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A mixture of \(\mathrm{FeO}\) and \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) with a mass of \(10.0 \mathrm{~g}\) is converted to \(7.43 \mathrm{~g}\) of pure Fe metal. What are the amounts in grams of \(\mathrm{FeO}\) and \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) in the original sample?

Short Answer

Expert verified
The sample contains 5.34 g of \( \mathrm{FeO} \) and 4.66 g of \( \mathrm{Fe}_2\mathrm{O}_3 \).

Step by step solution

01

Identify Known Quantities

We are given the total mass of the mixture, which is 10.0 g, and the mass of pure iron obtained, which is 7.43 g.
02

Chemical Reactions

Convert both iron oxides to pure iron:- For \( \mathrm{FeO} \): \[ \mathrm{FeO} + 2\mathrm{H}^{+} \rightarrow \mathrm{Fe}^{2+} + \mathrm{H}_2\mathrm{O} \] producing elemental iron.- For \( \mathrm{Fe}_2\mathrm{O}_3 \): \[ \mathrm{Fe}_2 \mathrm{O}_3 + 6\mathrm{H}^{+} \rightarrow 2\mathrm{Fe}^{3+} + 3\mathrm{H}_2\mathrm{O} \] likewise producing elemental iron.
03

Express in Terms of Variables

Let the mass of \( \mathrm{FeO} \) be \( x \) g, and the mass of \( \mathrm{Fe}_2\mathrm{O}_3 \) be \( y \) g. Thus, the equations are:1. \( x + y = 10.0 \)2. \( \text{Iron from FeO} + \text{Iron from Fe}_2\mathrm{O}_3 = 7.43 \)
04

Calculate Iron Mass Contribution

- Molar mass of \( \mathrm{FeO} \) is 71.85 g/mol, contributing \( \frac{55.85}{71.85}x \) g.- Molar mass of \( \mathrm{Fe}_2\mathrm{O}_3 \) is 159.7 g/mol, contributing \( \frac{2 \times 55.85}{159.7}y \) g to 7.43 g of iron.
05

Develop System of Equations

Using the above insights, we get:1. \[ x + y = 10.0 \]2. \[ \frac{55.85}{71.85}x + \frac{2 \times 55.85}{159.7}y = 7.43 \]
06

Solve the System of Equations

Substitute \( y = 10.0 - x \) into the second equation, solve for \( x \), then use \( x \) to find \( y \).Using the substitution:\[ \frac{55.85}{71.85}x + \frac{2 \times 55.85}{159.7}(10 - x) = 7.43 \]Solving this gives \( x = 5.34 \) g, and substituting back gives \( y = 4.66 \) g.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Iron Oxides
Iron oxides are compounds composed of iron and oxygen. They are prevalent in various forms and are known for being the key components in rust and ores. In this exercise, we are dealing with two specific types of iron oxides: ferrous oxide (FeO) and ferric oxide (Fe₂O₃). These oxides have distinct properties and chemical behaviors.

- **Ferrous Oxide (FeO):** In this formulation, iron has an oxidation state of +2. This compound is often found in mineral form and is less stable than its counterpart, Fe₂O₃.
- **Ferric Oxide (Fe₂O₃):** Here, iron takes an oxidation state of +3. This is known as hematite in nature and is more stable than ferrous oxide. It typically appears as a red-brown solid in its natural form.
Iron oxides are pivotal in various industrial applications, particularly in metallurgy, where they are used to extract iron metal. Recognizing these compounds and their properties is crucial to understand the transformation processes in chemical reactions.
Chemical Reactions
Chemical reactions involve the transformation of reactants into products. In terms of stoichiometry, each reaction can be expressed mathematically to reflect the conservation of mass. In this task, both iron oxides need to be converted into pure iron.

To break it down, the reactions involve using hydrogen ions to reduce the iron oxides:
  • For **FeO**, the reaction can be expressed as: - \[ \mathrm{FeO} + 2H^+ \rightarrow \mathrm{Fe}^{2+} + \mathrm{H}_2\mathrm{O} \]
  • For **Feâ‚‚O₃**, the reaction is: - \[ \mathrm{Fe}_2\mathrm{O}_3 + 6H^+ \rightarrow 2\mathrm{Fe}^{3+} + 3\mathrm{H}_2\mathrm{O} \]
These reactions show how the oxides are reduced to elemental iron under acidic conditions. The stoichiometry allows us to calculate how much pure iron results from each starting compound by balancing atoms and charges in the reactions.
Molar Mass
Molar mass, typically expressed in grams per mole, is an essential aspect of stoichiometry. It enables us to convert between grams and moles, which is critical in chemical calculations. In this problem, knowing the molar mass of each iron oxide allows us to determine how much pure iron they contribute to the final product.

Let's explore this closely:
  • **FeO has a molar mass of 71.85 g/mol:** It includes 55.85 g/mol of iron, which signifies roughly 78% of the compound is pure iron. This high percentage means a significant portion of FeO contributes directly to the iron metal produced.
  • **Feâ‚‚O₃'s molar mass is 159.7 g/mol:** This compound contains two iron atoms, each with a weight of 55.85 g/mol, leading to about 70% of its mass being iron. This lower percentage compared to FeO demonstrates its relatively lesser contribution to pure iron for the same mass.
Calculating the mass of iron from each oxide necessitates converting their given concentrations to moles and then back to mass using these molar relationships. Understanding these conversions is vital for solving stoichiometry problems efficiently.

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Most popular questions from this chapter

Which of the following equations are balanced? (a) The development reaction in silver-halide photography: $$ \begin{array}{r} 2 \mathrm{AgBr}+2 \mathrm{NaOH}+\mathrm{C}_{6} \mathrm{H}_{6} \mathrm{O}_{2} \longrightarrow \\ 2 \mathrm{Ag}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{NaBr}+\mathrm{C}_{6} \mathrm{H}_{4} \mathrm{O}_{2} \end{array} $$ (b) The preparation of household bleach: $$ 2 \mathrm{NaOH}+\mathrm{Cl}_{2} \longrightarrow \mathrm{NaOCl}+\mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O} $$

When eaten, dietary carbohydrates are digested to yield glucose \(\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)\), which is then metabolized to yield carbon dioxide and water: $$ \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}+\mathrm{O}_{2} \longrightarrow \mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O} $$ Unbalanced Balance the equation, and calculate both the mass in grams and the volume in liters of the \(\mathrm{CO}_{2}\) produced from \(66.3 \mathrm{~g}\) of glucose, assuming that \(1 \mathrm{~mol}\) of \(\mathrm{CO}_{2}\) has a volume of \(25.4 \mathrm{~L}\) at normal body temperature.

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What are the molecular weights of the following pharmaceuticals? (a) \(\mathrm{C}_{33} \mathrm{H}_{35} \mathrm{FN}_{2} \mathrm{O}_{5}\) (atorvastatin, lowers blood cholesterol) (b) \(\mathrm{C}_{22} \mathrm{H}_{27} \mathrm{~F}_{3} \mathrm{O}_{4} \mathrm{~S}\) (fluticasone, anti-inflammatory) (c) \(\mathrm{C}_{16} \mathrm{H}_{16} \mathrm{ClNO}_{2} \mathrm{~S}\) (clopidogrel, inhibits blood clots)

Assume that gasoline has the formula \(\mathrm{C}_{8} \mathrm{H}_{18}\) and has a density of \(0.703 \mathrm{~g} / \mathrm{mL}\). How many pounds of \(\mathrm{CO}_{2}\) are produced from the complete combustion of \(1.00\) gal of gasoline?

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