Chapter 8: Problem 36
Explain why, for isoelectronic ions, the anions are larger than the cations.
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Chapter 8: Problem 36
Explain why, for isoelectronic ions, the anions are larger than the cations.
These are the key concepts you need to understand to accurately answer the question.
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Name the ions with +3 charges that have the following electron configurations: (a) \([\mathrm{Ar}] 3 d^{3}\), (b) [Ar], (c) \([\mathrm{Kr}] 4 d^{6}\), (d) \([\mathrm{Xe}] 4 f^{14} 5 d^{6}\).
In halogen displacement reactions a halogen element can be generated by oxidizing its anions with a halogen element that lies above it in the periodic table. This means that there is no way to prepare elemental fluorine, because it is the first member of Group 7A. Indeed, for years the only way to prepare elemental fluorine was to oxidize \(\mathrm{F}\) ions by electrolytic means. Then, in \(1986,\) a chemist reported that by reacting potassium hexafluoromanganate(IV) \(\left(\mathrm{K}_{2} \mathrm{MnF}_{6}\right)\) with antimony pentafluoride \(\left(\mathrm{SbF}_{5}\right)\) at \(150^{\circ} \mathrm{C},\) he had generated elemental fluorine. Balance the following equation representing the reaction: $$ \mathrm{K}_{2} \mathrm{MnF}_{6}+\mathrm{SbF}_{5} \longrightarrow \mathrm{KSbF}_{6}+\mathrm{MnF}_{3}+\mathrm{F}_{2} $$
How do the chemical properties of oxides change from left to right across a period? From top to bottom within a particular group?
When magnesium metal is burned in air, it forms two products \(A\) and \(B\). A reacts with water to form a basic solution. B reacts with water to form a similar solution as that of A plus a gas with a pungent odor. Identify A and \(\mathrm{B}\) and write equations for the reactions. (Hint: See Chemistry in Action essay "Discovery of the Noble Gases" in Section \(8.6 .\) )
Arrange the following atoms in order of decreasing atomic radius: \(\mathrm{Na}, \mathrm{Al}, \mathrm{P}, \mathrm{Cl}, \mathrm{Mg} .\)
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