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A \(250.0 \mathrm{~g}\) sample of a white solid is known to be a mixture of \(\mathrm{KNO}_{3}, \mathrm{BaCl}_{2}\), and \(\mathrm{NaCl}\). When \(100.0 \mathrm{~g}\) of this mixture is dissolved in water and allowed to react with excess \(\mathrm{H}_{2} \mathrm{SO}_{4}, 67.3 \mathrm{~g}\) of a white precipitate is collected. When the remaining \(150.0 \mathrm{~g}\) of the mixture is dissolved in water and allowed to react with excess \(\mathrm{AgNO}_{3}, 197.6 \mathrm{~g}\) of a second precipitate is collected. (a) What are the formulas of the two precipitates? (b) What is the mass of each substance in the original \(250 \mathrm{~g}\) mixture?

Short Answer

Expert verified
(a) BaSO_4 and AgCl; (b) Check calculations in the steps.

Step by step solution

01

Understand the Reactions

When the mixture is dissolved in water and reacts with \(\mathrm{H}_{2} \mathrm{SO}_{4}\), the \(\mathrm{BaCl}_{2}\) will produce \(\mathrm{BaSO}_{4}\) as a precipitate. The equation is:\[\mathrm{BaCl}_{2} + \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4} + 2\mathrm{HCl}\] When the mixture is dissolved in water and reacts with \(\mathrm{AgNO}_{3}\), both \(\mathrm{BaCl}_{2}\) and \(\mathrm{NaCl}\) will produce precipitates of \(\mathrm{AgCl}\). The relevant reaction is:\[\mathrm{AgNO}_{3} + \mathrm{Cl}^- \rightarrow \mathrm{AgCl} + \mathrm{NO}_{3}^-\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is the part of chemistry that focuses on the quantitative relationships between the reactants and products in a chemical reaction. It allows us to determine the amounts of substances consumed and formed in chemical reactions. This concept is crucial in problems involving precipitation reactions as it helps calculate the mass of products arising from given quantities of reactants.

In the context of this exercise, stoichiometry enables us to relate the masses of the reactants to the precipitates formed. For instance, understanding that 1 mole of \( \mathrm{BaCl}_2 \) reacts with 1 mole of \( \mathrm{H}_2\mathrm{SO}_4 \) to yield 1 mole of \( \mathrm{BaSO}_4 \) and 2 moles of \( \mathrm{HCl} \) helps determine the mass of \( \mathrm{BaSO}_4 \) precipitated, based on the initial amount of \( \mathrm{BaCl}_2 \) present in the mixture.

Similarly, stoichiometry aids in calculating the silver chloride precipitate formed when the mixture reacts with \( \mathrm{AgNO}_3 \). Using molar masses and the stoichiometric coefficients from balanced chemical equations, one can deduce the necessary quantities involved in these reactions. By using stoichiometry, we can establish relationships such as: \( \text{mass of } \mathrm{BaSO}_4 \) obtained / \( \text{mass of } \mathrm{BaCl}_2 \) used equals the molar ratio from the balanced equation. This makes stoichiometry vital in deriving unknown quantities from known masses in such chemical processes.
Chemical Equations
Chemical equations are symbolic representations of chemical reactions. They display the reactants, products, and the respective stoichiometric coefficients, crucial for understanding how substances interact and transform.

The balanced chemical equation \( \mathrm{BaCl}_2 + \mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{BaSO}_4 + 2\mathrm{HCl} \) is crucial in understanding which products are formed when the mixture is reacted with sulfuric acid. The formation of \( \mathrm{BaSO}_4 \) as a precipitate is clearly depicted by this equation and highlights how \( \mathrm{BaCl}_2 \) is the key reactant contributing to the solid product.

Similarly, the reaction \( \mathrm{AgNO}_3 + \mathrm{Cl}^- \rightarrow \mathrm{AgCl} + \mathrm{NO}_3^- \) shows how chloride ions (\( \mathrm{Cl}^- \)) react with silver nitrate (\( \mathrm{AgNO}_3 \)) to form silver chloride (\( \mathrm{AgCl} \)), another solid precipitate. This illustrates how both \( \mathrm{BaCl}_2 \) and \( \mathrm{NaCl} \) contribute to the formation of different precipitates based on available ions.

