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Solid particles that form in the kidney are called kidney stones and frequently cause acute pain. One common type of kidney stone is formed from a precipitation reaction of calcium and oxalate: $$ \mathrm{Ca}^{2+}(a q)+\mathrm{C}_{2} \mathrm{O}_{4}^{2-}(a q) \rightleftharpoons \mathrm{CaC}_{2} \mathrm{O}_{4}(s) $$ Use Le Ch芒telier's principle to explain the following statements. (a) A person taking diuretics, medicines that help kidneys remove fluids, may be at increased risk for developing kidney stones. (b) A person diagnosed with hypercalciuria, a genetic condition causing elevated levels of calcium in the urine, has an increased risk for developing kidney stones. (c) One simple treatment for kidney stones is to avoid foods high in oxalate such as spinach, rhubarb, and nuts. (d) Another simple treatment for kidney stones is to increase consumption of water.

Short Answer

Expert verified
Diuretics and high ion concentrations increase stone risk; high water intake reduces it.

Step by step solution

01

Understanding Le Ch芒telier's Principle

Le Ch芒telier's principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium will shift to counteract the change and restore a new equilibrium.
02

Explanation for Taking Diuretics

Diuretics increase the removal of fluids from the body, reducing the overall volume of solvent in the urine. According to Le Ch芒telier's principle, reducing the solvent amount drives the equilibrium towards the formation of the solid, in this case, kidney stones.
03

Explanation for Hypercalciuria

Hypercalciuria leads to elevated levels of calcium in the urine. Le Ch芒telier's principle indicates that an increase in the concentration of reactants (Ca虏鈦 ions) will shift the equilibrium towards the formation of more CaC鈧侽鈧(s), increasing kidney stone formation.
04

Effect of High Oxalate Foods

Consuming foods high in oxalate increases the concentration of C鈧侽鈧劼猜 ions in the urine. Le Ch芒telier's principle suggests that increasing the concentration of a reactant causes the reaction to shift towards the formation of kidney stones.
05

Effect of Increased Water Consumption

Drinking more water increases the volume of solvent in which the ions are dissolved, effectively diluting their concentrations. According to Le Ch芒telier's principle, this dilution shifts the equilibrium away from forming solids, thus reducing the risk of kidney stones.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kidney Stones
Kidney stones are hard solid deposits that form inside the kidneys, and they can cause significant pain. They often develop when certain substances in urine, like calcium and oxalate, become concentrated and crystallize.
When these crystals gather and fuse together, they form stones. These kidney stones can vary in size, from as small as a grain of sand to as large as a golf ball. The process of stone formation can be explained using the concept of a precipitation reaction, where dissolved substances transform into a solid.
This poses a particular issue when urine becomes highly saturated with stone-forming ions.
Precipitation Reaction
A precipitation reaction occurs when two dissolved ions in aqueous solution react to form an insoluble solid, known as a precipitate. In the case of kidney stones, calcium ions ( \( ext{Ca}^{2+} \) ) and oxalate ions ( \( ext{C}_{2} ext{O}_{4}^{2-} \) ) can combine to create calcium oxalate ( \( ext{CaC}_{2} ext{O}_{4}(s) \) ), a solid precipitate.
This reaction can be influenced by changing conditions, as described by Le Ch芒telier's principle. When the concentration of calcium or oxalate ions increases significantly in the urine, the equilibrium shifts toward forming more of the solid ( \( ext{CaC}_{2} ext{O}_{4}(s) \) ), promoting the formation of kidney stones.
Understanding how these reactions work is crucial in determining how to prevent and treat kidney stones.
Chemical Equilibrium
Chemical equilibrium is a dynamic state where the rates of the forward and reverse reactions are equal, resulting in no net change in the concentration of reactants and products. For kidney stones formation, the reaction can be represented as: \[ \text{Ca}^{2+}(aq) + \text{C}_{2}\text{O}_{4}^{2-}(aq) \rightleftharpoons \text{CaC}_{2}\text{O}_{4}(s) \]
If the equilibrium is disturbed by an increase in reactants, such as higher levels of calcium or oxalate, the reaction shifts towards more solid product formation, according to Le Ch芒telier鈥檚 Principle.
Each time the concentration of solutes like calcium or oxalate increases in the urine, it moves the equilibrium further towards the formation of kidney stones, which is why managing these concentrations is crucial.
Hypercalciuria
Hypercalciuria is a condition characterized by high levels of calcium present in the urine. This can result from dietary choices, certain medications, or genetic factors. Large amounts of calcium in the urine can severely disrupt the chemical equilibrium, making the precipitation of calcium oxalate more likely.
As Le Ch芒telier's principle indicates, increasing calcium levels means there are more reactants available in the urine, which shifts the equilibrium toward forming more calcium oxalate stones.
  • Elevated calcium levels cause the body to take steps that result in more solid formation.
  • Managing dietary calcium intake and staying hydrated can help manage hypercalciuria.
This condition is a significant risk factor for kidney stone development, emphasizing the need for careful dietary and medical management.

