/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Predict which of the following b... [FREE SOLUTION] | 91Ó°ÊÓ

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Predict which of the following bonds should be weakest: \(\mathrm{Cl}-\mathrm{Cl}, \mathrm{Br}-\mathrm{Br}, \mathrm{I}-\mathrm{I}\)

Short Answer

Expert verified
The I-I bond is the weakest.

Step by step solution

01

Understand Bond Strength

Bond strength is determined by the bond dissociation energy, which is the energy required to break a bond between two atoms. Larger atoms have longer bond lengths, resulting in weaker bonds.
02

Analyze Atomic Sizes

Consider the atomic sizes of chlorine (Cl), bromine (Br), and iodine (I). Iodine is the largest atom, followed by bromine and then chlorine. As atomic size increases, the distance between the atoms in the bond increases, leading to weaker bonds.
03

Compare Bond Types

We are comparing single bonds: Cl-Cl, Br-Br, and I-I. These bonds are covalent and involve sharing of electrons between atoms of the same element.
04

Determine the Weakest Bond

Given that larger atomic radius leads to weaker bonds, the I-I bond is expected to be the weakest because iodine atoms are larger than bromine and chlorine atoms. Therefore, the I-I bond is longest and weakest.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bond Dissociation Energy
Bond dissociation energy is a vital concept in chemistry, as it signifies the energy required to break a bond between two atoms. Simply put, it describes how much energy is needed to "dissociate" or separate the atoms. This energy measure gives us insight into the strength of the bond: more energy means a stronger bond and vice versa.
Understanding bond dissociation energy is key to predicting chemical reactions, as bonds that require less energy to break are generally less stable. These unstable bonds can easily participate in chemical reactions. Therefore, by examining bond dissociation energy, chemists can predict which bonds in a molecule could break during a reaction.
In the exercise example, since iodine atoms in an I-I bond require less energy to separate compared to Cl-Cl or Br-Br, the I-I bond is considered the weakest among these three.
Atomic Sizes
Atomic size refers to the radius of an atom, which can influence the bond strength. Atoms with larger atomic radii form bonds with their neighbors that are generally longer. Longer bonds tend to be weaker because the electron density holding them together is distributed over a larger space.
Chlorine, bromine, and iodine are part of the same group in the periodic table, with increasing atomic size as you move down. This means:
  • Chlorine (Cl) is the smallest of the three.
  • Bromine (Br) is larger than chlorine.
  • Iodine (I) is the largest among them.
The increase in atomic size from chlorine to iodine indicates that the bonds become weaker because larger atoms lead to increased bond lengths. This explains why the I-I bond is the weakest: the atoms involved are the largest.
Covalent Bonds
Covalent bonds form when two atoms share electrons to achieve a stable electron configuration. This type of bond is common in nonmetals, like the halogens chlorine, bromine, and iodine. The mutual sharing of electrons provides a type of glue that holds the atoms together.
In single covalent bonds, each atom contributes one electron to the bond. These simple bonds, such as Cl-Cl, Br-Br, and I-I, consist of two electrons forming a shared pair. While all these bonds are covalent in nature, their strength can vary based on atomic sizes, as we've discussed.
In conclusion, the strength of a covalent bond is influenced by the size of the atoms involved. Larger atoms form weaker covalent bonds due to longer bond distances, as seen with the weakest I-I bond in the exercise.

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Most popular questions from this chapter

The \(\mathrm{N}_{2} \mathrm{O}_{5}\) molecule has nitrogen-oxygen bonds, but no nitrogen-nitrogen bonds nor oxygen-oxygen bonds. Draw eight resonance structures for \(\mathrm{N}_{2} \mathrm{O}_{5}\), and assign formal charges to the atoms in each. Which resonance structures make the more important contributions to the resonance hybrid?

Use the octet rule to predict the molecular formula of compounds that form between the elements (a) oxygen and fluorine. (b) silicon and chlorine.

Draw as many resonance structures as you can that obey the octet rule for each of the following molecules or ions. Use curved arrows to depict the conversion of one structure into another. (a) \(\mathrm{HN}_{3}\) (b) \(\mathrm{SO}_{3}\) (c) SCN

Suppose that the Pauli exclusion principle were somehow changed to allow three electrons per orbital rather than two. (a) Instead of an octet, how many outer-shell electrons would be needed for a noble-gas electron configuration? (b) How many electrons would be shared in a covalent bond? (c) Give the electron configuration, and draw an electron-dot structure for element \(X\) with \(Z=12\). (d) Draw an electron-dot structure for the molecule \(\mathrm{X}_{2}\).

The neutral OH molecule has been implicated in certain ozonedestroying processes that take place in the upper atmosphere. (a) Draw electron-dot structures for the OH molecule and the \(\mathrm{OH}^{-}\) ion. (b) Electron affinity can be defined for molecules just as it is defined for single atoms. Assuming that the electron added to \(\mathrm{OH}\) is localized in a single atomic orbital on one atom, identify which atom is accepting the electron, and give the \(n\) and \(l\) quantum numbers of the atomic orbital. (c) The electron affinity of \(\mathrm{OH}\) is similar to but slightly more negative than that of \(\mathrm{O}\) atoms. Explain.

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