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For each of the following pairs of elements, state whether the binary compound they form is likely to be ionic or covalent. Write the empirical formula and name of the compound: (a) I and \(\mathrm{Cl}\), (b) \(\mathrm{Mg}\) and \(\mathrm{F}\).

Short Answer

Expert verified
The binary compound formed by \(\mathrm{I}\) and \(\mathrm{Cl}\) is covalent, named Iodine monochloride, with empirical formula \(\mathrm{ICl}\). The binary compound formed by \(\mathrm{Mg}\) and \(\mathrm{F}\) is ionic, named Magnesium Fluoride, with empirical formula \(\mathrm{MgF}_2\).

Step by step solution

01

Determine the Bond Type

For each pair of elements, we need to know the bond type, i.e., either ionic or covalent. Ionic bonds typically occur between metals and nonmetals and involve the transfer of electrons. Covalent bonds, on the other hand, are formed between nonmetal elements and involve the sharing of electrons.
02

Ionic or covalent for \(\mathrm{I}\) and \(\mathrm{Cl}\)

Both iodine (\(\mathrm{I}\)) and chlorine (\(\mathrm{Cl}\)) are nonmetals, hence the bond between them is likely to be covalent.
03

Formula and name of \(\mathrm{I}\) and \(\mathrm{Cl}\) Compound

When covalently bonding, these elements each bring 7 electrons (they belong to group 17 in the periodic table), they share electrons to complete their octet. Thus, the empirical formula is \(\mathrm{ICl}\), and as the compound is covalent, it is named as Iodine monochloride.
04

Ionic or covalent for \(\mathrm{Mg}\) and \(\mathrm{F}\)

Magnesium (\(\mathrm{Mg}\)) is a metal and fluorine (\(\mathrm{F}\)) is a nonmetal. Therefore, these two elements will form an ionic bond.
05

Formula and name of \(\mathrm{Mg}\) and \(\mathrm{F}\) Compound

The magnesium atom loses 2 electrons to become \(\mathrm{Mg}^{2+}\) while each fluorine atom gains one electron to be \(\mathrm{F}^{-}\), therefore, two fluorine atoms are needed. This gives the empirical formula as \(\mathrm{MgF}_2\), and the name of this compound is Magnesium Fluoride.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic and Covalent Bonds
Understanding the strength and structure of the materials around us begins with a fundamental knowledge of ionic and covalent bonds, which are the main types of chemical bonding between atoms.

Ionic bonds, such as in table salt, occur when a metal donates one or more electrons to a nonmetal, resulting in positive and negative ions that attract each other. This transfer creates ions—atoms with a charge either positive (cation) or negative (anion). A classic example is the bond between sodium (Na) and chloride (Cl) to form sodium chloride (NaCl).

Covalent bonds, on the other hand, occur between nonmetals and involve the atoms sharing their electrons. The shared electrons allow each atom to achieve a stable electron configuration, often described as an 'octet', which is generally eight electrons in the outer shell. A well-known example of a molecule with covalent bonds is water (H2O); each hydrogen atom shares its single electron with oxygen to fill the oxygen's outer shell.

Identifying the type of bond can help to predict the properties of the compound. Ionic compounds tend to have higher melting and boiling points and conduct electricity when dissolved in water. Covalent compounds usually have lower melting and boiling points and do not conduct electricity.
Empirical Formula
The empirical formula of a compound gives the simplest whole-number ratio of atoms of each element in the compound. It is a critical concept in chemistry for understanding the composition of molecules.

To find the empirical formula, one must determine the smallest number of moles of the elements present in the compound and then express this ratio as the formula. For instance, in the compound benzene (C6H6), the empirical formula is CH since carbon and hydrogen are present in a 1:1 ratio despite having six of each type of atom.

