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The reaction \(\mathrm{NO}_{2}(g)+\mathrm{CO}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{CO}_{2}(g)\) occurs in one step. The activation energy is \(132 \mathrm{~kJ} / \mathrm{mol}\) and \(\Delta \mathrm{E}\) is \(-226 \mathrm{~kJ} / \mathrm{mol}\). (a) Is the reaction endothermic or exothermic? (b) What is the activation energy for the reverse reaction? (c) Does the reaction rate increase or decrease when temperature increases? Explain.

Short Answer

Expert verified
(a) Exothermic. (b) 358 kJ/mol. (c) Rate increases with temperature.

Step by step solution

01

Determine if the Reaction is Endothermic or Exothermic

An exothermic reaction releases energy, resulting in a negative change in enthalpy (abla \text{E}), whereas an endothermic reaction absorbs energy, resulting in a positive abla \text{E}. Here, \(abla \text{E} = -226 \text{ kJ/mol}\), indicating that energy is released from the system, making the reaction exothermic.
02

Calculate Activation Energy for the Reverse Reaction

To find the activation energy of the reverse reaction, we add the enthalpy change (abla \text{E}) to the forward activation energy (\(E_a\)). Thus, the activation energy for the reverse reaction is \(E_{a, \text{reverse}} = 132 \text{ kJ/mol} + 226 \text{ kJ/mol} = 358 \text{ kJ/mol}.\)
03

Analyze the Effect of Temperature on Reaction Rate

The rate of a chemical reaction generally increases with temperature because the molecules have greater kinetic energy, increasing the frequency and energy of collisions. According to the Arrhenius equation, \( k = A e^{-E_a/RT} \), where \( k \) is the rate constant, \( E_a \) is the activation energy, and \( T \) is the temperature in Kelvin, the rate constant \( k \) increases as temperature \( T \) increases, thus increasing the reaction rate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exothermic Reaction
An exothermic reaction is one where energy is released in the form of heat. This means the system loses energy, transferring it to the surroundings, often making the environment warmer. One way to identify an exothermic reaction is by looking at the change in enthalpy, \(\Delta E\), of the reaction.

* If \(\Delta E < 0\), it's negative, meaning the reaction releases energy, hence it is exothermic.

* If \(\Delta E > 0\), it's positive, indicating that the reaction absorbs energy, making it endothermic.

In the provided reaction \( \text{NO}_{2}(g) + \text{CO}(g) \rightarrow \text{NO}(g) + \text{CO}_{2}(g) \), \(\Delta E\) is \(-226 \, \text{kJ/mol}\). This negative value confirms that the reaction releases energy to its surroundings, thus it is classified as exothermic.
Reaction Rate
The reaction rate refers to how quickly a reactant is converted into a product. Various factors influence reaction rates, including temperature, concentration, and the presence of a catalyst.

When temperature increases, the molecules involved in the reaction gain kinetic energy, which leads to a higher frequency and energy of collisions. This often results in:
  • Increased likelihood of overcoming the activation energy barrier.
  • Faster overall conversion of reactants to products.
According to the Arrhenius equation, which we'll explore next, the rate constant \( k \) of a reaction increases with temperature. This directly results in increases in reaction rate. Warmer temperatures effectively "speed up" the reaction by making molecular interactions more frequent and energetic.
Arrhenius Equation
The Arrhenius equation is a formula that provides insight into how temperature affects the reaction rate. It's expressed as \( k = A e^{-E_a/RT} \), where:

* \( k \) is the rate constant, which increases as the reaction becomes faster.

* \( A \) is the pre-exponential factor, representing the number of successful collisions between reacting molecules.

* \( E_a \) is the activation energy, the energy barrier that must be overcome for a reaction to proceed.

* \( R \) is the universal gas constant.

* \( T \) is the temperature in Kelvin.

Increasing the temperature \( T \) reduces the negative exponent \( -E_a/RT \), causing an exponential increase in \( k \). This demonstrates that higher temperatures lead to greater chances of reactant molecules acquiring the necessary energy to surpass the activation energy barrier, thereby increasing the reaction rate. The Arrhenius equation elegantly quantifies this effect, highlighting the relationship between temperature and reactivity.

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Most popular questions from this chapter

For the one-step reaction \(\mathrm{NO}_{2}(g)+\mathrm{CO}(g) \longrightarrow\) \(\mathrm{NO}(g)+\mathrm{CO}_{2}(g)\), draw four possible ways that the two reactant molecules can collide. Which is most likely to result in a successful reaction?

The rate of the reaction \(\mathrm{A}+\mathrm{B}_{2} \rightarrow \mathrm{AB}+\mathrm{B}\) is directly proportional to the concentration of \(\mathrm{B}_{2}\), independent of the concentration of \(A\), and directly proportional to the concentration of a substance \(\mathrm{C}\). (a) What is the rate law? (b) Write a mechanism that agrees with the experimental facts. (c) What is the role of \(C\) in this reaction? Why doesn't \(C\) appear in the chemical equation for the overall reaction?

Beginning with the integrated rate law, derive a general equation for the half-life of a zeroth-order reaction of the type \(\mathrm{A} \rightarrow\) Products. How does the length of each half-life compare with the length of the previous one? Make the same comparison for firstorder and second-order reactions.

At elevated temperatures, nitrous oxide decomposes according to the equationGiven the following data, plot the appropriate graphs to determine whether the reaction is zeroth, first, or second order. What is the value of the rate constant for the consumption of \(\mathrm{N}_{2} \mathrm{O}\) ?$$ \begin{array}{llllll} \hline \text { Time (min) } & 0 & 60 & 90 & 300 & 600 \\ {\left[\mathbf{N}_{2} \mathrm{O}\right]} & 0.250 & 0.228 & 0.216 & 0.128 & 0.0630 \\ \hline \end{array} $$

The substitution reactions of molybdenum hexacarbonyl, \(\mathrm{Mo}(\mathrm{CO})_{6}\), with a variety of other molecules \(\mathrm{L}\) are believed to \(\mathrm{oc}-\) cur by the following mechanism: $$ \begin{aligned} &\mathrm{Mo}(\mathrm{CO})_{6} \stackrel{\mathrm{k}_{1}}{\longrightarrow} \mathrm{Mo}(\mathrm{CO})_{5}+\mathrm{CO} \\ &\mathrm{Mo}(\mathrm{CO})_{5}+\mathrm{L} \stackrel{k_{2}}{\longrightarrow} \mathrm{Mo}(\mathrm{CO})_{s} \mathrm{~L} \end{aligned} $$ (a) What is the overall reaction? (b) What is the molecularity of each of the elementary steps? (c) Write the rate law, assuming that the first step is rate determining.

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