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The value of \(\Delta H^{\circ}\) for the reaction \(3 \mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{O}_{3}(g)\) is \(+285 \mathrm{~kJ} .\) Does the equilibrium constant for this reaction increase or decrease when the temperature increases? Justify your answer using Le Châtelier's principle.

Short Answer

Expert verified
The equilibrium constant increases as temperature increases due to the endothermic nature of the reaction.

Step by step solution

01

Understand the Reaction and Given Data

The reaction involves the conversion of oxygen gas (\(\mathrm{O}_2\)) to ozone (\(\mathrm{O}_3\)). The enthalpy change for this reaction, \(\Delta H^{\circ}\), is positive \(+285\) kJ, indicating that the reaction is endothermic.
02

Apply Le Châtelier's Principle

Le Châtelier's principle states that if a system at equilibrium is subjected to a change in temperature, pressure, or concentration, the system will adjust to counteract the change. For an endothermic reaction (where \(\Delta H^{\circ} > 0\)), increasing the temperature will shift the equilibrium to the right, favoring the formation of products in order to absorb the added heat.
03

Determine the Effect on the Equilibrium Constant

Since increasing the temperature shifts the equilibrium to the right (toward the products \(\mathrm{O}_3\)), the equilibrium constant \(K\) for the reaction will increase. This is because \(K\) is defined by the ratio of the concentrations of products to reactants, and an increase in the formation of products means an increase in \(K\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant
The equilibrium constant, symbolized as either \( K_c \) or \( K_p \) depending on whether concentrations or partial pressures are used, quantifies the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction. It provides insight into the position of equilibrium:
  • If \( K \) is large, the equilibrium position is toward the products.
  • If \( K \) is small, it is toward the reactants.
The equilibrium constant is only affected by changes in temperature and not by concentration, pressure, or catalysts. It is essential in predicting how a change in conditions will affect the balance between products and reactants, especially in understanding Le Châtelier's principle. In essence, \( K \) helps predict the direction in which a reaction mixture will shift to restore equilibrium after a disturbance.
This particular reaction has an equilibrium constant that increases with increased temperature due to its endothermic nature.
Endothermic Reaction
An endothermic reaction is characterized by the absorption of heat during the conversion of reactants to products. This type of reaction has a positive enthalpy change \((\Delta H^{\circ} > 0)\). During such a reaction, energy is transferred from the surroundings into the system, which is a critical aspect to consider when analyzing how changes in conditions affect the reaction. Endothermic reactions require energy input, meaning the system 'takes in' heat to proceed, leading to product formation. A common example includes photosynthesis. Moreover, endothermic reactions are usually associated with reactions that feel cold to the touch, as they absorb surrounding heat.
For the reaction \(3 \mathrm{O}_2(g) \rightleftharpoons 2 \mathrm{O}_3(g)\), an increase in temperature provides the necessary energy to favor the forward reaction, hence producing more ozone \((\mathrm{O}_3)\).
Temperature Change Effect
When considering the effect of temperature changes on chemical equilibria, Le Châtelier's principle plays a pivotal role. It states that if a dynamic equilibrium experiences a change in temperature, the system will adjust to counteract that change and establish a new equilibrium.
In an endothermic reaction like \(3 \mathrm{O}_2(g) \rightleftharpoons 2 \mathrm{O}_3(g)\), increasing the temperature supplies more thermal energy, effectively shifting the equilibrium position to the right. This translates to more products being formed. As the reaction absorbs heat, it counteracts the temperature increase by utilizing the excessive heat for product formation.
Thus, higher temperatures facilitate a greater value of the equilibrium constant \(K\), indicating an increase in product concentration relative to reactants. This relationship is crucial for adjusting industrial processes to optimize yield by manipulating temperatures, always taking into account the reaction's nature regarding heat.

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Most popular questions from this chapter

A chemical engineer is studying reactions to produce \(\mathrm{SO}_{3}\) as a step in the manufacture of sulfuric acid. The value of \(K_{\mathrm{p}}\) for the reaction \(2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{SO}_{3}(g)\) is \(2.5 \times 10^{10}\) at \(500 \mathrm{~K}\). Will a mixture of \(\mathrm{SO}_{2}\) and \(\mathrm{O}_{2}\) produce much \(\mathrm{SO}_{3}\) when equilibrium is reached?

In the gas phase at \(400{ }^{\circ} \mathrm{C}\), isopropyl alcohol (rubbing alcohol) decomposes to acetone, an important industrial solvent: \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}(g) \rightleftharpoons\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}(g)+\mathrm{H}_{2}(g) \quad \Delta H^{\prime \prime}=+57.3 \mathrm{~kJ}\) Isopropyl akcahel Acetone Does the amount of acetone increase, decrease, or remain the same when an equilibrium mixture of reactants and products is subjected to the following changes? (a) The temperature is increased (b) The volume is increased (c) Argon is added (d) \(\mathrm{H}_{2}\) is added (e) A catalyst is added

When \(9.25 \mathrm{~g}\) of \(\mathrm{ClF}_{3}\) was introduced into an empty \(2.00 \mathrm{~L}\) container at \(700.0 \mathrm{~K}, 19.8 \%\) of the \(\mathrm{ClF}_{3}\) decomposed to give an equilibrium mixture of \(\mathrm{ClF}_{3}\), \(\mathrm{ClF}\), and \(\mathrm{F}_{2}\). $$ \mathrm{ClF}_{3}(g) \rightleftharpoons \mathrm{ClF}(g)+\mathrm{F}_{2}(g) $$ (a) What is the value of the equilibrium constant \(K_{c}\) at \(700.0 \mathrm{~K} ?\) (b) What is the value of the equilibrium constant \(K_{\mathrm{p}}\) at \(700.0 \mathrm{~K} ?\) (c) In a separate experiment, \(39.4 \mathrm{~g}\) of \(\mathrm{ClF}_{3}\) was introduced into an empty \(2.00 \mathrm{~L}\) container at \(700.0 \mathrm{~K}\). What are the concentrations of \(\mathrm{ClF}_{3}, \mathrm{ClF}\), and \(\mathrm{F}_{2}\) when the mixture reaches equilibrium?

For each of the following equilibria, write the equilibrium constant expression for \(K_{c}\) : (a) \(\mathrm{CH}_{4}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons \mathrm{CO}(g)+3 \mathrm{H}_{2}(g)\) (b) \(3 \mathrm{~F}_{2}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons 2 \mathrm{ClF}_{3}(g)\) (c) \(\mathrm{H}_{2}(g)+\mathrm{F}_{2}(g) \rightleftharpoons 2 \mathrm{HF}(g)\)

Ethyl acetate, a solvent used in many fingernail-polish removers, is made by the reaction of acetic acid with ethanol: \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}(\mathrm{soln})+\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}(\mathrm{soln}) \rightleftharpoons \mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}(\mathrm{soln})+\mathrm{H}_{2} \mathrm{O}(\) soln \() \quad \Delta H^{\circ}=-2.9 \mathrm{~kJ}\) \(\begin{array}{lll}\text { Acetic acid } & \text { Ethanol } & \text { Ethyl acetate }\end{array}\) Does the amount of ethyl acetate in an equilibrium mixture increase or decrease when the temperature is increased? How does \(K_{c}\) change when the temperature is decreased? Justify your answers using Le Châtelier's principle.

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