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Consider the decomposition of gaseous \(\mathrm{N}_{2} \mathrm{O}_{4}\) : $$\mathrm{N}_{2} \mathrm{O}_{4}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) \quad \Delta H^{\circ}=+55.3 \mathrm{~kJ} ; \Delta S^{\circ}=+175.7 \mathrm{~J} / \mathrm{K}$$ (a) Is this reaction spontaneous under standard-state conditions at \(25^{\circ} \mathrm{C} ?\) (b) Estimate the temperature at which the reaction becomes spontaneous.

Short Answer

Expert verified
(a) No, it is not spontaneous at 25°C. (b) It becomes spontaneous above 314.8 K.

Step by step solution

01

Understand the Gibbs Free Energy Change Equation

The Gibbs Free Energy change (\( \Delta G^{\circ} \)) for a reaction is given by the equation: \( \Delta G^{\circ} = \Delta H^{\circ} - T \Delta S^{\circ} \). Here, \( \Delta H^{\circ} \) is the change in enthalpy, \( \Delta S^{\circ} \) is the change in entropy, and \( T \) is the temperature in Kelvin.
02

Convert Units and Calculate Spontaneity at 25°C

First, convert the entropy change from J to kJ to match the units of enthalpy: \( \Delta S^{\circ} = 0.1757 \) kJ/K. Using \( T= 298 \) K (since 25°C is 298 K), calculate \( \Delta G^{\circ} \) using \( \Delta G^{\circ} = 55.3 \text{ kJ} - 298 \times 0.1757 \text{ kJ/K} \). This gives \( \Delta G^{\circ} = 2.8886 \text{ kJ} \). Since \( \Delta G^{\circ} > 0 \), the reaction is not spontaneous at 25°C.
03

Determine Temperature for Spontaneity

A reaction becomes spontaneous when \( \Delta G^{\circ} \leq 0 \). Set \( \Delta G^{\circ} = 0 \), and solve for \( T \) using \( 0 = \Delta H^{\circ} - T \Delta S^{\circ} \), or \( T = \frac{\Delta H^{\circ}}{\Delta S^{\circ}} \). With \( \Delta H^{\circ} = 55.3 \) kJ and \( \Delta S^{\circ} = 0.1757 \) kJ/K, \( T = \frac{55.3}{0.1757} \approx 314.8 \) K. Thus, the reaction becomes spontaneous at temperatures above 314.8 K.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spontaneity
In the context of chemical reactions, spontaneity refers to the natural tendency of a process to occur without the need for external energy. A spontaneous reaction proceeds on its own under given conditions. To assess the spontaneity of a reaction, we use the Gibbs Free Energy change (\( \Delta G^{\circ} \)) as a key indicator.
When \( \Delta G^{\circ} \) is negative, the reaction is considered spontaneous, meaning it happens naturally. However, if \( \Delta G^{\circ} \) is positive, the reaction is not spontaneous under those conditions and requires an input of energy to occur.
This free energy change takes into account both the changes in enthalpy and entropy, alongside the temperature at which the reaction is occurring. Understanding these factors allows us to predict whether a given reaction can happen spontaneously at a specific temperature.
Enthalpy
Enthalpy (\( \Delta H^{\circ} \)), in simple terms, is a measure of the total heat content in a system. It reflects the heat absorbed or released during a chemical reaction, under constant pressure.
For the decomposition of \( \text{N}_2\text{O}_4 \) into \( \text{NO}_2 \), an enthalpy change of \( +55.3 \text{ kJ} \) indicates that the reaction absorbs heat from its surroundings.
This endothermic process requires energy input, as suggested by the positive enthalpy change. While a reaction with negative enthalpy (\( \Delta H^{\circ} < 0 \)) typically favors spontaneity, one with a positive enthalpy often needs a boost in temperature or must be driven by favorable entropy changes to become spontaneous.
Entropy
Entropy (\( \Delta S^{\circ} \)) is a measure of disorder or randomness within a system. When a system becomes more disordered, its entropy increases, as seen in the decomposition reaction where \( \text{N}_2\text{O}_4 \) transforms into two \( \text{NO}_2 \) molecules.
An increase in entropy (\( \Delta S^{\circ} > 0 \)) generally promotes spontaneity in a chemical reaction because Nature tends to favor states of higher disorder.
In our example, the positive entropy change of \( +175.7 \text{ J/K} \) suggests increased molecular disorder - two molecules of \( \text{NO}_2 \) are more disordered compared to one molecule of \( \text{N}_2\text{O}_4 \). As such, a significant entropy change can counteract an unfavorable enthalpy change, making a reaction spontaneous at sufficiently high temperatures.
Reaction Temperature
Temperature plays a crucial role in determining the spontaneity of a reaction. As characterized by the Gibbs Free Energy equation: \( \Delta G^{\circ} = \Delta H^{\circ} - T\Delta S^{\circ} \), temperature (\( T \)) directly affects the balance between enthalpy and entropy contributions.
In the case of the decomposition of \( \text{N}_2\text{O}_4 \), the temperature at which the reaction becomes spontaneous is calculated to be above \( 314.8 \text{ K} \).
At temperatures higher than this threshold, the entropy term (\( T \Delta S^{\circ} \)) outweighs the positive enthalpy change, making \( \Delta G^{\circ} \) negative and the reaction spontaneous. Therefore, understanding the interplay between entropy, enthalpy, and temperature is vital in manipulating and predicting the conditions required for reactions to occur naturally.

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Most popular questions from this chapter

Give an equation that relates the entropy change in the surroundings to the enthalpy change in the system. What is the sign of \(\Delta S_{\text {surr }}\) for the following? (a) An exothermic reaction (b) An endothermic reaction

Which state in each of the following pairs has the higher entropy per mole of substance? (a) Ice at \(-40^{\circ} \mathrm{C}\) or ice at \(0^{\circ} \mathrm{C}\) (b) \(\mathrm{N}_{2}\) at STP or \(\mathrm{N}_{2}\) at \(0{ }^{\circ} \mathrm{C}\) and \(10 \mathrm{~atm}\) (c) \(\mathrm{N}_{2}\) at STP or \(\mathrm{N}_{2}\) at \(0{ }^{\circ} \mathrm{C}\) in a volume of \(50 \mathrm{~L}\) (d) Water vapor at \(150^{\circ} \mathrm{C}\) and 1 atm or water vapor at \(100{ }^{\circ} \mathrm{C}\) and \(2 \mathrm{~atm}\)

Tell whether the following processes are spontaneous or nonspontaneous: (a) Dissolving sugar in hot coffee (b) Decomposition of \(\mathrm{NaCl}\) to solid sodium and gaseous chlorine at \(25^{\circ} \mathrm{C}\) and 1 atm pressure (c) Uniform mixing of bromine vapor and nitrogen gas (d) Boiling of gasoline at \(25^{\circ} \mathrm{C}\) and 1 atm pressure

Consider the gas-phase reaction of \(\mathrm{AB}_{3}\) and \(\mathrm{A}_{2}\) molecules: (a) Write a balanced equation for the reaction. (b) What is the sign of the entropy change for the reaction?

Predict the sign of the entropy change in the system for each of the following processes: (a) A solid sublimes (b) A liquid freezes (c) AgI precipitates from a solution containing \(\mathrm{Ag}^{+}\) and \(\mathrm{I}^{-}\) ions (d) Gaseous \(\mathrm{CO}_{2}\) bubbles out of a carbonated beverage

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