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Explain, in terms of their electron configurations, why \(\mathrm{Fe}^{2+}\) is more easily oxidized to \(\mathrm{Fe}^{3+}\) than \(\mathrm{Mn}^{2+}\) is to \(\mathrm{Mn}^{3+}\)

Short Answer

Expert verified
Fe2+ is more easily oxidized to Fe3+ than Mn2+ is to Mn3+ because Fe2+ can achieve a more stable half-filled d orbital configuration by losing one more electron while Mn2+, which already has a stable half-filled d orbital, would become less stable by losing an electron to become Mn3+.

Step by step solution

01

Understand Electron Configurations

Electron configurations describe the distribution of electrons in an atom's electron shells. They are determined by the Aufbau Principle which states that electrons always fill the lowest energy levels first, the Pauli Exclusion Principle which states that each orbital can hold a maximum of two electrons with opposite spins, and Hund's rule which states that electrons will occupy empty orbitals of equal energy before pairing up.
02

Identify the Electron Configurations of Fe2+, Fe3+, Mn2+ and Mn3+

The electron configuration for Fe2+ is [Ar] 3d6 and for Fe3+ it is [Ar] 3d5. For Mn2+, it is [Ar] 3d5 and for Mn3+ it is [Ar] 3d4.
03

Understand the Stability of Half-Filled and Fully Filled Orbitals

Half-filled and fully filled orbitals are particularly stable configurations. This stability comes from the symmetrical distribution of electrons and the maximum amount of unpaired electrons. In this context, Fe2+, which has four unpaired electrons, can lose one more electron to become Fe3+ with a half-filled (hence, stable) d orbitals while Mn2+ is already in a stable state with half-filled d orbitals so Mn3+ (which implies loss of electron from Mn2+) leads to a less stable configuration.
04

Compare the Ease of Oxidation

Since Fe2+ can become more stable by losing one more electron, it is more easily oxidized to Fe3+, compared to Mn2+ which is already in a stable state and would become less stable by losing an electron to become Mn3+.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configurations
When exploring the intricacies of chemistry, electron configurations provide a fundamental blueprint for understanding how atoms interact during chemical reactions. These configurations map out the electrons surrounding a nucleus and show us the order in which atoms fill their available energy levels, or orbitals. Think of it like organizing a bookshelf, where the books must be arranged in specific slots based on their sizes.

Some key points about electron configurations include:
  • They're designated by a combination of quantum numbers and letters representing the orbital types (s, p, d, f).
  • Configuration patterns follow a predictive order based on increasing energy.
  • They influence an atom's magnetic properties, ability to bond with other atoms, and reactivity in chemical processes such as oxidation-reduction reactions.
Additionally, knowing the electron configurations of ions like Fe^{2+} and Mn^{2+} is critical in predicting their chemical behavior.
Aufbau Principle
The Aufbau Principle is a guiding rule that dictates electron configurations. In simple terms, it's like the 'first come, first served' of electron arrangements, meaning electrons fill up the lowest energy orbitals available first before moving on to higher ones. This principle creates the foundation for an atom's structure.

Here’s why it is important:
  • It helps us predict electron placement for both neutral atoms and ions.
  • The energy of orbitals increases from 1s to 2s to 2p to 3s, and so on, following a specific sequence.
  • Understanding this concept is vital when you are determining why certain ions are more or less stable after losing an electron.
This principle is so reliable that it is used almost universally across all elements on the periodic table.
Pauli Exclusion Principle
Central to the framework of quantum mechanics, the Pauli Exclusion Principle provides the 'no double occupancy' rule for electrons in the same orbital. It states that two electrons can share the same orbital only if they have opposite spins, like dancers moving in perfect unison but in opposite directions.

Some points about the Pauli Exclusion Principle include:
  • It explains why electrons in the same orbital must have different spins, which is distinguished by spin quantum numbers: +1/2 or -1/2.
  • This principle ensures that each electron in an atom has a unique set of quantum numbers.
  • It's a key factor in determining the electron configurations of atoms and ions and, consequently, their chemical characteristics.
Without this principle, our predictions of chemical bonding and the structures of molecules would be less accurate.
Hund's Rule
Hund's Rule can be thought of as a 'spread out before pairing up' strategy adopted by electrons. It explains that electrons will fill degenerate, or equal energy, orbitals singly as far as possible before starting to pair up. This behavior is akin to passengers preferring to sit in separate empty rows in a bus before sharing seats.

Key aspects of Hund's rule include:
  • It reflects the electrons' natural repulsion from one another due to their negative charge.
  • By occupying separate orbitals, the electrons remain as unpaired as possible, leading to maximum total spin. This ultimately impacts an atom’s stability and reactivity.
  • Applying Hund's rule is crucial when predicting how atoms will interact, particularly in processes such as the formation of Fe^{3+} from Fe^{2+}, where orbital occupancy plays a role.
The rule highlights the fine balance between electron repulsion and the desire to achieve the lowest energy state.
Oxidation-Reduction Reactions
Diving into the collaborative world of electrons, oxidation-reduction reactions, or redox reactions, showcase the intimate dance of electron transfer between atoms. They are a type of chemical reaction where one substance loses electrons (oxidation) and another gains electrons (reduction).

Here's what makes redox reactions fascinating:
  • They're fundamental to processes like cellular respiration, photosynthesis, and even the rusting of iron.
  • Oxidation states denote the charge an atom would have if all bonds were ionic, helping chemists keep track of electrons during reactions.
  • An atom's propensity to lose or gain electrons is heavily influenced by its electron configuration and the relative stability that configuration provides.
For example, the transition from Fe^{2+} to Fe^{3+} is more favorable than Mn^{2+} to Mn^{3+}, chiefly due to the electron arrangements and stability associated with half-filled orbitals.

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Most popular questions from this chapter

The air in a manned spacecraft or submarine needs to be purified of exhaled carbon dioxide. Write equations for the reactions between carbon dioxide and (a) lithium oxide \(\left(\mathrm{Li}_{2} \mathrm{O}\right),\) (b) sodium peroxide \(\left(\mathrm{Na}_{2} \mathrm{O}_{2}\right),\) and \((\mathrm{c})\) potassium superoxide \(\left(\mathrm{KO}_{2}\right)\)

When carbon dioxide is bubbled through a clear calcium hydroxide solution, the solution appears milky. Write an equation for the reaction and explain how this reaction illustrates that \(\mathrm{CO}_{2}\) is an acidic oxide.

(a) Define electron affinity. (b) Electron affinity measurements are made with gaseous atoms. Why? (c) Ionization energy is always a positive quantity, whereas electron affinity may be either positive or negative. Explain.

The only confirmed compound of radon is radon difluoride, \(\operatorname{RnF}_{2}\). One reason that it is difficult to study the chemistry of radon is that all isotopes of radon are radioactive so it is dangerous to handle the substance. Can you suggest another reason why there are so few known radon compounds? (Hint: Radioactive decays are exothermic processes.)

An element X reacts with hydrogen gas at \(200^{\circ} \mathrm{C}\) to form compound Y. When \(Y\) is heated to a higher temperature, it decomposes to the element \(X\) and hydrogen gas in the ratio of \(559 \mathrm{~mL}\) of \(\mathrm{H}_{2}\) (measured at STP) for \(1.00 \mathrm{~g}\) of \(\mathrm{X}\) reacted. \(\mathrm{X}\) also combines with chlorine to form a compound \(Z,\) which contains 63.89 percent by mass of chlorine. Deduce the identity of \(X\).

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