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Calculate the percent dissociation of \(0.10 \mathrm{M}\) hydrazoic acid \(\left(\mathrm{HN}_{3}, K_{\mathrm{a}}=1.9 \times 10^{-5}\right) .\) Recalculate the percent dissociation of \(0.10 \mathrm{M} \mathrm{HN}_{3}\) in the presence of \(0.10 \mathrm{M} \mathrm{HCl}\), and explain the change.

Short Answer

Expert verified
Percent dissociation without HCl is approximately 1.378%. With 0.10 M HCl, dissociation is negligible due to the common ion effect.

Step by step solution

01

Understand the Concept of Percent Dissociation

Percent dissociation refers to the percentage of the initial concentration of a weak acid that dissociates into its ions in solution. For a weak acid HA, dissociation in water is given by the equation: \( \text{HA} \rightleftharpoons \text{H}^+ + \text{A}^- \).
02

Set Up the Initial Expression for Dissociation

For the initial concentration of hydrazoic acid \( [\text{HN}_3] = 0.10 \; \text{M} \), we set up an equilibrium expression: \( [\text{HN}_3] \rightleftharpoons [\text{H}^+] + [\text{N}_3^-] \). The change in concentration at equilibrium is given by \( x \), where \( x \) is the concentration of ions formed.
03

Write the Equilibrium Expression

Using the given \( K_a \), the equilibrium expression for dissociation is:\[ K_a = \frac{[\text{H}^+][\text{N}_3^-]}{[\text{HN}_3]} = 1.9 \times 10^{-5} \]Substitute the equilibrium concentrations: \[ K_a = \frac{x^2}{0.10 - x} \]
04

Approximate and Solve for x

Since \( K_a \) is small, assume \( x \ll 0.10 \), so \( 0.10 - x \approx 0.10 \). Thus, the equation simplifies to:\[ x^2 = (0.10)(1.9 \times 10^{-5}) \]Solve for \( x \):\[ x = \sqrt{1.9 \times 10^{-6}} \approx 1.378 \times 10^{-3} \; \text{M} \]
05

Calculate Percent Dissociation

Percent dissociation is calculated as:\[ \text{Percent Dissociation} = \left( \frac{x}{0.10} \right) \times 100 \approx 1.378 \% \]
06

Recalculate Percent Dissociation with HCl

In the presence of \(0.10 \; \text{M} \; \text{HCl}\), \([\text{H}^+]\) from \text{HCl} is added to the mixture. Total \([\text{H}^+]\) is approximately \(0.10 \; \text{M}\). Since \([\text{H}^+]\) from \text{HCl} is much larger than \(x\), additional dissociation of \text{HN}_3 is negligible, leading to minimal further dissociation.
07

Explain the Change in Percent Dissociation

The percent dissociation of \( \text{HN}_3 \) decreases significantly in the presence of \( \text{HCl} \) due to the common ion effect. The initial concentration of \( [\text{H}^+] \) is already high in the solution due to \( \text{HCl} \), thus suppressing the further dissociation of weak acid \( \text{HN}_3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Ion Effect
The common ion effect occurs when a solution containing a weak acid is mixed with a strong acid or salt that shares a common ion. This effect reduces the dissociation of the weak acid. In our example, adding HCl to the hydrazoic acid solution introduces more H鈦 ions, which are common between both acids.
This additional concentration of H鈦 ions shifts the equilibrium position to favor the undissociated form of hydrazoic acid (HN鈧).

This happens because, according to Le Chatelier's Principle, the system will adjust to minimize the disturbance (additional H鈦). As a result, less HN鈧 dissociates, and the dissociation percentage decreases.
  • Reduces the ionization of the weak acid.
  • Adds a common ion, increasing the concentration of H鈦.
  • Shifts equilibrium towards the non-dissociated acid.
Weak Acid Dissociation
Weak acids like hydrazoic acid ( HN鈧) only partially dissociate in solutions. Unlike strong acids, which fully dissociate, weak acids reach an equilibrium between the dissociated ions and the undissociated molecules.
For hydrazoic acid, the dissociation can be represented as:
HN鈧 鈫 H鈦 + N鈧冣伝.
This means that not all of the acid molecules release H鈦 ions into the solution.

The extent of dissociation is crucial to understand as it affects calculations like percent dissociation. In the absence of other influencing factors, this dissociation is determined by the inherent acid strength, captured by its acid dissociation constant (K鈧).
  • Partial dissociation of weak acids.
  • Equilibrium between dissociated and undissociated forms.
Equilibrium Expression
The equilibrium expression is crucial in understanding how concentration changes affect the dissociation process in weak acids.
For hydrazoic acid, the equilibrium expression is:\[ K_a = \frac{[\text{H}^+][\text{N}_3^-]}{[\text{HN}_3]} \]
This formula relates the concentrations of ions produced to the original acid concentration.

