/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 111 When a person has a severe fever... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

When a person has a severe fever, one therapy used to reduce the fever is an "alcohol rub." Explain how the evaporation of alcohol from a person's skin removes heat energy from the body.

Short Answer

Expert verified
The evaporation of alcohol from a person's skin removes heat energy from the body due to three key factors: the absorption of latent heat of vaporization, heat conduction between the skin and alcohol, and the faster evaporation rate of alcohol compared to water. As the alcohol evaporates, it absorbs heat energy from the body, causing the body temperature to decrease and, therefore, reducing the fever.

Step by step solution

01

Understand evaporation and its cooling effect

Evaporation is the process where a liquid turns into its vapor (gaseous) form at a temperature below its boiling point. When a liquid evaporates, it absorbs the latent heat of vaporization from its surroundings, which causes the removal of heat energy and results in a cooling effect. In the case of an alcohol rub, the alcohol evaporates at room/body temperature, taking away the heat energy from the person's skin.
02

Heat transfer from the body to alcohol

Heat energy is transferred from the body to the alcohol by conduction and convection. When an alcohol rub is applied to a person's skin, the alcohol absorbs the heat energy from the body by conduction. This process of heat transfer occurs at the molecular level as the warmer molecules of the body lose energy to the cooler molecules of the alcohol.
03

Alcohol's faster evaporation rate

Due to its lower boiling point, alcohol evaporates faster than water. This quick-evaporation property is essential in achieving the desired cooling effect. When alcohol is applied to the skin, it rapidly evaporates and absorbs the heat energy from the body's surface, resulting in a decrease in body temperature.
04

How alcohol rub reduces fever

Now that we understand the physics behind evaporation and its cooling effect, we can explain how an alcohol rub reduces fever. When a person is experiencing a fever, their body temperature is higher than normal. An alcohol rub is applied to the skin, causing the evaporation of alcohol. This evaporation process removes heat energy from the body, causing the body temperature to decrease. In conclusion, the evaporation of alcohol from a person's skin removes heat energy due to the absorption of latent heat of vaporization, heat conduction between the skin and alcohol, and the faster evaporation rate of alcohol. The person's body temperature is lowered, helping to reduce the fever.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The radius of tungsten is \(137 \mathrm{pm}\) and the density is \(19.3 \mathrm{~g} / \mathrm{cm}^{3}\). Does elemental tungsten have a face-centered cubic structure or a body-centered cubic structure?

Rubidium chloride has the sodium chloride structure at normal pressures but assumes the cesium chloride structure at high pressures. (See Exercise 67.) What ratio of densities is expected for these two forms? Does this change in structure make sense on the basis of simple models? The ionic radius is \(148 \mathrm{pm}\) for \(\mathrm{Rb}^{+}\) and 181 pm for \(\mathrm{Cl}^{-}\).

Consider the following enthalpy changes: $$ \begin{aligned} \mathrm{F}^{-}+\mathrm{HF} \longrightarrow \mathrm{FHF}^{-} \quad \Delta H=-155 \mathrm{~kJ} / \mathrm{mol} \\ \left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O}+\mathrm{HF} \longrightarrow\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O}-\mathrm{-HF} \\ \Delta H=-46 \mathrm{~kJ} / \mathrm{mol} \\ \mathrm{H}_{2} \mathrm{O}(g)+\mathrm{HOH}(g) \longrightarrow \mathrm{H}_{2} \mathrm{O}--\mathrm{HOH}(\text { in ice }) \\ \Delta H=-21 \mathrm{~kJ} / \mathrm{mol} \end{aligned} $$ How do the strengths of hydrogen bonds vary with the electronegativity of the element to which hydrogen is bonded? Where in the preceding series would you expect hydrogen bonds of the following type to fall?

What quantity of energy does it take to convert \(0.500 \mathrm{~kg}\) ice at \(-20 .{ }^{\circ} \mathrm{C}\) to steam at \(250 .{ }^{\circ} \mathrm{C} ?\) Specific heat capacities: ice, \(2.03 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C} ;\) liquid, \(4.2 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C} ;\) steam, \(2.0 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C} ; \Delta H_{\mathrm{vap}}=\) \(40.7 \mathrm{~kJ} / \mathrm{mol} ; \Delta H_{\mathrm{fus}}=6.02 \mathrm{~kJ} / \mathrm{mol}\)

Explain why water forms into beads on a waxed car finish.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.