/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 95 Write the formula for each of th... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 20: Problem 95

Write the formula for each of the following compounds: (a) Diamminesilver(I) nitrate (b) Potassium diaquadioxalatocobaltate(III) (c) Hexacarbonylmolybdenum(0) (d) Diamminebis(ethylenediamine) chromium(III) chloride

Short Answer

Expert verified
(a) 摆础驳(狈贬鈧�)鈧俔NO鈧� (b) K[Co(H鈧侽)鈧�(C鈧侽鈧�)鈧俔 (c) [Mo(CO)鈧哴 (d) [Cr(NH鈧�)鈧�(en)鈧俔Cl鈧�

Step by step solution

01

Identify each component of the compound

Break down the names of each compound to identify the metal, ligands, charge or oxidation state, and other components that will form the formula.
02

Write the chemical formula for Diamminesilver(I) nitrate

For Diamminesilver(I) nitrate, the ligand is ammonia (NH鈧�), silver is Ag with a 1+ charge, and nitrate is NO鈧冣伝. The complex can be written as 摆础驳(狈贬鈧�)鈧俔NO鈧�.
03

Write the chemical formula for Potassium diaquadioxalatocobaltate(III)

For Potassium diaquadioxalatocobaltate(III), the oxidation state of cobalt is +3, it is coordinated to two water (H鈧侽) and two oxalate (C鈧侽鈧劼测伝) ligands. The complex becomes K[Co(H鈧侽)鈧�(C鈧侽鈧�)鈧俔.
04

Write the chemical formula for Hexacarbonylmolybdenum(0)

For Hexacarbonylmolybdenum(0), Molybdenum (Mo) is coordinated to six carbonyl (CO) ligands with an oxidation state of 0. Therefore, the formula is [Mo(CO)鈧哴.
05

Write the chemical formula for Diamminebis(ethylenediamine) chromium(III) chloride

For Diamminebis(ethylenediamine) chromium(III) chloride, chromium is coordinated to two ammonia (NH鈧�) and two ethylenediamine (en) ligands in the +3 oxidation state. The resulting formula is [Cr(NH鈧�)鈧�(en)鈧俔Cl鈧�.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Formulas
When creating chemical formulas for coordination compounds, it is essential to decode the chemical names given. You should identify the central metal atom or ion, the oxidation state, and the attached ligands. For example, in Diamminesilver(I) nitrate, 'Diammine' means two ammonia (NH鈧�) ligands are attached to a silver ion. The oxidation state of silver here is +1, indicated by the Roman numeral I in parentheses. Consequently, the formula is written with the complex ion in square brackets:
  • 摆础驳(狈贬鈧�)鈧俔
  • NO鈧� outside the brackets represents the nitrate part of the compound.
Order and brackets play crucial roles in expressing these relationships correctly.
Nomenclature
Understanding nomenclature is key for writing formulas for coordination compounds. Each part of a compound's name provides specific details:
  • The prefix indicates the number of each type of ligand (e.g., 'di-' for two).
  • The name of the ligands comes before the metal's name.
  • Oxidation states are expressed in Roman numerals in parentheses after the metal's name.
Hence in Potassium diaquadioxalatocobaltate(III), 'potassium' refers to the counter ion. 'Diaqua' means two water molecules act as ligands, 'dioxalato' means two oxalate ions, and the number in parentheses signifies cobalt's oxidation state.
Ligands
Ligands are ions or molecules that donate an electron pair to the central metal atom or ion in coordination compounds. They are crucial in defining the structure and properties of the compound. For example, in Hexacarbonylmolybdenum(0), 'hexacarbonyl' indicates six carbon monoxide (CO) ligands.
  • Neutral ligands like H鈧侽 and NH鈧� do not affect the net charge of the complex.
  • Charged ligands such as C鈧侽鈧劼测伝 (oxalate) do affect charge balance.
In coordination chemistry, ligands can be monodentate (attaching at one site) like CO, or polydentate (attaching at multiple sites), such as ethylenediamine.
Oxidation States
Oxidation states in coordination compounds denote the charge of the central metal ion after electrons have been donated by the ligands. It's depicted in Roman numerals. For example, in Diamminebis(ethylenediamine) chromium(III) chloride, chromium is in a +3 state.
  • This guides the formula as it determines the number and type of ligands needed for charge balance.
  • The counter ions outside the complex, like Cl鈦� in this case, adjust to neutralize the overall charge of the compound.
Identifying the oxidation state helps in accurately writing and balancing chemical formulas.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What is the systematic name for each of the following coordination compounds? (a) \(\mathrm{Cs}\left[\mathrm{FeCl}_{4}\right]\) (b) \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]\left(\mathrm{NO}_{3}\right)_{3}\) (c) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{Br}\) (d) \(\mathrm{Cu}(\mathrm{gly})_{2}\)

Tell how many diastereoisomers are possible for each of the following complexes, and draw their structures: (a) \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{CN})_{2}\) (b) \(\left[\mathrm{Co}(\mathrm{en})(\mathrm{SCN})_{4}\right]^{-}\) (c) \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\right]^{+}\) (d) \(\mathrm{Ru}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{I}_{3}\)

Nickel(II) complexes with the formula \(\mathrm{NiX}_{2} \mathrm{~L}_{2}\), where \(\mathrm{X}^{-}\) is \(\mathrm{Cl}\) or N-bonded \(\mathrm{NCS}^{-}\) and \(\mathrm{L}\) is the monodentate triphenylphosphine ligand \(\mathrm{P}\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{3}\), can be square planar or tetrahedral. (a) Draw crystal field energy-level diagrams for a square planar and a tetrahedral nickel(II) complex, and show the popula- tion of the orbitals. (b) If \(\mathrm{NiCl}_{2} \mathrm{~L}_{2}\) is paramagnetic and \(\mathrm{Ni}(\mathrm{NCS})_{2} \mathrm{~L}_{2}\) is diamagnetic, which of the two complexes is tetrahedral and which is square planar? (c) Draw possible structures for each of the \(\mathrm{NiX}_{2} \mathrm{~L}_{2}\) complexes, and tell which ones have a dipole moment.

Draw a crystal field \(d\) -orbital energy-level diagram, and predict the number of unpaired electrons for each of the following complexes: (a) \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) (b) \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}\) (c) \(\left[\mathrm{VF}_{6}\right]^{3-}\) (d) \(\left[\mathrm{Ni}(\mathrm{en})_{3}\right]^{2+}\)

Conceptual PROBLEM How does the effective nuclear charge, \(Z_{\text {eff }}\) vary from left to right across the first transition series? $$ \begin{array}{|l|l|l|l|l|l|l|l|l|l|} \hline \mathrm{Sc} & \mathrm{Ti} & \mathrm{V} & \mathrm{Cr} & \mathrm{Mn} & \mathrm{Fe} & \mathrm{Co} & \mathrm{Ni} & \mathrm{Cu} & \mathrm{Zn} \\ \hline \end{array} $$ Based on the variation in \(Z_{\mathrm{eff}}\) (a) Which \(\mathrm{M}^{2+}\) ion \((\mathrm{M}=\mathrm{Ti}-\mathrm{Zn})\) should be the strongest reducing agent? Which should be the weakest? (b) Which oxoanion \(\left(\mathrm{VO}_{4}{ }^{3-}, \mathrm{CrO}_{4}^{2-}, \mathrm{MnO}_{4}^{2-}\right.\), or \(\left.\mathrm{FeO}_{4}{ }^{2-}\right)\) should be the strongest oxidizing agent? Which should be the weakest?
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Making Measurements

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Kinetics

Read Explanation

The Earths Atmosphere

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.