The process of determining the empirical formula involves converting the mass of each element to moles, and then finding the simplest ratio. If you're given percentages, you would assume a certain amount of the compound—usually 100 grams—to make the math easier. The empirical formula is crucial in chemistry because it is used as the basis for naming compounds and can hint at their structures and properties.
Naming Chemical Compounds
The ability to name chemical compounds accurately is essential for clear communication in science. The names convey critical information about the elements present and the proportions in which they combine.

Ionic compounds are generally named by writing the name of the cation (positive ion) first, followed by the name of the anion (negative ion). For example, NaCl is named sodium chloride. When naming covalent compounds, prefixes are used to denote the number of atoms present (e.g., 'mono' for one, 'di' for two), with the first element named first followed by the second element with an '-ide' suffix. An example is CO2, which is called carbon dioxide.

In naming compounds, one must also pay attention to the oxidation state of the elements, which can affect the name. Transition metals, for instance, can have multiple positive charges and are indicated in the name by Roman numerals, such as iron(III) oxide for Fe2O3. Elemental names, oxidation states, and numeric prefixes are all critical to the robust system of chemical nomenclature that guides both students and professionals in chemistry.

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Most popular questions from this chapter

Nitroglycerin, one of the most commonly used explosives, has the structure The decomposition reaction is $$ \begin{array}{r} 4 \mathrm{C}_{3} \mathrm{H}_{5} \mathrm{~N}_{3} \mathrm{O}_{9}(l) \longrightarrow \\ 12 \mathrm{CO}_{2}(g)+10 \mathrm{H}_{2} \mathrm{O}(g)+6 \mathrm{~N}_{2}(g)+\mathrm{O}_{2}(g) \end{array} $$ The explosive action is the result of the heat released and the large increase in gaseous volume. (a) Calculate the \(\Delta H^{\circ}\) for the decomposition of one mole of nitroglycerin using both standard enthalpy of formation values and bond enthalpies. Assume that the two \(\mathrm{O}\) atoms in the \(\mathrm{NO}_{2}\) groups are attached to \(\mathrm{N}\) with one single bond and one double bond. (b) Calculate the combined volume of the gases at STP. (c) Assuming an initial explosion temperature of \(3000 \mathrm{~K}\), estimate the pressure exerted by the gases using the result from (b). (The standard enthalpy of formation of nitroglycerin is \(-371.1 \mathrm{~kJ} / \mathrm{mol} .\) )

Draw Lewis structures for the following organic molecules: (a) tetrafluoroethylene \(\left(\mathrm{C}_{2} \mathrm{~F}_{4}\right),\) (b) propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right),(\mathrm{c})\) butadiene \(\left(\mathrm{CH}_{2} \mathrm{CHCHCH}_{2}\right),\) (d) propyne \(\left(\mathrm{CH}_{3} \mathrm{CCH}\right),(\mathrm{e})\) benzoic acid \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\right) .\) (To draw \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH},\) replace a \(\mathrm{H}\) atom in benzene with a COOH group.)

Of the noble gases, only \(\mathrm{Kr}, \mathrm{Xe},\) and \(\mathrm{Rn}\) are known to form a few compounds with \(\mathrm{O}\) and/or \(\mathrm{F}\). Write Lewis structures for the following molecules: (a) \(\mathrm{XeF}_{2},\) (b) \(\mathrm{XeF}_{4}\), (c) \(\mathrm{XeF}_{6}\), (d) \(\mathrm{XeOF}_{4}\), (e) \(\mathrm{XeO}_{2} \mathrm{~F}_{2}\). In each case Xe is the central atom.

Write three resonance structures for hydrazoic acid, \(\mathrm{HN}_{3}\). The atomic arrangement is HNNN. Show formal charges.

Because fluorine has seven valence electrons \(\left(2 s^{2} 2 p^{5}\right),\) seven covalent bonds in principle could form around the atom. Such a compound might be \(\mathrm{FH}_{7}\) or \(\mathrm{FCl}_{7}\). These compounds have never been prepared. Why?

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