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Nitrogen dioxide, a pollutant that contributes to photochemical smog, is formed by a series of two reactions. $$ \begin{array}{ll} \mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) & \rightleftharpoons 2 \mathrm{NO}(g) & K_{\mathrm{cl}}=4.3 \times 10^{-25} \\ 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) & \rightleftharpoons 2 \mathrm{NO}_{2}(g) & K_{c 2}=6.4 \times 10^{9} \\ \hline \mathrm{N}_{2}(g)+2 \mathrm{O}_{2}(g) & \rightleftharpoons 2 \mathrm{NO}_{2}(g) & K_{c}(\text { overall })=? \end{array} $$ (a) Write the equilibrium constant expression for the overall reaction. (b) What is the value of \(K_{c}\) (overall)?

Short Answer

Expert verified
\( K_c \text{ (overall)} = 2.752 \times 10^{-14} \).

Step by step solution

01

Understand the given reactions

The problem provides two sequential chemical reactions that lead to the formation of nitrogen dioxide (NOâ‚‚) from nitrogen (Nâ‚‚) and oxygen (Oâ‚‚). The equilibrium constants for these reactions are given as \( K_{c1} = 4.3 \times 10^{-25} \) for the production of NO from Nâ‚‚ and Oâ‚‚, and \( K_{c2} = 6.4 \times 10^{9} \) for the conversion of NO to NOâ‚‚.
02

Understand the overall reaction

The overall reaction can be expressed as: \( \mathrm{N}_{2}(g) + 2 \mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}_{2}(g) \). This is the sum of the two given reactions.
03

Calculate the equilibrium constant for the overall reaction

The equilibrium constant \( K_c \) for a series of reactions can be found by multiplying the equilibrium constants of the individual reactions. Thus, \( K_c \text{ (overall)} = K_{c1} \times K_{c2} \).
04

Substitute the known values

Substitute the given values into the equation: \[ K_c \text{ (overall)} = (4.3 \times 10^{-25}) \times (6.4 \times 10^{9}) \].
05

Perform the calculation

Calculate the value: \[ K_c \text{ (overall)} = 4.3 \times 6.4 \times 10^{-25 + 9} = 27.52 \times 10^{-16} = 2.752 \times 10^{-14}. \]
06

Conclusion

The equilibrium constant for the overall reaction \( K_c \text{ (overall)} \) is \( 2.752 \times 10^{-14}. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant
In chemical reactions, the equilibrium constant, denoted as \( K_c \), is a vital parameter that tells us about the balance between products and reactants when a reaction reaches equilibrium.

Simply put, it describes the ratio of product concentrations to reactant concentrations, each raised to the power of their coefficients in the balanced equation, at equilibrium.
For a balanced reaction \( aA + bB \rightleftharpoons cC + dD \), the equilibrium constant expression is:
\[ K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b} \]
This means if \( K_c \) is large, the equilibrium lies towards the products, whereas a small \( K_c \) indicates more reactants are present at equilibrium.

Calculating \( K_c \) for a sequence of reactions involves multiplying the \( K_c \) values of individual steps.
In the case of nitrogen dioxide formation, we found \( K_c \text{ (overall)} = 2.752 \times 10^{-14} \), suggesting more reactants than products.
Reaction Mechanism
A reaction mechanism outlines the step-by-step sequence of elementary reactions by which overall chemical change occurs. It provides insight into how reactants transform into products.

For example, the formation of nitrogen dioxide \( \text{NO}_2 \), a key player in the development of photochemical smog, occurs in two steps:
  • Step 1: \( \mathrm{N}_2(g) + \mathrm{O}_2(g) \rightleftharpoons 2\mathrm{NO}(g) \) with \( K_{c1} = 4.3 \times 10^{-25} \)
  • Step 2: \( 2\mathrm{NO}(g) + \mathrm{O}_2(g) \rightleftharpoons 2\mathrm{NO}_2(g) \) with \( K_{c2} = 6.4 \times 10^{9} \)
Each elementary reaction has its own rate law, and the sequence ensures our understanding of molecules interacting at a given stage.

Understanding the mechanism helps in designing strategies to control reactions, especially those producing environmental pollutants like \( \text{NO}_2 \).
Nitrogen Dioxide Formation
Nitrogen dioxide (\( \text{NO}_2 \)) formation is crucial in environmental chemistry due to its impact on air quality.

