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Write a balanced net ionic equation for each of the following reactions: (a) \(\mathrm{Zn}(s)+\) dilute \(\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow ?\) (b) \(\mathrm{BaSO}_{3}(s)+\mathrm{HCl}(a q) \longrightarrow ?\) (c) \(\mathrm{Cu}(s)+\) hot, concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}(l) \longrightarrow ?\) (d) \(\mathrm{H}_{2} \mathrm{~S}(a q)+\mathrm{I}_{2}(a q) \longrightarrow ?\)

Short Answer

Expert verified
(a) Zn + 2H鈦 -> Zn虏鈦 + H鈧; (b) BaSO鈧 + 2H鈦 -> Ba虏鈦 + SO鈧 + H鈧侽; (c) Cu + 2H鈦 + H鈧係O鈧 -> Cu虏鈦 + SO鈧 + 2H鈧侽; (d) H鈧係 + I鈧 -> 2HI + S.

Step by step solution

01

Identify All Participants (Reaction A)

For reaction (a), the participants are solid zinc (Zn) and dilute sulfuric acid (H鈧係O鈧), which can be considered as dissociating into H鈦 and SO鈧劼测伝 ions in solution.
02

Write Equation for Reaction A

The reaction is Zn(s) + 2H鈦(aq) -> Zn虏鈦(aq) + H鈧(g). Zinc metal is oxidized to Zn虏鈦 while hydrogen ions are reduced to hydrogen gas.
03

Net Ionic Equation (Reaction A)

Since SO鈧劼测伝 is a spectator ion, the net ionic equation is Zn(s) + 2H鈦(aq) 鈫 Zn虏鈦(aq) + H鈧(g).
04

Identify All Participants (Reaction B)

In reaction (b), barium sulfite (BaSO鈧) and hydrochloric acid (HCl) react. BaSO鈧 dissolves into Ba虏鈦 and SO鈧兟测伝 ions, and HCl dissociates into H鈦 and Cl鈦.
05

Write Equation for Reaction B

The overall reaction is BaSO鈧(s) + 2H鈦(aq) -> Ba虏鈦(aq) + SO鈧(g) + H鈧侽(l). Sulfite ions react with hydrogen ions to form water and sulfur dioxide gas.
06

Net Ionic Equation (Reaction B)

The net ionic equation, removing the spectator Cl鈦 ions, is BaSO鈧(s) + 2H鈦(aq) 鈫 Ba虏鈦(aq) + SO鈧(g) + H鈧侽(l).
07

Identify All Participants (Reaction C)

In reaction (c), copper (Cu) and hot, concentrated sulfuric acid (H鈧係O鈧) react. Concentrated sulfuric acid also acts as an oxidizing agent here.
08

Write Equation for Reaction C

The overall reaction is Cu(s) + 2H鈧係O鈧(l) -> CuSO鈧(aq) + SO鈧(g) + 2H鈧侽(l). Copper is oxidized to Cu虏鈦, with sulfuric acid being reduced to SO鈧.
09

Net Ionic Equation (Reaction C)

For copper oxidation, the net ionic equation is Cu(s) + 2H鈦(aq) + H鈧係O鈧(l) 鈫 Cu虏鈦(aq) + SO鈧(g) + 2H鈧侽(l).
10

Identify All Participants (Reaction D)

In reaction (d), hydrogen sulfide (H鈧係) and iodine (I鈧) react. H鈧係 donates electrons to I鈧.
11

Write Equation for Reaction D

The balanced reaction is H鈧係(aq) + I鈧(aq) -> 2HI(aq) + S(s). Hydrogen sulfide is oxidized, and iodine is reduced.
12

Net Ionic Equation (Reaction D)

