Chapter 20: Problem 43
Predict the number of unpaired electrons for each of the following: (a) \(\mathrm{Sc}^{3+}\) (b) \(\mathrm{Co}^{2+}\) (c) \(\mathrm{Mn}^{3+}\) (d) \(\mathrm{Cr}^{2+}\)
Short Answer
Expert verified
\(\mathrm{Sc}^{3+}\): 0 unpaired, \(\mathrm{Co}^{2+}\): 3 unpaired, \(\mathrm{Mn}^{3+}\): 4 unpaired, \(\mathrm{Cr}^{2+}\): 4 unpaired.
Step by step solution
01
Understand Electron Configuration Basics
To predict the number of unpaired electrons, first understand the electron configuration of each element. Elements lose electrons from their outermost shells to form cations. Focus on the configuration in their neutral state first and then adjust for the charge.
02
Determine Neutral Electron Configurations
Determine the electron configuration of each element in its neutral state before adjusting for the charge:
- Scandium (Sc): [Ar] 3d鹿 4s虏
- Cobalt (Co): [Ar] 3d鈦 4s虏
- Manganese (Mn): [Ar] 3d鈦 4s虏
- Chromium (Cr): [Ar] 3d鈦 4s鹿
03
Adjust for Cation Electron Loss
Convert each neutral atom to its given charge by removing electrons, starting from the outermost shell (4s before 3d):- (\(\mathrm{Sc}^{3+}\)): Remove 3e鈦: [Ar]- (\(\mathrm{Co}^{2+}\)): Remove 2e鈦: [Ar] 3d鈦- (\(\mathrm{Mn}^{3+}\)): Remove 3e鈦: [Ar] 3d鈦- (\(\mathrm{Cr}^{2+}\)): Remove 2e鈦: [Ar] 3d鈦
04
Count Unpaired Electrons
Count the unpaired electrons for each cation configuration:- (\(\mathrm{Sc}^{3+}\)): 0 unpaired electrons (noble gas configuration)- (\(\mathrm{Co}^{2+}\)): 3 unpaired electrons (configuration is t鈧俫鈦 e_g^2)- (\(\mathrm{Mn}^{3+}\)): 4 unpaired electrons (configuration is t鈧俫鲁 e_g^1)- (\(\mathrm{Cr}^{2+}\)): 4 unpaired electrons (configuration is t鈧俫虏 e_g^2)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron Configurations
Electron configurations are like the blueprint of an atom's electrons arranged in different shells and subshells. They follow a specific order dictated by the Aufbau principle, which guides electrons to fill the lowest energy shell available. This principle, along with Hund's rule and the Pauli exclusion principle, helps us understand how these electrons spread out in an atom.
Start with the reference noble gas configuration in brackets (e.g., [Ar] for argon) and then add the electrons in the shells beyond it.
For example, neutral scandium (Sc) has an electron configuration of [Ar] 3d鹿 4s虏, meaning after reaching the configuration of argon, it has one more electron in the 3d subshell and two more in the 4s subshell. These notations are pivotal for determining the arrangement of electrons when elements become ions.
Cation Electron Loss
When an atom loses electrons to become a cation, this process usually begins with the electrons in the outermost shell. For transition metals, like the ones in the exercise, it鈥檚 common to start losing electrons from the 4s subshell before the 3d, even though 4s is filled before 3d.For instance, if scandium becomes \( \mathrm{Sc}^{3+} \), it loses three electrons. This results in a configuration of just [Ar], as the 3d鹿 and 4s虏 electrons are removed. Such an electron loss rearrangement is crucial for correctly predicting the magnetic and chemical properties of transition metal cations.
Transition Metals
Transition metals are unique because they involve filling their d subshells, which can lead to complex electron arrangements and magnetic properties. These elements can exhibit multiple oxidation states and can form colored compounds due to the d-d electron transitions.When forming cations, transition metals often have unpaired d electrons. This is because the 3d subshell is not fully filled, even after losing 4s electrons, thus often leaving some electrons unpaired. For example, when cobalt becomes \( \mathrm{Co}^{2+} \), it retains a 3d鈦 configuration with some unpaired electrons that significantly influence its magnetic properties.
Electron Pairing
Electron pairing within a subshell involves placing two electrons in one orbital, which is possible due to their opposite spins. However, the more electrons in the d subshell, the more complex the pairing situation becomes.For cations like \( \mathrm{Mn}^{3+} \) with a 3d鈦 configuration, pairing depends on how the d orbitals are filled, often reflected in the crystal field theory model. It predicts the splitting of d orbitals into t鈧俫 and e鈧檊 sets in environments like octahedral complexes. This split impacts not just chemical bonding but also the number of unpaired electrons, affecting the magnetic behavior of the element.