In calculations, this expression helps evaluate how changes in conditions, like adding a common ion, shift the equilibrium.
By understanding how to substitute values for concentrations at equilibrium, you can solve for unknowns like the concentration of hydrogen ions ([H鈦篯).
  • Relates ion concentrations to original acid amount.
  • Essential for calculating dissociation ratios.
  • Helps predict behavior under different conditions.
Acid Dissociation Constant (Ka)
The acid dissociation constant (K鈧) is a key metric that defines the strength of a weak acid. It quantifies the extent to which an acid dissociates in solution. A smaller K鈧 value indicates that the acid only partially dissociates, typical of weak acids like hydrazoic acid.

In our example, the given K鈧 is \(1.9 \times 10^{-5}\). This shows that hydrazoic acid is a weak acid since this value is small.
The K鈧 value allows us to set up the equilibrium expression and solve for the changes in concentrations at equilibrium.
  • Defines the dissociation level of an acid.
  • Smaller values indicate weaker acids.
  • Essential for equilibrium calculations.

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Most popular questions from this chapter

Which of the following compounds are more soluble in acidic solution than in pure water? (a) \(\mathrm{AgCN}\) (b) \(\mathrm{PbI}_{2}\) (c) \(\mathrm{Al}(\mathrm{OH})_{3}\) (d) \(\mathrm{ZnS}\)

A \(40.0 \mathrm{~mL}\) volume of \(0.100 \mathrm{M} \mathrm{NaOH}\) is titrated with \(0.0500 \mathrm{M} \mathrm{HCl}\). Calculate the \(\mathrm{pH}\) after addition of the following volumes of acid: (a) \(60.0 \mathrm{~mL}\) (b) \(80.2 \mathrm{~mL}\) (c) \(100.0 \mathrm{~mL}\)

On the same graph, sketch pH titration curves for the titration of \((1)\) a strong acid with a strong base and (2) a weak acid with a strong base. How do the two curves differ with respect to the following? (a) The initial \(\mathrm{pH}\) (b) The \(\mathrm{pH}\) in the region between the start of the titration and the equivalence point (c) The \(\mathrm{pH}\) at the equivalence point (d) The \(\mathrm{pH}\) beyond the equivalence point (e) The volume of base required to reach the equivalence point

Consider a buffer solution that contains equal concentrations of \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) and \(\mathrm{HPO}_{4}^{2-}\). Will the \(\mathrm{pH}\) increase, decrease, or remain the same when each of the following substances is added? (a) \(\mathrm{Na}_{2} \mathrm{HPO}_{4}\) (b) \(\mathrm{HBr}\) (c) \(\mathrm{KOH}\) (d) \(\mathrm{KI}\) (e) \(\mathrm{H}_{3} \mathrm{PO}_{4}\) (f) \(\mathrm{Na}_{3} \mathrm{PO}_{4}\)

In qualitative analysis, \(\mathrm{Ca}^{2+}\) and \(\mathrm{Ba}^{2+}\) are separated from \(\mathrm{Na}^{+}, \mathrm{K}^{+}\), and \(\mathrm{Mg}^{2+}\) by adding aqueous \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3}\) to a solution that also contains aqueous \(\mathrm{NH}_{3}\) (Figure 16.18). Assume that the concentrations after mixing are \(0.080 \mathrm{M}\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3}\) and \(0.16 \mathrm{M} \mathrm{NH}_{3}\). (a) List all the Br酶nsted-Lowry acids and bases present initially, and identify the principal reaction. (b) Calculate the \(\mathrm{pH}\) and the concentrations of all species present in the solution. (c) In order for the human eye to detect the appearance of a precipitate, a very large number of ions must come together to form solid particles. For this and other reasons, the ion product must often exceed \(K_{\mathrm{sp}}\) by a factor of about \(10^{3}\) before a precipitate can be detected in a typical qualitative analysis experiment. Taking this fact into account, show quantitatively that the \(\mathrm{CO}_{3}{ }^{2-}\) concentration is large enough to give observable precipitation of \(\mathrm{CaCO}_{3}\) and \(\mathrm{BaCO}_{3}\), but not \(\mathrm{MgCO}_{3}\). Assume that the metal-ion concentrations are \(0.010 \mathrm{M}\). (d) Show quantitatively which of the \(\mathrm{Mg}^{2+}, \mathrm{Ca}^{2+}\), and \(\mathrm{Ba}^{2+}\) ions, if any, should give an observable precipitate of the metal hydroxide. (e) Could the separation of \(\mathrm{Ca}^{2+}\) and \(\mathrm{Ba}^{2+}\) from \(\mathrm{Mg}^{2+}\) be accomplished using \(0.80 \mathrm{M} \mathrm{Na}_{2} \mathrm{CO}_{3}\) in place of \(0.080 \mathrm{M}\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3} ?\) Show quantitatively why or why not.

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