Writing chemical equations helps identify reactants and products, revealing the pathways through which reactions take place. This understanding is crucial for analyzing and predicting reaction outcomes, especially in mixture analysis and determining quantities of substances involved.
Mixture Analysis
Mixture analysis involves determining the components and their quantities within a given sample. This is particularly relevant when dealing with problems involving complex combinations of multiple substances.

In the exercise, the mixture analysis is performed by using two types of reactions to separate components based on their reactivity with specific reagents. By dissolving the mixture in water and reacting it with \( \mathrm{H}_2\mathrm{SO}_4 \) and \( \mathrm{AgNO}_3 \), distinct precipitates are formed which correspond to the constituents of the mixture.

  • The \( \mathrm{H}_2\mathrm{SO}_4 \) reaction specifically identifies \( \mathrm{BaCl}_2 \) through the formation of \( \mathrm{BaSO}_4 \), allowing us to determine the presence and quantity of \( \mathrm{BaCl}_2 \).
  • The \( \mathrm{AgNO}_3 \) reaction differentiates between chloride sources: \( \mathrm{NaCl} \) and \( \mathrm{BaCl}_2 \), which are both reflected in the formation of \( \mathrm{AgCl} \).
By carefully analyzing the mass of precipitates and using stoichiometric principles, we deduce the components of the original mixture. This methodical approach of mixture analysis allows the identification of different substances based on chemical reactions and is a valuable skill in chemistry, especially in laboratory settings and quality control processes.

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Most popular questions from this chapter

Assume that you have \(1.00 \mathrm{~g}\) of a mixture of benzoic acid (Mol. wt. \(=122\) ) and gallic acid (Mol.wt. \(=170\) ), both of which contain one acidic hydrogen that reacts with \(\mathrm{NaOH}\). On titrating the mixture with \(0.500 \mathrm{M} \mathrm{NaOH}, 14.7 \mathrm{~mL}\) of base is needed to completely react with both acids. What mass in grams of each acid is present in the original mixture?

Following the removal of phosphate by precipitation, an excess of silver ion was added to \(100.0 \mathrm{~mL}\) of a sports beverage. A white precipitate of silver chloride was isolated by filtration, dried, and found to have a mass of \(172 \mathrm{mg}\). Calculate the concentration of chloride ion in the drink in units of molarity.

What is the molarity of each ion in a solution prepared by dissolving \(0.550 \mathrm{~g}\) of \(\mathrm{Na}_{2} \mathrm{SO}_{4}, 1.188 \mathrm{~g}\) of \(\mathrm{Na}_{3} \mathrm{PO}_{4}\) and \(0.223 \mathrm{~g}\) of \(\mathrm{Li}_{2} \mathrm{SO}_{4}\) in water and diluting to a volume of \(100.00 \mathrm{~mL}\) ?

Dichromate ion, \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\), reacts with aqueous iron(II) ion in acidic solution according to the balanced equation \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)+6 \mathrm{Fe}^{2+}(a q)+14 \mathrm{H}^{+}(a q) \longrightarrow\) \(2 \mathrm{Cr}^{3+}(a q)+6 \mathrm{Fe}^{3+}(a q)+7 \mathrm{H}_{2} \mathrm{O}(l)\) What is the concentration of \(\mathrm{Fe}^{2+}\) if \(46.99 \mathrm{~mL}\) of \(0.2004 \mathrm{M}\) \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) is needed to titrate \(50.00 \mathrm{~mL}\) of the \(\mathrm{Fe}^{2+}\) solution?

Salicylic acid, used in the manufacture of aspirin, contains only the elements \(\mathrm{C}, \mathrm{H}\), and \(\mathrm{O}\) and has only one acidic hydrogen that reacts with \(\mathrm{NaOH}\). When \(1.00 \mathrm{~g}\) of salicylic acid undergoes complete combustion, \(2.23 \mathrm{~g} \mathrm{CO}_{2}\) and \(0.39 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}\) are obtained. When \(1.00 \mathrm{~g}\) of salicylic acid is titrated with \(0.100 \mathrm{M} \mathrm{NaOH}, 72.4 \mathrm{~mL}\) of base is needed for complete reaction. What are the empirical and molecular formulas of salicylic acid?

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