Chapter 5: Problem 39
The MRI (magnetic resonance imaging) body scanners used in hospitals operate with \(400 \mathrm{MHz}\) radio frequency energy. How much energy does this correspond to in kilojoules per mole?
Short Answer
Expert verified
The energy is approximately \(1.596 \times 10^{-4}\) kJ/mol.
Step by step solution
01
Convert Frequency to Energy
Using Planck's equation, the energy of a photon can be calculated by the formula: \[ E = h \cdot u \]where \( u \) is the frequency, and \( h \) is Planck's constant \( 6.626 \times 10^{-34} \text{ J s} \). Given \( u = 400 \times 10^6 \text{ Hz} \), the energy is calculated as:\[ E = 6.626 \times 10^{-34} \times 400 \times 10^6 = 2.6504 \times 10^{-25} \text{ J} \]
02
Energy Per Mole
The energy calculated in Step 1 corresponds to the energy of one photon. Since one mole contains Avogadro's number of entities \( (N_A = 6.022 \times 10^{23} \text{ mol}^{-1}) \), the energy per mole (\( E_{\text{mole}} \)) is:\[ E_{\text{mole}} = E \times N_A = 2.6504 \times 10^{-25} \times 6.022 \times 10^{23} \]\[E_{\text{mole}} = 1.596 \times 10^{-1} \text{ J/mol} \]
03
Convert Joules to Kilojoules
To convert the energy from Joules to kilojoules, divide by 1000:\[ E_{\text{kJ/mol}} = \frac{1.596 \times 10^{-1}}{1000} \approx 1.596 \times 10^{-4} \text{ kJ/mol} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Photon Energy
In the world of physics, the energy of a photon is a crucial concept. A photon is a tiny packet of light energy, and to determine its energy, we rely on Planck's equation: \( E = h \cdot u \), where:
- \( E \) is the energy of the photon.
- \( h \) stands for Planck's constant, which equals \( 6.626 \times 10^{-34} \text{ J s} \).
- \( u \) is the frequency of the photon.
Avogadro's Number
Avogadro's number is a very large constant used in chemistry and physics, where it defines the number of entities, usually atoms or molecules, in one mole of a substance. This constant is approximately \( 6.022 \times 10^{23} \text{ mol}^{-1} \).
This number helps to bridge the microscopic world of atoms to the macroscopic world we observe. In the context of our exercise, once we determine the energy of a single photon, we multiply this by Avogadro's number to find the total energy contained in a mole of photons. Thus, \( E_{\text{mole}} = 2.6504 \times 10^{-25} \text{ J} \times 6.022 \times 10^{23} = 1.596 \times 10^{-1} \text{ J/mol} \).
By using Avogadro's number, we can scale up the energy from a single photon to a quantity like a mole, providing insight into energy calculations on a bulk level.
This number helps to bridge the microscopic world of atoms to the macroscopic world we observe. In the context of our exercise, once we determine the energy of a single photon, we multiply this by Avogadro's number to find the total energy contained in a mole of photons. Thus, \( E_{\text{mole}} = 2.6504 \times 10^{-25} \text{ J} \times 6.022 \times 10^{23} = 1.596 \times 10^{-1} \text{ J/mol} \).
By using Avogadro's number, we can scale up the energy from a single photon to a quantity like a mole, providing insight into energy calculations on a bulk level.
Frequency Conversion
The frequency conversion is an essential step when dealing with electromagnetic radiation. Frequency (\( u \)) represents how many cycles of a wave pass a point in one second and is measured in Hertz (Hz).
- In our specific scenario, we started with \( 400 \text{ MHz} \), which is equivalent to \( 400 \times 10^6 \text{ Hz} \).
- The process basically involves multiplying by the factor of \( 10^6 \) to convert from megahertz (MHz) to hertz (Hz).
Kilojoules per Mole
When dealing with energy in chemistry and physics, converting joules to kilojoules per mole is common practice. The mole is a standard unit in chemistry, and energies are often expressed in this way for convenience and meaningful comparison.
- In the given exercise, once we've calculated the energy in joules per mole (\( 1.596 \times 10^{-1} \text{ J/mol} \)), we convert this figure into kilojoules by dividing by 1000, as there are 1000 joules in a kilojoule.
- This conversion yields \( 1.596 \times 10^{-4} \text{ kJ/mol} \), which is far more manageable and useful for chemical and physical calculations.