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Sodium melts at \(98^{\circ} \mathrm{C}\), and magnesium melts at \(650{ }^{\circ} \mathrm{C}\). Account for the higher melting point of magnesium using the electron-sea model.

Short Answer

Expert verified
Magnesium's higher melting point is due to its stronger metallic bonds from more delocalized electrons.

Step by step solution

01

Understanding the Electron-Sea Model

The electron-sea model explains metallic bonding. In this model, metal atoms release some of their electrons to form a 'sea' of electrons. These electrons are delocalized, meaning they don't belong to any particular atom, but instead move freely throughout the metallic structure, holding the atoms together.
02

Comparing Sodium and Magnesium

Sodium and magnesium are both metals and form metallic bonds, but there are differences in their atomic structure. Sodium has one valence electron per atom, while magnesium has two. This means magnesium can contribute more electrons to the electron sea than sodium.
03

Impact of Electron Sea on Melting Points

The more delocalized electrons in the electron sea, the stronger the metallic bonds. Magnesium's two valence electrons create a stronger electron sea than the single electron provided by sodium. Stronger metallic bonds require more energy to break, resulting in a higher melting point.
04

Conclusion

The greater number of valence electrons in magnesium enhances the metallic bonding strength through a stronger electron-sea effect compared to sodium, thus accounting for magnesium's higher melting point.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Metallic Bonding
Metallic bonding is a fundamental concept in chemistry that explains why metals have certain mechanical properties, such as malleability and electrical conductivity. In metals, the atoms are arranged in a structured lattice, where each atom releases one or more of its outermost electrons, or valence electrons, to form a shared 'sea' of electrons. These electrons are not bound to any specific atom but can move freely throughout the entire metallic structure. This freedom allows the atoms to slide past one another without breaking the metallic bond, contributing to the malleability and ductility of metals.
Additionally, this free movement of electrons within the lattice is what gives metals their ability to conduct electricity effectively. When an electric field is applied, these delocalized electrons can flow through the lattice, enabling an electric current. Thus, metallic bonding is a critical reason behind many of the unique characteristics of metals.
Melting Points of Metals
The melting points of metals are affected by the strength of their metallic bonds. When a metal is heated to its melting point, the energy supplied causes the atoms to break free from the constraints of the static lattice. The stronger the metallic bond, the more energy is required to reach a metal's melting point, as more energy is necessary to overcome the attractive forces holding the atoms together within the electron-sea model.
Magnesium, for instance, has a higher melting point than sodium because it has stronger metallic bonds. This is due to the presence of more valence electrons that contribute to the electron sea, enhancing the cohesive forces between the magnesium atoms compared to those in sodium.
Valence Electrons
Valence electrons play a crucial role in determining the properties of an element, particularly in metals. These are the electrons found in the outermost shell of an atom and are involved in forming bonds. In the context of metallic bonding, these electrons do not remain attached to their original atoms but become part of the electron sea.
This delocalization contributes to the overall strength of the metallic bond. For example:
  • In sodium, there is only one valence electron per atom, which results in a weaker electron sea.
  • In contrast, magnesium provides two valence electrons, creating a more robust electron-sea effect.
The presence of more valence electrons not only strengthens the metallic bond but also increases the metal's melting point, as a stronger electron sea requires more energy to disrupt.
Metallic Structure
The metallic structure of an element is characterized by a tightly packed arrangement of atoms in a regular, repeating pattern. This structure is stabilized by the electron sea surrounding the positive metal ions, resulting from the delocalization of valence electrons. In metals, this structure is highly beneficial because:
  • It allows for efficient packing of atoms, contributing to the density and strength of the metal.
  • The uniform distribution of electrons leads to consistent bonding strength throughout the material, enhancing durability.
In magnesium, the closely packed atomic structure combined with the electron sea of delocalized electrons accounts for its substantial resistance to melting compared to metals with less dense electron seas, like sodium. The metallic structure not only impacts physical properties like melting points but also affects how metals interact with external forces and elements in the environment.

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Most popular questions from this chapter

A \(3.4 \times 10^{3} \mathrm{~kg}\) batch of cast iron contains \(0.45 \%\) by mass of phosphorus as an impurity. In the conversion of cast iron to steel by the basic oxygen process, the phosphorus is oxidized to \(\mathrm{P}_{4} \mathrm{O}_{10}\) which then reacts with \(\mathrm{CaO}\) and is removed as slag. (a) Write balanced equations for the oxidation of \(\mathrm{P}_{4}\) and for the formation of slag. (b) How many kilograms of \(\mathrm{CaO}\) are required to react with all the \(\mathrm{P}_{4} \mathrm{O}_{10}\) ?

The \(\mathrm{YBa}_{2} \mathrm{Cu}_{3} \mathrm{O}_{7}\) superconductor can be synthesized by the solgel method from a stoichiometric mixture of metal ethoxides followed by heating in oxygen. How many grams of \(\mathrm{Y}\left(\mathrm{OCH}_{2} \mathrm{CH}_{3}\right)_{3}\) and how many grams of \(\mathrm{Ba}\left(\mathrm{OCH}_{2} \mathrm{CH}_{3}\right)_{2}\) are required to react with \(75.4 \mathrm{~g}\) of \(\mathrm{Cu}\left(\mathrm{OCH}_{2} \mathrm{CH}_{3}\right)_{2}\) and an excess of water? Assuming a \(100 \%\) yield, how many grams of \(\mathrm{YBa}_{2} \mathrm{Cu}_{3} \mathrm{O}_{7}\) are obtained?

Classify the following semiconductors as \(n\) -type or \(p\) -types (a) Si doped with In (b) Ge doped with \(\mathrm{Sb}\) (c) Gray Sn doped with As

How does the electrical conductivity of a semiconductor change as the temperature increases? Explain.

The alkali metal fulleride superconductors \(\mathrm{M}_{3} \mathrm{C}_{60}\) have a cubic closest-packed (face-centered cubic) arrangement of nearly spherical \(\mathrm{C}_{60}{ }^{3-}\) anions with \(\mathrm{M}^{+}\) cations in the holes between the larger \(\mathrm{C}_{60}{ }^{3-}\) ions. The holes are of two types: octahedral holes, which are surrounded octahedrally by six \(\mathrm{C}_{60}{ }^{3-}\) ions, and tetrahedral holes, which are surrounded tetrahedrally by four \(\mathrm{C}_{60}{ }^{3-}\) ions. (a) Sketch the three-dimensional structure of one unit cell. (b) How many \(\mathrm{C}_{60}{ }^{3-}\) ions, octahedral holes, and tetrahedral holes are present per unit cell? (c) Specify fractional coordinates for all the octahedral and tetrahedral holes. (Fractional coordinates are fractions of the unit cell edge lengths. For example, a hole at the center of the cell has fractional coordinates \(\frac{1}{2}, \frac{1}{2}, \frac{1}{2}\).) (d) The radius of a \(\mathrm{C}_{60}{ }^{3-}\) ion is about \(500 \mathrm{pm}\). Assuming that the \(\mathrm{C}_{60}{ }^{3-}\) ions are in contact along the face diagonals of the unit cell, calculate the radii of the octahedral and tetrahedral holes. (e) The ionic radii of \(\mathrm{Na}^{+}, \mathrm{K}^{+}\), and \(\mathrm{Rb}^{+}\) are 102,138 , and \(152 \mathrm{pm}\), respectively. Which of these ions will fit into the octahedral and tetrahedral holes? Which ions will fit only if the framework of \(\mathrm{C}_{60}{ }^{3-}\) ions expands?

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