It forms through the oxidation of nitrogen monoxide (\( \text{NO} \)), an intermediate in air pollution processes. The sequence is:
  • First Reaction: Nitrogen and oxygen react to form nitrogen monoxide \( \text{NO} \).
  • Second Reaction: \( \text{NO} \) further reacts with oxygen to create \( \text{NO}_2 \).
This process signifies how seemingly harmless substances like \( \text{N}_2 \) and \( \text{O}_2 \) in the atmosphere undergo chemical transformations to form pollutants.

These reactions have significant temperature and pressure dependence, affecting their rates and equilibrium constant values. Understanding these aspects is important in regulating \( \text{NO}_2 \) levels, which, in high concentrations, can lead to respiratory issues.
Photochemical Smog
Photochemical smog is a type of air pollution created when sunlight reacts with pollutants like nitrogen oxides and volatile organic compounds in the atmosphere.

It's known for its harmful effects on human health, visibility, and the environment.
Key to smog formation is \( \text{NO}_2 \), which plays a dual role:
  • Directly contributes to smog by scattering sunlight, giving smog its characteristic brownish color.
  • Participates in reactions that form ozone (\( \text{O}_3 \)), another harmful component of smog.
The cyclical reaction involving \( \text{NO} \) and \( \text{NO}_2 \), combined with hydrocarbons, leads to a persistent formation of more pollutants under sunlight.

Strategies to reduce smog include regulating emissions from vehicles and industrial sources, aiming to limit the atmospheric concentrations of \( \text{NO}_2 \) and other precursors.

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Most popular questions from this chapter

At \(500^{\circ} \mathrm{C}, \mathrm{F}_{2}\) gas is stable and does not dissociate, but at \(840^{\circ} \mathrm{C}\), some dissociation occurs: \(\mathrm{F}_{2}(g) \rightleftharpoons 2 \mathrm{~F}(g) .\) A flask filled with \(0.600\) atm of \(\mathrm{F}_{2}\) at \(500^{\circ} \mathrm{C}\) was heated to \(840^{\circ} \mathrm{C}\), and the pressure at equilibrium was measured to be \(0.984\) atm. What is the equilibrium constant \(K_{\mathrm{p}}\) for the dissociation of \(\mathrm{F}_{2}\) gas at \(840^{\circ} \mathrm{C} ?\)

At \(100^{\circ} \mathrm{C}, K_{c}=4.72\) for the reaction \(2 \mathrm{NO}_{2}(g) \rightleftharpoons \mathrm{N}_{2} \mathrm{O}_{4}(g) .\) An empty \(10.0 \mathrm{~L}\) flask is filled with \(4.60 \mathrm{~g}\) of \(\mathrm{NO}_{2}\) at \(100^{\circ} \mathrm{C}\). What is the total pressure in the flask at equilibrium?

Does the number of moles of products increase, decrease, or remain the same when each of the following equilibria is subjected to an increase in pressure by decreasing the volume? (a) \(\mathrm{CO}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}_{2}(g)+\mathrm{H}_{2}(g)\) (b) \(2 \mathrm{CO}(g) \rightleftharpoons \mathrm{C}(s)+\mathrm{CO}_{2}(g)\) (c) \(\mathrm{N}_{2} \mathrm{O}_{4}(g) \rightleftharpoons 2 \mathrm{NO}_{2}(g)\)

Which direction will the equilibrium reaction of hemoglobin and oxygen shift as temperature increases in the muscles during intense exercise? Does the effect of temperature on equilibrium position help muscles acquire the oxygen they need? $$ \mathrm{Hb}+4 \mathrm{O}_{2} \rightleftharpoons \mathrm{Hb}\left(\mathrm{O}_{2}\right)_{4} \quad \Delta \mathrm{H}=-200 \mathrm{~kJ} / \mathrm{mol} $$

The reaction of fumarate (Problem \(14.143\) ) with water to form L-malate is catalyzed by the enzyme fumarase; \(K_{c}=3.3\) at \(37^{\circ} \mathrm{C}\). When a reaction mixture with [fumarate] \(=1.56 \times 10^{-3} \mathrm{M}\) and [L-malate] \(=2.27 \times 10^{-3} \mathrm{M}\) comes to equilibrium in the presence of fumarase at \(37{ }^{\circ} \mathrm{C}\), what are the equilibrium concentrations of fumarate and L-malate? (Water can be omitted from the equilibrium equation because its concentration in dilute solutions is essentially the same as that in pure water.)

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