the effect of that change and restore a new equilibrium.
For example:
  • If a reactant or product is added, the equilibrium will shift to consume the added substance.
  • If a reactant or product is removed, the equilibrium will shift to produce more of the removed substance.
  • Changing the pressure by altering the volume impacts reactions involving gases, encouraging shifts to the side with fewer or more moles of gas, depending on the change.
Understanding these shifts helps chemists predict how changes in the environment will affect the outcome of a reaction, allowing for improved control over reaction conditions.
Exothermic Reaction
An exothermic reaction is a chemical reaction that releases heat into its surroundings. In these reactions, the energy of the products is lower than that of the reactants. As such, heat can be considered a product of the reaction.
When temperature changes occur in an exothermic reaction, Le Chatelier's Principle helps predict how the equilibrium will shift. Increasing the temperature results in more heat in the system, prompting the system to shift towards the endothermic direction to absorb the extra heat, which is the reverse direction for exothermic reactions.
Conversely, decreasing the temperature will cause the system to favor the exothermic direction, producing more heat to compensate for the temperature drop. This concept is crucial in industrial chemistry where temperature control is used to maximize yields or manage reaction speed.
Gas Laws in Chemistry
Gas laws in chemistry describe the behavior of gases and how they respond to changes in conditions such as pressure, volume, and temperature. These principles are essential for understanding reactions involving gases, particularly those in equilibrium states.
  • Boyle's Law: States that for a given mass of gas at constant temperature, the product of pressure and volume is constant. (P鈧乂鈧 = P鈧俈鈧)
  • Charles's Law: States that the volume of a given mass of gas is directly proportional to its temperature at constant pressure. (V鈧/T鈧 = V鈧/T鈧)
  • Avogadro's Law: States that equal volumes of gases, at the same temperature and pressure, contain equal numbers of molecules.
These laws are critical for predicting how changes will impact the behavior of gases in a reaction, aiding in the understanding of reaction dynamics and equilibrium.

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Most popular questions from this chapter

Lexan is a plastic used to make compact discs, eyeglass lenses, and bullet- proof glass. One of the compounds used to make Lexan is phosgene \(\left(\mathrm{COCl}_{2}\right)\), an extremely poisonous gas. Phosgene decomposes by the reaction $$ \mathrm{COCl}_{2}(g) \rightleftharpoons \mathrm{CO}(g)+\mathrm{Cl}_{2}(g) $$ for which \(K_{\mathrm{p}}=6.8 \times 10^{-9}\) at \(100^{\circ} \mathrm{C}\). If pure phosgene at an initial pressure of \(1.0\) atm decomposes, calculate the equilibrium pressures of all species.

The gas arsine, \(\mathrm{AsH}_{3}\), decomposes as follows: $$ 2 \mathrm{AsH}_{3}(g) \rightleftharpoons 2 \mathrm{As}(s)+3 \mathrm{H}_{2}(g) $$ In an experiment at a certain temperature, pure \(\mathrm{AsH}_{3}(g)\) was placed in an empty, rigid, sealed flask at a pressure of \(392.0\) torr. After 48 hours the pressure in the flask was observed to be constant at \(488.0\) torr. a. Calculate the equilibrium pressure of \(\mathrm{H}_{2}(\mathrm{~g})\). b. Calculate \(K_{\mathrm{p}}\) for this reaction.

The formation of glucose from water and carbon dioxide is one of the more important chemical reactions in the world. Plants perform this reaction through the process of photosynthesis, creating the base of the food chain: $$ 6 \mathrm{H}_{2} \mathrm{O}(g)+6 \mathrm{CO}_{2}(g) \rightleftharpoons \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+6 \mathrm{O}_{2}(g) $$ At a particular temperature, the following equilibrium concentrations were found: \(\left[\mathrm{H}_{2} \mathrm{O}(g)\right]=7.91 \times 10^{-2} M,\left[\mathrm{CO}_{2}(g)\right]=\) \(9.3 \times 10^{-1} M\), and \(\left[\mathrm{O}_{2}(g)\right]=2.4 \times 10^{-3} M .\) Calculate the value of \(K\) for the reaction at this temperature.

For the reaction $$ \mathrm{PCl}_{5}(g) \rightleftharpoons \mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g) $$ at \(600 . \mathrm{K}\), the equilibrium constant, \(K_{\mathrm{p}}\), is \(11.5 .\) Suppose that \(2.450 \mathrm{~g} \mathrm{PCl}_{5}\) is placed in an evacuated \(500 .-\mathrm{mL}\) bulb, which is then heated to \(600 . \mathrm{K}\). a. What would be the pressure of \(\mathrm{PCl}_{5}\) if it did not dissociate? b. What is the partial pressure of \(\mathrm{PCl}_{5}\) at equilibrium? c. What is the total pressure in the bulb at equilibrium? d. What is the degree of dissociation of \(\mathrm{PCl}_{5}\) at equilibrium?

Given the following equilibrium constants at \(427^{\circ} \mathrm{C}\), $$ \begin{array}{ll} \mathrm{Na}_{2} \mathrm{O}(s) \rightleftharpoons 2 \mathrm{Na}(l)+\frac{1}{2} \mathrm{O}_{2}(g) & K_{1}=2 \times 10^{-25} \\ \mathrm{NaO}(g) \rightleftharpoons \mathrm{Na}(l)+\frac{1}{2} \mathrm{O}_{2}(g) & K_{2}=2 \times 10^{-5} \\ \mathrm{Na}_{2} \mathrm{O}_{2}(s) \rightleftharpoons 2 \mathrm{Na}(l)+\mathrm{O}_{2}(g) & K_{3}=5 \times 10^{-29} \\ \mathrm{NaO}_{2}(s) \rightleftharpoons \mathrm{Na}(l)+\mathrm{O}_{2}(g) & K_{4}=3 \times 10^{-14} \end{array} $$ determine the values for the equilibrium constants for the following reactions. a. \(\mathrm{Na}_{2} \mathrm{O}(s)+\frac{1}{2} \mathrm{O}_{2}(g) \rightleftharpoons \mathrm{Na}_{2} \mathrm{O}_{2}(s)\) b. \(\mathrm{NaO}(g)+\mathrm{Na}_{2} \mathrm{O}(s) \rightleftharpoons \mathrm{Na}_{2} \mathrm{O}_{2}(s)+\mathrm{Na}(l)\) c. \(2 \mathrm{NaO}(g) \rightleftharpoons \mathrm{Na}_{2} \mathrm{O}_{2}(s)\) (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

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