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Most popular questions from this chapter

An equilibrium mixture of \(\mathrm{PCl}_{5}, \mathrm{PCl}_{3}\), and \(\mathrm{Cl}_{2}\) at a certain temperature contains \(8.3 \times 10^{-3} \mathrm{M} \mathrm{PCl}_{5}, 1.5 \times 10^{-2} \mathrm{M} \mathrm{PCl}_{3}\) and \(3.2 \times 10^{-2} \mathrm{M} \mathrm{Cl}_{2} .\) Calculate the equilibrium constant \(K_{c}\) for the reaction \(\mathrm{PCl}_{5}(g) \rightleftharpoons \mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g) .\)

Ethylene glycol, used as antifreeze in automobile radiators, is manufactured by the hydration of ethylene oxide. Write the equilibrium constant expression for \(K_{c}\) \(\mathrm{O}\) \(\mathrm{H}_{2} \mathrm{C}-\mathrm{CH}_{2}(\mathrm{soln})+\mathrm{H}_{2} \mathrm{O}(\mathrm{soln}) \rightleftharpoons \mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH}(\mathrm{soln})\)

When each of the following equilibria is disturbed by increasing the pressure as a result of decreasing the volume, does the number of moles of reaction products increase, decrease, or remain the same? (a) \(2 \mathrm{CO}_{2}(g) \rightleftharpoons 2 \mathrm{CO}(g)+\mathrm{O}_{2}(g)\) (b) \(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}(g)\) (c) \(\mathrm{Si}(s)+2 \mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{SiCl}_{4}(g)\)

For each of the following equilibria, write the equilibrium constant expression for \(K_{c}\). Where appropriate, also write the equilibrium constant expression for \(K_{\mathrm{p}^{-}}\) (a) \(\mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{CO}(g) \rightleftharpoons 2 \mathrm{Fe}(l)+3 \mathrm{CO}_{2}(g)\) (b) \(4 \mathrm{Fe}(s)+3 \mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{Fe}_{2} \mathrm{O}_{3}(s)\) (c) \(\mathrm{BaSO}_{4}(s) \rightleftharpoons \mathrm{BaO}(s)+\mathrm{SO}_{3}(g)\) (d) \(\mathrm{BaSO}_{4}(s) \rightleftharpoons \mathrm{Ba}^{2+}(a q)+\mathrm{SO}_{4}^{2-}(a q)\)

The first step in the industrial synthesis of hydrogen is the reaction of steam and methane to give synthesis gas, a mixture of carbon monoxide and hydrogen: \(\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{CH}_{4}(g) \rightleftharpoons \mathrm{CO}(g)+3 \mathrm{H}_{2}(g) \quad K_{c}=4.7\) at \(1400 \mathrm{~K}\) A mixture of reactants and products at \(1400 \mathrm{~K}\) contains \(0.035\) \(\mathrm{M} \mathrm{H}_{2} \mathrm{O}, 0.050 \mathrm{M} \mathrm{CH}_{4}, 0.15 \mathrm{M} \mathrm{CO}\), and \(0.20 \mathrm{M} \mathrm{H}_{2}\). In which di- rection does the reaction proceed to reach equilibrium?

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