There are no spectator ions to remove in this reaction, so the net ionic equation is H鈧係(aq) + I鈧(aq) 鈫 2HI(aq) + S(s).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
Chemical reactions are processes where substances, known as reactants, transform into different substances, called products. These transformations involve the breaking and forming of bonds. Chemical reactions can occur in various forms such as combination, decomposition, single replacement, and double replacement reactions.
A deeper understanding of chemical reactions involves observing changes like color, temperature, gas production, or precipitate formation. These changes indicate that a reaction has taken place, signaling the creation of new products with distinct chemical properties compared to the original reactants.
For example, in the net ionic equations given, you can see various transformations occurring, such as zinc turning into zinc ions or sulfite reacting with hydrogen ions to produce sulfur dioxide gas.
Equation Balancing
Equation balancing ensures that the number of each type of atom is conserved during a chemical reaction. This is based on the Law of Conservation of Mass, which states that matter cannot be created or destroyed.
A correctly balanced equation will have the same number of atoms for each element on both sides of the equation. Balancing requires adjusting coefficients, which are numbers placed in front of compounds or elements in a chemical equation to achieve this balance.
  • For reaction (a), the equation is balanced to show two hydrogen ions reacting with solid zinc to form zinc ions and hydrogen gas.
  • In reaction (b), coefficients are adjusted to indicate that barium sulfite reacts with two hydrogen ions.
Balancing might take some time to master, but it is crucial for accurately representing chemical reactions.
Acid-Base Reactions
Acid-base reactions involve the transfer of protons (hydrogen ions) between reactants. Acids are substances that can donate protons, while bases accept them. These reactions usually form water and salt as products.
Net ionic equations simplify these reactions by focusing only on the particles that undergo change, ignoring spectator ions that do not participate in the actual chemical transformation.
  • In reaction (b), for example, BaSO鈧 reacts with HCl to form water and sulfur dioxide gas鈥攄emonstrating an acid-base reaction where hydrogen ions and sulfite ions are the primary participants.
The net ionic equation clearly depicts how these ions interact to form the final products.
Oxidation-Reduction Reactions
Oxidation-reduction (redox) reactions are chemical processes where the oxidation state of atoms changes due to electron transfer. Oxidation is the loss of electrons, while reduction is the gain of electrons.
In the provided reactions, we see classic examples of redox processes:
  • In reaction (a), zinc undergoes oxidation as it loses electrons to become Zn虏鈦, while hydrogen ions gain electrons in a reduction process to form hydrogen gas.
  • In reaction (c), copper metal is oxidized by the sulfuric acid, which itself is reduced, highlighting the dual nature of redox reactions involving both oxidation and reduction simultaneously.
  • In reaction (d), iodine molecules accept electrons from hydrogen sulfide, illustrating a straightforward redox interaction where iodine is reduced and H鈧係 is oxidized.
Understanding redox reactions is key to grasping the intricate changes that occur during many chemical reactions, especially those involving metals and nonmetals.

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Most popular questions from this chapter

Reaction of titanium and chlorine at \(300^{\circ} \mathrm{C}\) yields a metal halide that is \(25.25 \% \mathrm{Ti}\) by mass. The melting point \(\left(-24^{\circ} \mathrm{C}\right)\) and boiling point \(\left(136^{\circ} \mathrm{C}\right)\) of the halide suggest it is a molecular compound rather than an ionic one. (a) What are the formula and name of the compound, assuming the molecular formula is the same as the empirical formula? (b) Write the balanced equation for the reaction. (c) When treated with magnesium, the compound yields high-purity titanium metal. Write a balanced equation for the reaction.

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Which element in each of the following pairs is the better electrical conductor? (a) \(\mathrm{B}\) or \(\mathrm{Ga}\) (b) In or \(\mathrm{S}\) (c) \(\mathrm{Pb}\) or \(\mathrm{P}\)

Write a balanced net ionic equation for each of the following reactions: (a) \(\mathrm{ZnS}(s)+\mathrm{HCl}(a q) \longrightarrow ?\) (b) \(\mathrm{H}_{2} \mathrm{~S}(a q)+\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}(a q) \longrightarrow\) ? (c) \(\mathrm{Fe}(s)+\) dilute \(\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow ?\) (d) \(\mathrm{BaO}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow ?\)

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